This form field for a PayPal transaction will be produced during a user session. how to automatically submit it with "live" and $.post?
<?php
SCRIPT
print "<form id="paynowForm" action="https://www.paypal.com/cgi-bin/webscr" method="post">
[Code].....
I just started using jQuery, but i can't get it working. On the index.php page I want a search form, that post's to search.php. Following next, I want that the html of search.php (which will only be a table with the results), is show into the 'results' div in the index.php.
This is the code im using:
<script type="text/javascript">
/* attach a submit handler to the form */
$(document).ready(function(){
alert("Ok - 1");
[Code].....
The alert's are for debugging, but none of them show's up.
[Code]....
how do i cause the form to post to another page? Am I doing it correct? I want this to happen ONLY if validation passes.
I want to run an external function outside the post.
This is what I have currently.
On success of the post I want to run the setGrandTotal(); function which will do some calculating for me.
i need to post data from a form to a page on another domain, without leaving the current page.I am using ASP as a server language.
View 9 Replies View RelatedHow can I post array of controls through &.post() in jQuery??I have some of checkboxs in my page and declare them like this
<input name="mycheckbox[]" "value="myvalue" type="checkbox">
I can get it works if I using <form> tag with an action="post" and a submit button to post to another php page by using this statement to get all controls in receiver's page _GET['mycheckbox'];I have tried
$.post('ajax/test.php", {checkbox: $
(
'input[name="mycheckbox"]'
)});
[code]....
I'm trying to use an Ajax system to make a double post method submitting.The fact is I want to send the data of the form to a page called Mailing.php (no need to have a response of this page) and in the same time, I want to send the data to another page (external of my website).[code]
View 1 Replies View RelatedI am trying to use JQuery to submit a form without reloading the page. Although this works well with thejQuery Form Plugin on a standalone page I need it to work on a page I've loaded with AJAX.[code]...
View 2 Replies View Relatedim trying to post each input element in my form. The elements are generated with a click function. So if there are 2 elements i want to post the values of both to a php script. This is what ive tried so far but it doesnt appear to work.
[Code]...
How can I gather all values from the form (select, input (text, checkbox....), textarea... ) using jquery and send them by post. The number of items is not fixed, I need something that will gather everything that form contains.
View 3 Replies View Relateddoing this ajax post request i get an error:
[Code]...
doing the same through the html form-element works, what could the problem be?
my error function returns 0 for the xhr.status, error for the textStatus and undefined for the errorThrown.EDIT: i just tried the http_post_field function of the php pecl library. this works aswell. could it be that my data string is not correct?
How to send one input data using ajax, I then needed to send a form with multiple inputs. I believe I can't do this with AJAX so have tried to implement it using JQuery.
The problems I am having is that my page is refreshing when I click on submit and the data is not being sent.
I am more than happy to look at other ways to do this if JQuery is not the answer. All I want is a page that doesn't refresh or redirect but does submit a form.
My form is:
$("input").blur(function(){
$.post("/designyourown/scripts/post.php", { id: $(this).attr('id'), value: $(this).attr('value') } );
$('img#preview').attr('src','preview.php' + '?' + Math.random());
});
the above code works how it is supposed to with elements hard coded into the page but if i add more elements with this code
[Code]...
1). Once my form posts, all the information stays in the post. How do I get it to blank. Is this where I set cache to false or is that something else?
2). I am using classic ASP and once I do my insert to sql server I retrieve the new record's ID, how do I get that returned back as part of the post?
Some background: I am trying to submit a form, pull the id, and then requery all records for a user and display them in a div below the blank form without recycling the page.
I've tried every combination of the following toovercome the "invalid parameter" error, but failed hitherto.
The url, listName and choiceText are all defined and have content. I've stepped through the jquery functions that support these calls and have not been able to identify the invalid argument, or by process of elimination.
[Code]...
I have a web form (yeah) that I would like to have jquery direct the post and the form values to one of two php pages depending on the choice selected.
Ideal flow:
If a person selects radio button "email" and clicks submitsend form values to page1
-Generate and send email and report success
-User never actually sees page1
If a person selects radio button"view" and clicks submit send form values to page2.
-Displaypage2
$(document).ready(function(){$("#listrequest_form").submit(function() {
This is my first post, and I'm only just learning jqury/JavaScript.
i have a form I'd like to send via POST method to a second php page, i have all the validation etc working fine, I'm struggling with the on Submit handler.. once the form is validated...
can anyone please tell/direct me how i can post this form to a php page that will do the data insertion?[code]...
The server i'm trying to post data to in an ajax call expects data in xml format, including a particular attribute value. I have to use Chrome browser which does not support the XML Class (e4x).
I tried to marshal my data as follows:
But the ajax call does not appear to transfer the xml data to the server even though the xmlhttprequest call appears ok in Chrome's developer tool console.
I'm wondering whether I'm forming the xml formatted data correctly.
I have created an entry form that I display in a modal dialog. I have two buttons on the form: "Add and close", and "Add and allow me to add another". However the only time my modal form will post back to the server is after the form has been closed. I want to do the following: The user opens the form in a modal dialog. The user enters data, and clicks the "Add and allow me to add another" button. The page sends the user input to the server, which adds the input to a database and updates a datagrid on the page. This updated datagrid is visible behind the modal form, so the user can see it happening in the background The form clears all input fields and the user goes again. Any code I write that calls the server (button click events, ajax calls, etc) are ignored, unless the modal form has been closed.
View 1 Replies View RelatedHere is a script and its uses a latest jquery
$(function(){
$(".submit").click(function(){
varname=$("#name").val();
varsurname=$("#surname").val();
[Code].....
Its sends only a M value ..The different IDs gives a undefined there is a problem with radio button DOM - Jquery
I try to create form to subscript a newsletter using plugins and the $.post() function ,but the URL outside the server[URL] to send me an email if it receives the data but it doesn't work,
here is the code <html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
[code]....
My programme is to let people play roulette wheel, record their choice of bet, amount of bet, result of bet, number of bets, bet limit. I would like these data being posted to myqsl each time the person bet, without the disruption of page refreshing. I have code as below, but it does not work. There is no error msg, just no data could be inserted.
>>>>>>result.html
input name= "spin" id="spin" type="button" value="spin"onclick="spin();postRecord()">
....
function postRecord() { $.ajax({ type:
[Code]....
I would like to submit a form depending on the success data of an ajax post.
Below is my jquery code; as you see #theform is the main form and before submitting the form I need to check the availability of the the date and time and the room using$.ajax. However it doesn't submit the main form if the date, time and the room is available.
required=["txtCal_Event_CalendarID","txt_TreatmentRoom","txtTreatmentID","txtTreatmentTypeID","datepicker1","datepicker2","timepicker1","timepicker2"];
emptyerror="Please fill out this field.";
[Code].....
I have a form in a webpage that I want to submit
and get the result back without reloading the page.
I've seen many times ppl using text/x-www-form-urlencode but I was
wondering if it was possible somehow to submit the form element
directly so I wouldn't have to process the form to put it in a string.
So I load a form through a XMLHttpRequest and set the content of a div to the returned data, which contains a form, problem is I can't submit this form when it is requested through Javascript, but I can submit it when it is standalone.
I am thinking that this is probably a security setting in the browser to prevent XXS attacks? But I am not sure, why doesn't it work? It is nothing fancy just a regular old HTML POST form and a Javascript AJAXey request.
I am trying to validate a form field using a $.post request and am having an issue with timing because of the synchronous property of the post I assume. If I put in an alert, it works fine because the post has returned in time to stop the form submission. Here is the original way I did it but the form is submitting before I can send the return = false.
Code JavaScript:
$('form#form-oidupdate').submit(function(e) {
var srchstr = $('form#form-oidupdate input').val();
var passdata = {'type': 'availability', 'srchstr': srchstr};
[Code]....