I am trying to use JQuery to submit a form without reloading the page. Although this works well with thejQuery Form Plugin on a standalone page I need it to work on a page I've loaded with AJAX.[code]...
View 2 RepliesHow to get post data from a page loaded in iframe in parent page
View 1 Replies View Relatedi need to post data from a form to a page on another domain, without leaving the current page.I am using ASP as a server language.
View 9 Replies View Related[Code]....
how do i cause the form to post to another page? Am I doing it correct? I want this to happen ONLY if validation passes.
This is my first post, and I'm only just learning jqury/JavaScript.
i have a form I'd like to send via POST method to a second php page, i have all the validation etc working fine, I'm struggling with the on Submit handler.. once the form is validated...
can anyone please tell/direct me how i can post this form to a php page that will do the data insertion?[code]...
My programme is to let people play roulette wheel, record their choice of bet, amount of bet, result of bet, number of bets, bet limit. I would like these data being posted to myqsl each time the person bet, without the disruption of page refreshing. I have code as below, but it does not work. There is no error msg, just no data could be inserted.
>>>>>>result.html
input name= "spin" id="spin" type="button" value="spin"onclick="spin();postRecord()">
....
function postRecord() { $.ajax({ type:
[Code]....
I have a device with embedded webserver. Its page offers to reset the device,with the following javascript function:
function Restart()
{
if (confirm("Your Web browser will lose contact with the
camera.
Are you sure you want to restart the camera?"))
{
var form = document.WizardForm
form.do_reboot.value = "yes"
form.submit()
}
}
Now I want to execute the reset function automatically on a timeschedule (every 24 hours, from crontab). How do I accomplish this? I guess I need something like the reverse of WGET - something like a WPUT or WSUBMIT, that talks to the embedded web server and submits a form with
do_reboot = "yes". However, I have never heard of any such tool.
How can I trigger the functionality in an automated way, without browsing the page and clicking the button manually?
I have a form that I submit to an asp page. The asp page contains an iframe that needs to receive the form results too. How can I submit the form to both the asp page and the iframe at the same time?
View 1 Replies View RelatedI'm using an intermediate page to break up some data and assign it new names. What I then want to do is pass them onto to the next page. However, I don't want to use any method which involves sending them in a query string. So, in short, I want to automatically POST (ie no user intervention) the data.
View 4 Replies View RelatedI have a form with three fields. When the user changes the value of field1, the form displays either field2 or field3. This works fine for NEW records.However, I'm running into a problem when trying to EDIT an existing record. When the form is loaded, I need to test the value of field1 and display either field2 or field3. I've tried using the form onload event, but do not know how to access the value of field1.I'm using Javascript and div tags.This is what I have so far.
<script type="text/javascript">
function hide(obj)
obj1 = document.getElementById(obj);
[code]....
i have this script I found that i think does what i am looking for but i cant seem to get it to work.I think I am just overlooking something. I have a group of radio buttons in a form on a page and i am trying to get the value and image attached to the chosen radio button to pass to another form on another page.here is what i have so far.
form 1 page named - giftcards.html
<form action="GIFTCERTIFICATES.html" name="giftcardstyle">
<input name="giftcardstocknumber" type="radio" value="BBA - 006"/>
<img src="GIFTCARDS/004 BASIC4.jpg" alt="bba-006" style="width: 150px; height: 100px">
[Code]....
I just started using jQuery, but i can't get it working. On the index.php page I want a search form, that post's to search.php. Following next, I want that the html of search.php (which will only be a table with the results), is show into the 'results' div in the index.php.
This is the code im using:
<script type="text/javascript">
/* attach a submit handler to the form */
$(document).ready(function(){
alert("Ok - 1");
[Code].....
The alert's are for debugging, but none of them show's up.
I am writing a small data entry screen that will post the form data to a page and return a message. But i cannot get the Success or Error functions working properly.
Here's the code where strData is the posted querystring of:
I'm not sure whether it should be in a form and using the onsubmit or click of a button.
I am working on a page that will load in other pages using AJAX and the .html method. Something like this :
<span id = "edit">Edit</span>
<div id = "cont">
</div>
//the click edit script
[Code]....
Unfortunately this does not seem to work, entirely. It does trigger the click event but it messes up the post for some reason. I have played around with it for the last 45 minutes or so and it seems like the click event trigger is what is messing things up, if I comment it out it works fine. Could anyone tell me why they think this is? note this is an over simplified version of my actual code, but the structure is the same.
I have the following bit of jQuery:
Code:
$("#save_photos_all_continue").click(function() {
event.preventDefault();
var $black_white_all = $("#black_white_all").is(':checked');
var $color_all = $("#color_all").is(':checked');
var $other_all = $("#other_all").is(':checked');
[Code]...
In Google Chrome it works fine but in Mozilla/5.0 it actually goes to the save_edits page instead of just using the post and staying on the original page.
I'm trying to load a page using the .load(url) from an already loaded page, but nothing responds. Below is a simple sample page created to show what I want to accomplish. Also, I'm using JQuery 1.3.
index.html
When the index.html page loads up, the page01.html loads into #mainview. And when I try to click on the <div id="clickme">Click Me!</div> inside page01.html to load page02.html, nothing works. Just can't figure out what's wrong...
Can jquery animate the way a web page is loaded? for example you may fade in a page or add some effect to it when its loaded. is this possible?
View 1 Replies View Relatedhow to control loaded page
$("div [id='menuTopLink'][class='menuTopLink4']").click(function () {
$("div [id='mainViewIn'][class='mainViewIn1']").slideUp("slow",function(){
$("div [id='mainViewOut'][class='mainViewOut1']").slideUp("slow");
[code]....
I have loaded the form in div tag using load() like below.$("#empdiv").load("http://empdata.employee.net/empinfo.html"); Now, I want to access the input fields in the empinfo.html.
View 1 Replies View RelatedI'm creating an inventory management back-end for an intranet application.
The user has to indicate whether the item is "Non-Inventory" or "Inventory".
Each item type has it's own set of fields so this distinction loads the proper data entry form via:
The form loaded via inventory_form.html is:
how to post dat from curent page to another php page using jquery
View 2 Replies View RelatedHere is the issue I am having: In my project, I have a index.php page with a sidebar menu and a div id called œcontent.The user can select different menu items and perform searches from the database and make updates to their account. Im using ajax to load all of the menu items and all of the forms into the div id "content" on the index page. The Forms all load into the target div as they are suppose to with ajax.
However, on the mysettings page I have two forms and two different buttons, one called save and the other called update. When a user wants to edit their account information and makes changes to their account they clicks on either button and the form processes the information and updates or inserts data into the database correctly but the problem is that after that the form or page does not display the form back in the div id "content" like how it was loaded originally in the index.php page. The problem is that it reloads or refreshes the form page without the index.php page being involved. That is does not get reloaded or updated inside the index.php page content div again.
What I would like do is have all of my forms process whatever is submitted on the page and display the results back inside the same content div on the index.php page again. I know I am missing something because all of my forms are doing the same thing. I am hoping someone can help me out. I would be very grateful for example code that I can learn from since I am still relatively new to web development. I am posting some sample code below.
[Code]...
I'm trying to .show() a div that contains a ...loading... gif before the page is fully loaded. On .ready Im going to hide it code...
View 2 Replies View Relatedi have the following code
<script type="text/javaScript">
$(document).ready(function(){
$("#dropPrd").change(function() {
$('#imgAjaxLoading').ajaxStart(function(){
[Code].....
and i want to access the element dropSubPrd that is inserted on that ajax function, on the div FirstResult, but it will not work in $('document').ready because when the page load's that element isnt there.
For example I have a page: [URL] On this page I use $.ajax:
$.ajax({
type: "GET",
data: "data=123456",
dataType: 'html',
[Code].....
where temp.php - [URL] On temp.php I use requests for DB with param from $.ajax - data=123456. How I can protect page temp.php? For example, somebody typing [URL] and then he can get all results. I found one solution - using if($_SERVER['HTTP_REFERER'] == "http:// mysite.com/content/") {....} But Am not shure that it can realy protect my page?
I am trying use the Load function and it looks partly succesful:the script code is:
function doCallBack(action, value)
{
if (action == 'projlokatiemutaties')
[code]....
Projectlokaties1 contains an XML control and the content is being transformed using Xslt. As far as I can see the html variable contains
the correct value. However the Response.Write() operations fails completely. As a matter of fact at this point any Response operation fails.