I would like to delay my jquery .post() call for 5 seconds like: jQuery.delay(5000).post( ajaxurl, data, function(response){ alert(response); } ); but it is not working. the error msg tells that the object do not support that method jQuery().delay(5000) or jQuery('body').delay(5000) is too not working.
View 8 Replies
I am putting together a simple bubble tooltip that I want to delay the hiding of so that the user can click on the href link created in the bubble if they want to. The script is called like this;
<img src="images/dscf0225.jpg" alt="" width="160" height="120" style="border: none" onmouseout="$('#bubble_tooltip').delay(2000).hide(10);" onmouseover="showme('Click the image to visit <a href=www.yahoo.com>Yahoo</a>', this);"/>
Everything works fine when there is only one instance of the call on a page. If there are multiple instances of the call, there is a bad reaction to each subsequent call. Here is a demo of what I mean, rollover the first image then just roll-out, the delay works as designed. But if you roll-out of one image into another, the delay fires the first onMouseOut on the second image. [URL] Do I need a Return True or something in my call?
How do I pass a variable as a key in a key/value pair in Ajax?
[Code]...
The server i'm trying to post data to in an ajax call expects data in xml format, including a particular attribute value. I have to use Chrome browser which does not support the XML Class (e4x).
I tried to marshal my data as follows:
But the ajax call does not appear to transfer the xml data to the server even though the xmlhttprequest call appears ok in Chrome's developer tool console.
I'm wondering whether I'm forming the xml formatted data correctly.
I am trying to use a $.post call in jQuery to check a user's credentials before submitting a form (so I can show errors without reloading the page), but I've run into a problem. I know why it is, because AJAX is not synchronous, but I just can't figure out how to do it.
In my code the script I'm making the call to returns "valid" or "invalid". If the return is "valid", I want to submit the form, if not, show an error message. Here is a simplified version:
$("#my_form").submit( function () {
some_value = "username"
$.post(script_location, {data : some_value}, function (data) {
response = data
[Code]...
This obviously does not work because code is executed quickly one after another and the variable "response" is not yet set when the execution gets to the if statement, since it is set sometime later, asynchronously.
I looked into using functions, callbacks, but nothing seems to work properly, I always run into the same issue. This is probably really simple, i just a complete dunce, please do let me know what is the standard way of doing this properly.
Im trying to make a script, which will call .php by $.post as many times as divs i have in my document.
Script looks like this
The problem is, that if I have two of these divs, the php script will run 4 times...i there are 3 of them, script runs 9 times. it is very important to run it as many times as number of divs.
$("#ucet").append(echo); is for testing how many times php script will run...its always wrong.
I have the following code:
$(function() {
$("#check_login").click(function() {
event.preventDefault();
[code]....
I'm basically checking a user login. If the login is successful I'd like to close the Fancybox. This part works fine. I'm using an iFrame from Fancybox. If I don't have this part:
parent.$.fancybox.close();
It will reload the index page in my iFrame. How can I refresh my other page from the iFrame?
i retrieved data from mysql table into html page i.e
Code:
$query="select * from student";
$result=mysql_query($query)or die(mysql_error());
while($rs=mysql_fetch_array($result))
{
?>
[Code]...
assume that checkbox of id 1 is checked and retrieved from mysql table.<br /> Now what i want to do is that when i checked the remaing two checkbox into this table and a function is called to ajax which goes to php page and update the value of checked field according to the given id (i.e 2 and 3 in this case). Not refreshing the whole page nor updating the whole record just the value of check box.<br/> i am new to ajax so
I want to run an external function outside the post.
This is what I have currently.
On success of the post I want to run the setGrandTotal(); function which will do some calculating for me.
How can I post array of controls through &.post() in jQuery??I have some of checkboxs in my page and declare them like this
<input name="mycheckbox[]" "value="myvalue" type="checkbox">
I can get it works if I using <form> tag with an action="post" and a submit button to post to another php page by using this statement to get all controls in receiver's page _GET['mycheckbox'];I have tried
$.post('ajax/test.php", {checkbox: $
(
'input[name="mycheckbox"]'
)});
[code]....
I just started using jQuery, but i can't get it working. On the index.php page I want a search form, that post's to search.php. Following next, I want that the html of search.php (which will only be a table with the results), is show into the 'results' div in the index.php.
This is the code im using:
<script type="text/javascript">
/* attach a submit handler to the form */
$(document).ready(function(){
alert("Ok - 1");
[Code].....
The alert's are for debugging, but none of them show's up.
I need to make a $.post call on the beforeSend event of another $.ajax call.I read the documentation and I see that if the beforeSend return false the ajax call will be interrupt.So I made this code but doesn't work, because the real value of the beforesend function isn't true or false, is the value of the post.I have to do this because when you click on a link I need to verify before if you are able to do this via db permission of my webapp.I think you don't understand...This is the code:
$.ajax({
async: true,
beforeSend: function(){[code]....
});I see always the alert of success event, so the return of the beforesend is not correctly done.
[Code]....
how do i cause the form to post to another page? Am I doing it correct? I want this to happen ONLY if validation passes.
I have a function which shows the caption of an image in a span tag part of an image slider. The idea is that when the function is called I change the image (this is fine), hide the span containing the alt tag info, change the text to the next image's alt tag and show it again.
The whole thing works fine exept for one thing, I have added a delay before I change the text content of the span tag but it does not seem to take the delay, the text is changed immediately as teh function is called:
$('#caption_content').slideUp(500).delay(1000).html('<p>'+caption+'</p>').slideDown(500);
Am I using delya correctly there or may be it does not work with .html()?
I have three <div> with text. On clicking on a menu <div>, the associated text <div> will slideDown(). When I click the next one, I have the last one hide() and the next slideDown(), but I would rather have the last one fadeOut() before the next one slideDown().
But the next <div> 'pushes' the last one down as it fades.
Here's what I've got now. The only one I've tried to get to work the way I want is the <div class="work_button"> And no giggling at my elementary code:
$(function(){
$(".panel").hide();
$(".work_button").click(function(){
$("#cms, #contact").fadeOut();
[Code]....
is there any specific function in Javascript / jquery which delay the functionality
I use SLEEP() funciton in php to add delays .
How can I have a delay between drawing one element and another?
View 3 Replies View RelatedI have a page that is a displaying a Movie, or it's really 3 Movies but to get to the 2nd Movie the user has to click a "Next" button. My problem is that I want to delay this button to appear until the movie is more or less done... could be 7 or 16 minutes. What would be the easiest and most propriate way to do this using jQuery... swaping out one DIV for another once after X minutes?
View 4 Replies View RelatedI'm using the great cloud zoom jquery plugin to add inside zoom to an image in my site, but I want to add a delay on the hover before the zoom takes place.
I created a jsfiddle so you can see the code in action [url]
Hover over the image and the effect takes place immediately. I'm not sure how to make it wait say .5 seconds before it happens.
So far there is no jquery involved from me, I just put the image inside a <a class='cloud-zoom' href='address of big image'><img src='address of small image'></a> to make it work.
I've got a very simple animation happening that when I try to wrap in a delay method that I found here, the last process does not work (animation opacity 1). Any ideas, pointers?
$.fn.delay = function(time, callback){
// Empty function:
jQuery.fx.step.delay = function(){};
// Return meaningless animation, (will be added to queue)
return this.animate({delay:1}, time, callback);
}$('#map').delay(500, function(){
$('#mapper').attr('style', 'background: url(' + this.src + ');');
$(this).stop().animate({opacity: 0}, 0);
$(this).attr('src', '/public/images/team/map0.jpg');
$(this).stop().animate({opacity: 1}, 600);
});
i have the following two pieces of code:
function slideOut() {
var $slidy = $('#slideout');
$slidy.animate({
right: parseInt($slidy.css('right'),10) == 0 ?
-$slidy.outerWidth() :
[Code]...
As long as i return false and the link is an anchor, i can see the menu slide out. Which is quite clear to me why. When i use a link with a href on another page though, the "jump" is executed before the animation ends most of the time even before it starts.
I would like the click to be delayed weather a certain condition kicks in, or some time passed to end the slide and then jump to the new page. I have been looking throughout the web and found no hint helping me to tackle this. delay() and setTimeout() dont seem to work the way i used them.
I am sure there is a way, its just the blind man's stick in my eye that keeps me from it. I hope someone can help me with this.
I'm having a problem with following code:
$(function() {
$('#footer a')
.bind('click',function(event) {
var text = $(this).attr('href').replace("#","");
[Code].....
However the .delay() isn't working for me. Is it because of the animation and its duration ?
I want to #name to wait 1 second on the mouseover before appearing, how can I do this?
<script>
$("#block").mouseover(function () {
$("#name").show();
});
$("#block").mouseleave(function() {
$("#name").hide();
});
</script>
Does someone have an working example of the following: Select records from a database, display the first 10, and after 30 seconds, display the next 10 without refreshing the page.Then, when no more records, start over.
View 1 Replies View RelatedI have a div container containing an image that shall disappear by an on-click event. But if the user won't do the click after 3 seconds, the image shall disapper by itself - using delay(). How can I combine these actions? I wasn't able to solve the problem with the bind()-functionality, but probably I misunderstood that?
View 1 Replies View RelatedI want to try and keep my syntax all encapsulted, but I'm not sure how to go about this.
So I add in some html to a div
$('#slideStage').append("<div id='popupTiming' style='display:none'>" + formatTime(currentCuePoint.time) + ' minutes</div>')
So the resulting html would be
[Code]...
