I think right now jQuery slideDown() will show the content bit by bit (line by line) of that DIV, showing top content first, and then little by little, the content below it...
Is there a way to actually slide the *content* down as well? In order words, showing the bottom of the DIV, and then it will move down, a little by little, and then show more of the content above it.
I'll slideUp a div, load some ajax, then slideDown the result.In the result, there are two more divs (navigation and 'subcontent' containers)I have links in the navigation div that should fadeIn new content (via ajax) into the subcontent container.Now, the fadeIn fadeOut functions operate correctly _until_ I use a slide on the larger div. If I slide at all, everything turns into a slide, even within the subcontainers. I'm not sure what's going on.ere's an example structure for the divs:
<div id="globalnav">Anchors/Links for the maincontent div</div>
<div id="maincontent">"maincontent" should slide open and closed.
<div id="nav">Anchors/Links in here</div>
[code]....
I have a container div with two inner divs. I have one inner div visible taking up 100% of the visible area and another hidden div. I
want the visible div to slide to the left while simultaneously sliding the other div in from the right. This works fine except that while the right div is sliding in, it appears below the left div. How can this be done?
Here is the code:
<script type="text/javascript" src="js/jQuery/jquery.js"></script>
<script type="text/javascript" src="js/jQuery/effects.core.js"></
script>
[code]....
I'm working on a page, where I want to use jQuery to build a "Portfolio" div that contains pics and info about some of my work. I found a bunch of cool tutorials about making a slide show, but they all have a sliding animation. With my page, the sliding animation would look awkward. I'm fine if it just replaces the current div with the next one. I'm just planning on using a previous and next button (Within the same div) to cycle through these.
View 4 Replies View RelatedI am trying to create a menu that would look and act like this image illustrates: [URL] Essentially the three boxes slide down when rolled over and menu items appear in the portion that has slid down.So far, I have figured out how to make an image slide using jQuery: [URL]
View 2 Replies View RelatedTrying to learn the basics... Here is a script for three toggle buttons that each when clicked open their corresponding divs. Fine. Now how does one go about automatically closing an open div when clicking on a new 'toggler' that opens it's div? I see other posts about this very question, but I'm just not grasping the logic.
jQuery(document).ready(function($) {
$("#toggle1").click(function () {
$("#toggle1div").toggle("drop", {direction:"right"}, 500);
});
$("#toggle2").click(function () {
I have a script that will slide a div up from the bottom of the page. The toggle button for this div however is going to be right on top of the sliding div. But, when the button is pressed and the div starts to slide down, the script hides the button. Here's an example... [URL] How can I get the toggle button to slide with it, but not disappear?
View 7 Replies View RelatedI have some div's as blocks hidden wich should show on a button click, and if there is some other block visible, I have to slide it Up and then slideDown the clicked one...like this
The problem is that I'm doing this with the callback function, but it start sliding down when the other block is not completly up...
I want to create a simple portfolio site using the following tutorial: [URL]. However, instead of the small panel I want the whole page to slide, example: [URL] how can this be achieved?! I don't really have a clue about javascript.
View 1 Replies View RelatedI thought this would be easy but I'm stuck and I can't describe what's really simple so I've drawn a diagram. [URL]. I have a div containing an image like 1 in the diagram. I only want to show the top of the image like 2 in the diagram. When I hover over the div I want the image to scroll up to show the bottom of the image like 3 in the diagram. [URL].
Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"[URL]">
<html xmlns="[URL]" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>untitled</title>
<style type="text/css" media="screen">
*{
margin:0;
padding:0;
}
#wrap{
margin:50px;
width:700px;
}
ul{
list-style:none;
}
</style>
</head>
<body>
<div id="wrap">
<ul>
<li><a href="#" id="one"><img src="img.gif" width="250" height="200"/></a></li>
</ul>
</div>
<script src="[URL]"type="text/javascript"></script>
<script>
$('li').hover(function(){
$(this).find('img').animate({top: + (-200) + 'px'},200);
})
return false;
</script>
</body>
</html>
I'm using three elements and jQuery to create a scrollable information element with a sliding animation (similar to this. I'm running into issues when resetting those three elements to prepare for the next prev/next animation, however. The issue is in my logic - jQuery's selectors will reverse themselves using the code I have.
Javascript Code:
Original - javascript Code
$('#name.current').removeClass('current').addClass('prev');
$('#name.next').removeClass('next').addClass('current');
$('#name.prev').removeClass('prev').addClass('next');
$('#name.current').removeClass('current').addClass('prev');$('#name.next').removeClass('next').addClass('current');$('#name.prev').removeClass('prev').addClass('next');
As you can see, the last step will always reverse the first step These elements do need to be reset in one way or another so that the information can be loaded appropriately (from an XML file). and then animated again.
If slideToggle()'s parameters were expanded to include a separate callback for sliding up and sliding down. Or for backwards compatibility, perhaps include an optional boolean parameter in the callback to more easily discern between a slideUp and slideDown operation.
View 1 Replies View RelatedI have a div containing an image like 1 in the diagram I only want to show the top of the image like 2 in the diagram When I hover over the div I want the image to scroll up to show the bottom of the image like 3 in the diagram It seems really simple but I'm completely stuck
[Code]....
I have a quick question for all you skilled developers -- I'm new to the forum, intermediate with JS/jQ.
How simple would it be to implement a subtle and quick slide-in of the page content using jQuery (only that once for the home page onload).
For a reference check out this site example. I wanted to do something nice like this WITHOUT FLASH =)
I have hidden div, that i want to show by sliding it in from topborder.The problem is that i don't know how to make it "slide in" instead of"wipe in".I want it all to move with it's content instead of showing more andmore of it.
View 1 Replies View Relatedcatch an element and add another element in run-time using jQuery. The HTML looks like this -
<td class="fieldCell"><input class="inputbox" id="password" type="password"><span class="cbFieldIcons">lots of HTML codes</span>....
</td>
I want to add some more element in .... place. That is, just after the <span class="cbFieldIcons"> ends. note that there is actually no .... in actual code.
I personally wrote a code using jQuery, but some reason, it is not working in IE6 and IE7.
Im looking for something that would allow a user to click on a button / link that would then reveal hidden content by sliding the whole of the main site content / container down.
I found this which slides the page content to the left or right [URL]
But need something vertical, almost as if the whole site was a big vertical accordian.
Or like on twitter / facebook phone app when refreshing for new tweets etc.
I have the following HTML...
<div id="files">
<ul id="filelist">
<li>
<a href="/image/b/" title="Uploaded on 02-09-2009 at 5:53 PM BST">delle4200_1.png<span class="size">34.6 KB</span></a>
[Code]...
When the user hovers their mouse over the <a> inside the list item I need the <span class="size"> to sort of slide to the left a bit and another span to be inserted where the current one is (fade in)... This new span will have links like "Share", "Bookmark", etc inside of it.
I'm using Lightbox picture displayer [URL].. and a content slide show UI [URL].. on the same pagesimultaneously. Although when I connect to the javascript files in my html page one of the effects won't work. Whichever javascript file I include last doesn't seem to work.
In the scenario below my content slide show effects won't work because they are listed first. It seems that whatever is listed last overrides everything else. I've also listed the error I get when running the page.
[Code]...
i am trying to slide multiple elements in my page at the same time.I wrote a script that can do one element at a time:
var count;
var obj;
function slide(elem,endy,endx,time){}
[code]....
is their anyway to modify this code so it does not use global variables and can run multiple instances simulatnuasly.
I have a vertical navigation menu with the basics (a <ul> with four <li>) but I need one of these list elements to slide to the left and when it finishes show or slide down a nested <ul> with its own li that is now hidden with display: none. and when I click again the first list element I wish everything to close back. or alternatively to close with a timeout. so far I got to this:
$(document).ready(function(){
$("#gioca").click(function(){
$("#gioca").animate({ left: "+=400" }, 1200)
[code].....
I'm having a little trouble with 2 differentJS scripts. I have a drop down slide menu and a parralex slide gallery. Both work on separate pages and puton the same page they still work however the submenu of the slide down menu does not. if I remove the style sheet that belongs to the gallery
Then the munu works, however (obviously) the page layout goes wrong. if i remove<h1 class="title">Alex Holland Perspective</h1> the menu works however page layout goes wrong andI loose my header
Here is the code.
is there any feature to slide the images in accordion form left to right and right to left with minimum time frame(delay)?
View 1 Replies View RelatedI'm look to create a kind on instruction manual where the user can slide through pages. Rather than using an image slider, which scroll's through the images (or content), I want to stack the pages on top of each other.1. Click NEXT and Page 1 slides into view.2. Click NEXT again, and Page 2 slides out on top of Page 13. Click PREV and page 2 slides back, out of viewI started a fiddle here, showing the slide of page 1. But I'll need a way to count the pages, and for the NEXT and PREV links to know which pages to slide.
View 3 Replies View RelatedI am having some real trouble figuring out how I can hide and show divs one at a time, a bit like an accordian. Currently, I have several buttons, which open and close a div containing a ul menu. What I am trying to achieve is to only have one div showing at a time.
So for instance, when the page loads no divs are displayed, just the buttons. You click a button a div slides out. you click another button this div closes and another opens. I am new to jQuery, but working hard to understand and learn. So far I have the below for each button (div).
[Code]...
Bascially I have a main page with all the code setup to slide whatever content is in the div 'sub_content'. As below: [URL] Contained in the my "external pages" are different slide contents that I want inputting into the 'sub_content' div as below: [URL] If you click 'Test Link 2' you will see it fade out but it's then loading in the main page again? I think it is this line of code found in submenu.js where the problem lies? var myXHR = new Ajax( objLink.href + '&blnAjax=1', { method: 'get', evalScripts: true, autoCancel: true, onSuccess: showSubPage } ).request();
View 13 Replies View Related
