Slide And Stack Sequential Content?
Oct 4, 2011
I'm look to create a kind on instruction manual where the user can slide through pages. Rather than using an image slider, which scroll's through the images (or content), I want to stack the pages on top of each other.1. Click NEXT and Page 1 slides into view.2. Click NEXT again, and Page 2 slides out on top of Page 13. Click PREV and page 2 slides back, out of viewI started a fiddle here, showing the slide of page 1. But I'll need a way to count the pages, and for the NEXT and PREV links to know which pages to slide.
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Mar 22, 2010
I have a quick question for all you skilled developers -- I'm new to the forum, intermediate with JS/jQ.
How simple would it be to implement a subtle and quick slide-in of the page content using jQuery (only that once for the home page onload).
For a reference check out this site example. I wanted to do something nice like this WITHOUT FLASH =)
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Mar 4, 2010
Bascially I have a main page with all the code setup to slide whatever content is in the div 'sub_content'. As below: [URL] Contained in the my "external pages" are different slide contents that I want inputting into the 'sub_content' div as below: [URL] If you click 'Test Link 2' you will see it fade out but it's then loading in the main page again? I think it is this line of code found in submenu.js where the problem lies? var myXHR = new Ajax( objLink.href + '&blnAjax=1', { method: 'get', evalScripts: true, autoCancel: true, onSuccess: showSubPage } ).request();
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Jul 19, 2009
is there a way to run js functions one at a time? example, this is part of some code i
have:EvalSound('CorrectIs');
WrongAnswer();
PlaysRemain();
[code]....
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Oct 16, 2009
I have hidden div, that i want to show by sliding it in from topborder.The problem is that i don't know how to make it "slide in" instead of"wipe in".I want it all to move with it's content instead of showing more andmore of it.
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Jun 2, 2010
I have a list of sequential numbers here. How can i show the 5 numbers infront and behind a clicked number?e.g. When i clicked on the number 0, this is the situation:5 4 3 2 1 0 -1 -2 -3 -4 -5So when i clicked on the number 2, it should show like this:7 6 5 4 3 2 1 0 -1 -2 -3
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Jan 13, 2012
Im looking for something that would allow a user to click on a button / link that would then reveal hidden content by sliding the whole of the main site content / container down.
I found this which slides the page content to the left or right [URL]
But need something vertical, almost as if the whole site was a big vertical accordian.
Or like on twitter / facebook phone app when refreshing for new tweets etc.
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May 9, 2011
I'm trying to create an image gallery using a ul with an id of #gallerylist,where the images are contained in the li items. I would like the images to .fadeIn() sequentially, i.e. looping through the li items one by one. I've had a go with the .each() method, but the images all appear together, which isn't what I'd like.
Here's my basic code so far..
$(function () {
//select first image from the gallerylist ul
$('#gallerylist li:first img')
// once the image has loaded...
.load(function () {
// set the image hidden by default
$(this).hide();
// select the li container for the image
$(this).parent()
// remove the loading class .removeClass()
// then insert the image
.append(this);
// fade the image in $(this).fadeIn('slow');
})});
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Feb 9, 2011
I'm using Lightbox picture displayer [URL].. and a content slide show UI [URL].. on the same pagesimultaneously. Although when I connect to the javascript files in my html page one of the effects won't work. Whichever javascript file I include last doesn't seem to work.
In the scenario below my content slide show effects won't work because they are listed first. It seems that whatever is listed last overrides everything else. I've also listed the error I get when running the page.
[Code]...
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Apr 30, 2009
I am using this script called virtualpaginate, I have it all working but there is one thing that I would like to change. currently it displays all the paginated page number, I have 14 so it looks like "1 2 3 4 5 ... 14", What I would like to do is change the script so it will show " 1 2 3 4" once you click 4, 5 will appear once you click 5, 6 will appear and so on. I am completely stuck on how I can archive this. The section of the code I need to change is below:
Code:
virtualpaginate.prototype.paginate_output_flatview=function(flatviewcontainer, divpos, anchortext){
var flatviewhtml=""
var anchortext=anchortext || new Array()
for (var i=0; i<this.pagecount; i++){
if (typeof anchortext[i]!="undefined") //if custom anchor text for this link exists
flatviewhtml+='<a href="#flatview" rel="'+i+'">'+anchortext[i]+' |</a> ' //build pagination link using custom anchor text
else
flatviewhtml+='<a href="#flatview" rel="'+i+'">'+(i+1)+'</a> | ' //build pagination link using auto incremented sequential number instead
}
flatviewcontainer.innerHTML=flatviewhtml
this.paginate_build_flatview(flatviewcontainer, divpos, anchortext)
}
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Feb 2, 2011
I'm having a little trouble with 2 differentJS scripts. I have a drop down slide menu and a parralex slide gallery. Both work on separate pages and puton the same page they still work however the submenu of the slide down menu does not. if I remove the style sheet that belongs to the gallery
Then the munu works, however (obviously) the page layout goes wrong. if i remove<h1 class="title">Alex Holland Perspective</h1> the menu works however page layout goes wrong andI loose my header
Here is the code.
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Mar 16, 2009
I discovered this really great jQuery plugin which adds a scroll to top link to every page (implemented through my CMS) - http://blog.ph-creative.com/post/jQu...ll-to-Top.aspxIn Firefox its fine but in IE after going through a few pages I start to get an alert box which says "Stack overflow at line: 13". I understand that this may be caused by an infinite loop but being a JS novice I'm kinda lost as to where to start.
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May 30, 2010
I think right now jQuery slideDown() will show the content bit by bit (line by line) of that DIV, showing top content first, and then little by little, the content below it...
Is there a way to actually slide the *content* down as well? In order words, showing the bottom of the DIV, and then it will move down, a little by little, and then show more of the content above it.
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Jul 14, 2009
When loading my web page I'm getting this error"stack overflow at line 0"What can be the reason for that? Is it related to the images I'm using in my site?
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Sep 1, 2002
Is there any way to prevent this error, flush some memory maybe?
Is it caused by logical coding error? (script runs error free except this)
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Dec 7, 2010
asume I have a stack of images:
<img src='img1.jpg' class='imageClass' />
<img src='img2.jpg' class='imageClass' />
<img src='img3.jpg' class='imageClass' />
[code]....
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Apr 6, 2009
I have written a function that works but it is recursive so ends up blowing the browser stack.I have seen a few examples of converting recursive functions to use a local stack but cannot convert my own function.I have a recursive function that is using the return values to build a result.
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Aug 23, 2006
I'm testing out the Opera browser to see what to expect from the upcomming Wii browser. But whenever I try to play this javascript game (www.kirl.nl/javaSnake.html), I get the following error:
"ECMAScript interpreter stack overflow.
Script terminated."
How does Opera handle Javascript diffrently, is there possibly a site wich lists the diffrences between the browsers and how they handle code?
Any specific Opera quirks you know of?
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May 1, 2007
Does anyone know of a hacked up JS patch for Error.prototype.stack or a getStack functionality for IE and Safari?
Does Opera have Error.prototype.stack?
Maybe something like:
Code:
Error.getStack = function getStack( error ) {
if( error.stack ) return error.stack;
// look up the call chain...
var fakeStack = [ ];
for( var caller = arguments.callee.caller;
caller != null; caller = callee.caller ) {
fakeStack.push( caller );
}
return fakeStack;
};
This is just typed in. I need tested library code that I can rely on.
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Sep 7, 2007
stack overflow at line 1797.i have this error when i run my java script calendar.
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Aug 22, 2005
when a user clicks back to get to my site, I want it to run a javascript
function.
can you detect when the FORWARD button is greyed out?
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May 6, 2011
I'm newbie on jquery and I hope to help me. i'vea problem to showmultiple stack image. For example, I've a jpeg image map on background and I would like to show multiple pin with multiple coordinates.
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Feb 5, 2009
Anyway my aim here is to have x,y, or z Div come to the front onClick.
how to do it with two Div's (using the code below) but not with 3 or more. I'm not attached to the code,
<script>
function changeZunder() {
layer1.style.zIndex = 1;
layer2.style.zIndex = 2;
[Code]....
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Oct 19, 2011
I'm making a form with some fields. Once the form is submitted it updates the page with a new div containing the data entered without refreshing. Im using jquery form plugin. What I'd like to achieve is the new div(.record) to .slideDown. I guess I need to somehow specify the exact div by giving it an id or number. I'm not sure and why im here.
At the moment when i submit all of the divs(.record) are hidden with .hide, then they all slide down with .slide. Best i can understand is to hide the last div then slide down. But again.. I don't know how to specify to only slide down the last div added and not the current .record divs on the page.
[Code]...
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Jun 17, 2011
I'm trying to manipulate the functions of Codaslider for a layout. What I need is the ability to use an image for slide dynamic slide navigation. I've solved the issue for dynamic hashing, however I'm stuck at modifying the HTML. I've tried a few things but I figure this is the easiest way...
[Code]....
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Apr 22, 2011
I have a JSP page that I am updating via an AJAX post. When the page gets sufficiently large, I get a "script stack space quota is exhausted" message. I realize it is due to the size of the response, but is there a better way than the following?
jQuery.fn.success = function(responseText, statusText, $form) {
var formId = '#' + $form.attr('id');
$(formId).replaceWith($(formId, responseText));
// Set up our form object again now that we've replaced our form with the data coming back.
$form = $(formId);
// ...
};
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