I have an HTML page which pases some value on button click event to an API using jquery and its succesfully running.It returns true or false.i want that if its returns true a popup box should appear where i have to show some message. i dont know how to do so after getting that respose as user have already submit the form.
View 1 RepliesThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have a form that is in a popup window. I need the form to submit to the opener window. Is is possible to do that? The opener window is the main window so it is does not have a name and there are no framesets.
<form action="something.php" method="post" target="????">
I'd like to use window.opener in the target but that's JavaScript...
I know somebody has done this before and has the code.
Basically, I have a form with two submit buttons. One is called "Save", and the other is "Preview". I want the "Save" button to submit the form using normal means (replace the current window).. but the "Preview" button must submit the form into a new window.
Can this be done? I started a thread about this in the HTML forum, and some have said it can be done via javascript, so here I am.
Can I pass the form contents (input tags, etc..) to some kind of javascript function and then have the form submit into a new window? Will I still be able to have the "Save" button NOT open a new window?
Here's the code I have right now. This basically is just two buttons that open the form into the same window. It's the Save button that I want to open up into a new window only.
:
Code:
<form name="form_name" method="post" action="http://www.domain.com/file.php">
<input type="submit" name="Save" value="Save">
<input type="submit" name="Preview" value="Preview">
</form>
I have a form which enables users to type in some text in a <TEXTAREA>,
allowing them to use HTML. I have defined two submit buttons - one to
submit as usual, but one which I would like to popup another window and
submit the typed text to different action/script to give a preview. Code:
I have a web page where I want the user to click a button to see a pop
up window where they can browse files on their computer to upload and
then when they click the submit button have the popup close and the
form to be submitted to the main window.
lets say i have a have page a with frame b, frame b has 2 forms, c and d, how would i go about making it so that i could submit form d from the parent page?
ive tried window.framename.document.formname.submit(); but it doesnt work and ive searched and havent found anything that worked either...
I need to set up a form that once submitted opens a window thats 550x400.
The form needs to be validated first however. I used an onClick event on the submit button but that opens the window regardless whether a user filled it out or not.
i'm using greybox on my website, and using survey. i want when click submit button then post form data to opened greybox window.. but can't..
my form actions
<form action="anket.php?islem=ok" method="post" onSubmit="javascript:return GB_showCenter('Anket',this.action, 280, 350)" >
greybox window open, but can't show post data..
I want a form that people fill in their name, email address then click a banner to submit the information to my site admin email address but as they submit using the banner, I want the site the banner is advertising to open up in a new window while the main page will go to a 'thank you' page.
Does anyone know how to do this?
So far I have this:
<form method="POST" action="http://...a php form" >
<p align="center"><span class="style6">Name</span><br>
<input type="text" name="Name">
<p align="center"><span class="style6">Email</span><br>
<input type="text" name="Email">
<p align="center"><input type="submit" name="submit" value="Submit">
<p align="center"><input type="image" src="http://..image" alt="Submit"> </form>
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIs it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
View 2 Replies View RelatedI have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I'm trying to get an upload popup working with the jQuery form plugin[URL].. When I click a link I load a form html from the server and add it to a container div by setting the div's html attribute. I then attach a submit handler to the form so I can call the ajaxSubmit function of the form plugin.
[Code]...
Malsup's most excellent and comprehensive Form plugin has me completely stuck on just one thing.Take a look at this: http:[url]....At the bottom are a variety of submit buttons, and when you click one, it knows which one has been clicked.And I've been through the js and the source and the examples and I can't figure out how the bleep it's done!I'll tell you why I'm asking, then perhaps you can probably tell me I'm doing it wrong anyway!Let's say a blind person logs in, and want to edit their presets.I don't want the form to be too complex or clever or ajaxy, as screenreaders don't like that, so it just iterates through as many presets as they have, and populates a form with edit boxes.But there's no point "pushing back" 29 unchanged items just to edit one row.
So my idea was I'd just "fieldSerialize()" the details of the row that was currently being edited and submit that to my little php routine that updates the db. Then they can do a refresh just to hear the list again.The js looks like:
$(document).ready(function() {
$('#myForm').ajaxForm(function() {
var queryString = $('#myForm').formSerialize(); [code]....
All works fine like that. But if I change line 3 to: var queryString = $('#myForm :button').fieldSerialize(); it doesn't work. I've also tried:
'#myForm :button'
'#myForm .button'
':button'[code]....
Maybe I should just generate as many separate forms as there are presets, but then I'm going to need as many ready(function)'s as there are rows, which is going to be very messy.
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle.
And for update " Are you sure you want to update Quantity to....." OK or Cancle.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....
So, here's my problem :
I've created a table in my document, presenting a list of items, one
can 'select' by clicking on it... (Kinda like a menu, you make your
choice from) But since this table can get very long, I've put
something of a 'search-form' on top, which enables the user to make a
selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the
form action. Some PHP script will make sure that the form is filled
out already, the next time it's presented.
The table, containing a list of products is presented, below the form.
When a user clicks on a product, the product should be "selected". At
first i just used a <a href="zoeken.php?prod_id=24"> link to do this,
but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden
form-field using JavaScript, using a onClick event.
Here's my code :
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
Using jQuery Form Plugin on a form that submits text & file fields to a remote server, the resulting XML/JSON returned does not appear to be available to jQuery.
[Code]...
Im trying to create a hidden form field in a parent window from within a child window (popup). I am trying to use jQuery, but unfortunately the hidden field does not get created.
Code JavaScript:
This should probably be pretty basic and I've been googling around as to the best approach to take and still a bit confused. I have a form that currently submits a form to a new window using jquery (shown below.) The form once submitted could go through a few redirects within the new window (it's calling some facebook stuff.)
All I'd like is when the initial new window pops up is for a spinner to appear in the popup window until the first response is returned. Is there a decent example on how to do best achieve this?
[Code]...