JQuery :: Forms - Add New Form Options
Aug 16, 2011
I google'd myself silly, I can't find tutorials for this. I hope someone could lend me a hand.
I'll try to make this simple. I have a PHP & MySQL driven site. I have a form for adding new content.
The form has a set of check box options that are pulled from MySQL.
At the bottom of the check boxes there is an "Add New" input field which I want to be used to add new check box options right above it.
database
So as I understand how this should work, when I click in the 'add new' text field, type something in, then press enter - the value of the add new field should be sent to a php script, addnew_backend.php. The form itself should not submit it's data. The PHP script will add the new value to the mysql table of options, and if successful, returns the newley generated checkbox which should fade in right above the add new text field into div#newoptions.
addnew_backend.php
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Jun 17, 2011
Is it possible to add additional data to the forms plugin options before submitting an ajax form, this would be only setting the data option after setting the main submit options previously in an object?
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Feb 27, 2002
Info from:
http://www.w3.org/TR/html4/interact/forms.html
I am trying to create a multiple selectable SELECT menu however I also want to have categories in this menu, so the menu might look like:
Category 1
>> Select Option
>> Select Option
>> Category 2
>> >> Select Option
>> >> Select Option
Category 3
>> Selection Option
for example. Now this OPTGROUP would be perfect but it only works one level deep. Can anyone think of an alternative to this, perhaps using javascript which prevents the user from selecting the categories?
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Sep 16, 2010
I want to make few forms but 1 submit button. I want to do 1 page , 5 forms , 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
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Dec 30, 2009
I have a form for the registration of a event for our club. Now I want this. If the check box groep is not selected there is a fieldset individu_km. If I select the check box groep this one must hide and the fieldset groep_km must be showed. This is the code i have now already found and changed.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
[Code]....
To hide the fieldset groep_km works only the fieldset individu_km won't hide.
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Apr 26, 2009
I'm not sure if my term usage is correct, but using a select form field with various options. I would like that when an option is selected, a php query is performed, and the rest of the form is updated according to the selection based query.
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Jul 26, 2010
I'm simply trying to get one form's submit button to submit another form.. Just can't seem to figure out why it does not work.. Could anybody take a look?Click Here
$(document).ready(function(){
$('#submit1').click(function(){
$('#form2').submit();
[code]....
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Sep 29, 2009
I have built out a fairly rhobust app using jquery and jquery-ui all was going well until we started to bring different screens together inside a tabbed interface. Seems that now when we execute our validation code on one form its checking the fields of all other forms on the page.All of my forms do have unique ID's and all elements within all forms have unique ID's.My understanding of using this.find inside of the submit event was that it should only find the forms elements am I wrong? Method that performs the actual validation:
function validateForm(event){
var allOk = true;
$(this).find("*[validation]").each(function(){[code]....
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Sep 4, 2009
I have a page which displays a list of resources in the database. For each of these resources I have a comment form. I am using jQuery form plugin to submit the form through ajax. After submitting I want to display the comment which was just submitted w/o reloading the page. But how do I know which form was submitted? I attach the resource ID as a GET variable to the action url of the form. If I can get the action url then I think I'm saved.
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Mar 22, 2010
[URL] that is the code in all its basic form (just stripped out other html). I am trying to modify the form actions of the 3 forms when i click on the tabs at the top of the page. but only the action of the delete form (id=form-horse-delete) gets modified. the other 2 forms do not change. i am not sure what the problem is. in IE8, if i have the jquery modifying the action of the 2 forms (add/delete), it gives a JS error. if i take out the add/delete in jquery, there is no JS error.
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Feb 21, 2007
Does anyone know how to get the value from a form option (dropdown list) and have it post the value without having a submit button?
So that when I choose a value in the option list the page is automatically reloaded with that value?
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Sep 16, 2009
I have a form that is repeated through out the page by the backend, which I have no control over.
<form action="">
<textarea class="your_comment" rows="10" cols="70">
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Jan 12, 2008
I am helping someone out with a form. He wants the name required, easy enough, but then only an email or street address required. I have tried a couple of things and it is not working.
I am trying a very simple code:
<script type="text/javascript">
<!--
function validate_form ( )
{
valid = true;
if ( document.contact_form.name_mailing.value == "" )
{
alert ( "Please fill in the 'Your Name' box." );
valid = false;
}
if ( document.contact_form.address_mailing.value == "" || document.contact_form.email_address.value == "")
{
alert ( "Please fill in the 'Your Information' box." );
valid = false;
}
return valid;
}
//-->
</script>
Am I not using the or operator correctly? I only want to have the address or email required, not necessarily both.
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May 15, 2010
how to fix the coding so when a user select a category it will add a different hidden filed for that option for example: When the user selects category "Men" the hidden filed
Code:
<INPUT TYPE="HIDDEN" NAME="REFERRER" VALUE="http://men.com/acatalog/">
automaticly will be added the search
and when the user selects category "Kids" the hidden filed
Code:
<INPUT TYPE="HIDDEN" NAME="REFERRER" VALUE="http://kids.com/acatalog/">
automaticly will be added the search[code]......
how do I make the "Select Catagory" a Must Choose and if not chosen to give message that say"Please Select a Category"
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Apr 3, 2011
I have a page that runs a lot of calculations.The math is computed on the fly using java scriptwhen all the calcs are in, prior to form submission the user needs to evaluate which numbers they prefer, and from there, once they select them, the form, based on those choices, will perform one last calclets say we have 3 result fields
r1 = 2000
r2 = 3000
r3 = 4000
what i want to do is have a select field be able to display those values at the bottom of the page;for example
<select name="s1">
<option value=[field contents of r1 above]>[field contents of r1 above]</option>
<option value=[field contents of r2 above]>[field contents of r2 above]</option>
[code]....
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Jan 30, 2010
I want to add more dropdown options which are dependent on previous options. Now I have "hand" and "loft". I want to add next option "model" How to add third dropdown option box?
Here is the code:
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Jul 22, 2009
I have been searching for hours and have not found what I am looking for. BUT, I have seen it before when I was NOT looking for it. haha!
Anyway, I am creating a form. And the form has an element that asks for "How Many Children?" followed by a dropdown from 1 to 6.
Well I would like to display another set of elements from 1 time to 6 times, based on their selection.
Name: ___ Age: ____ Sex:____
That will be displayed as many times as the user selects.
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Jul 5, 2010
I'm new to javascript and have stumbled yet again. Currently, my website has a form where you can type in your name, and generate a url.
Code:
<script>function updateURL() {
document.getElementById("theurl").innerHTML = '<a href="http://www.website.com/'+document.input.usersname.value+'/index.html">Here is the first link!</a>';
}
[Code]..
First, if I wanted to create an identical form and button, but with a different url (index1.html instead of index.html), do i just need to add numbers to the "updateURL();" parentheses on both the new input type=button, and the function script?
Second, if I can make this 2nd form and button, how can I make the 2nd input type="form" automatically mirror whatever is typed in the first input type="form"? Whether this be by button onClick, or live as they type it, it doesn't matter. I don't want to bypass the 2nd form however because I want to give users the option to erase the automatic mirrored text and put in a different name if they would like.
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Jul 5, 2010
I'm currently working on a website called 'eXtreme Gaming' I've almost completed it, apart from two things.
- Adding two values on my checkout page for the Grandtotal (I've tried everything, but I'm too much of a noob and have probably missed something small).
- Validation of forms (I don't know where to start here, I've looked on w3schools for tuts etc but I'm having difficulty incorporating it on my site)
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Jan 4, 2009
Is there any way to find if any form exists on the page and if yes then name of all forms?
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Feb 2, 2010
I'm trying to make a function that will disable elements of a form based on which options are selected.
I have made this work for individual form controls but now i want to make it into a function that could be used on any form control.
Here is the broken function
Code:
I've probably just missed something but i really cant see what?
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Apr 4, 2009
I have several forms on a page, one for each "product". Each form is essentially a row with product information. I have a "Add to Cart" button. Now, I want this to work so that when you add a product to the cart, it does it without refreshing the page (AJAX?)
I found this [url] and it works to an extent... it updates the DIV for the first product only (and understandably)
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Feb 23, 2009
I'm trying to get a form submit working for all browsers, and I am using document.forms['formname'].submit().
However, despite having 'formname' set on the forms in both the name and id properties, Safari 3 will not submit the form correctly; when I debug, $_POST is empty. IE, FF both work here fine. If I use document.forms[0].submit() it works correctly, but this code will be working in a dynamic site where I can never be sure at what index a given form will reside. I can make it work using document.getElementById('formname').submit(), but that does not work with js turned off, and I need this to work with js on/off.
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Sep 16, 2010
I want to make few forms but 1 submit button. I want to do 1 page, 5 forms, 1 submit button so when i click on the submit button it will send the 5 forms as 1 form.
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Feb 20, 2009
I am creating a form to enable advertisers to create listings on an accommodation directory site.One of the form fields is a drop down with the following optionshotelguestHouseselfCateringinnholidayParkcampingThe top part of my form is the same for all these accommodation types. However I need to include a section specific to the accommodation type. This section will include groups of radio buttons and checkboxes allowing the advertiser to choose which facilities/amenities are available.For exampleA hotel may have 24 room service campsite may have a shop on siteI was planning to have a separate div for each of the accommodation specific sections and toggling the display based on the choice of the accommodation type from a drop down list.I have just had a horrible thought that it may be possible if javascript was not enabled that either none of the sections would be displayed or even worse all of them at once.
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Sep 19, 2005
I have a page with 2 product forms to add to shopping cart each form has the same fields.
when someone changes one of the dropdown boxes depending on the size it is to change the price to a certain value. This works ok whan you only have one form but now that there is two forms. When you change the second form dropdown box it changes the price on the first product.
OnChange='if (this.value<=16)ChangeHiddenPrice(90);'
I suspect it has to do with how i reference the form field
function ChangeHiddenPrice(newprice) {
document.getElementById('PRICE').value=newprice;
}
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