I would like my page to load (and show a loading.gif in place of the main not-yet-downloaded image) and then download the main image. Uisng jquery, how can i achieve this? Ideally, i'd also like then to be able to switch that main image using links, again showing a loading.gif prior to display.
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I have a single webpage that contains information on all 50 U.S. states. There are 50 links at the top to jump down to the state you want, and at the bottom of the information for each state a Back to Top link.
I'm making the Back to Top link into something more complex, and it will require three or four lines of code.
So that I don't have to repeat the code 50 times, and create a burden when I need to edit it, I want to place it in a .js file and call it x. Then below the information for each state I'll simply have:
Does calling code from a .js file 50 times slow down the page load? Which method would load faster?
I have some javascript code that does some GET and POST requests that are required. Sometimes it doesn't fully execute for the user because they close or click onto another page before the javascript is completely done. Is there anyway I can let all of the javascript load first and slow down the actual page load of the website.
View 3 Replies View RelatedIs it faster/more beneficial to have two snippets of code be generated by php at 2 different urls and then have a load function for each url? Or have the two snippets on one page, surrounded by id's and then load them that way?
View 1 Replies View RelatedI'm having an issue with the status bar in Mozilla and Netscape showing that
it is still waiting on the page to load even after it is finished. This
problem does NOT occur with IE.
In summary, I am using a onLoad event in the BODY tag to communicate back to
another server each time a page finishes loading. I do this by using a "new
Image()" and setting the .src property to the server. The .src includes a
value in the querystring so I know what request it was that finished
loading.
The challenge here is that the status bar still shows "Transferring data
from www.mysite.com..." despite the image being loaded. It never clears and
leaves the user with the impression that there was a problem loading the
page. My web server logs at the mysite.com show that the browser does
indeed make a request for the image and I get the querystring just fine and
it returns a status of 200 so the image is being found and served ok.
I've tried everything I can think of to solve this and really could use your
help please. Bottom line is that if you use the "new Image" statment from
within the OnLoad event of the Body tag, Netscape and Mozilla never seem to
update the status bar to show "Done" despite it succesfully loading the
image.
Here is a simply snippet you can use to easily reproduce this issue:
i want to load web page on div [URL]
Code:
$('#news_modal_container').load(getContents_link);
getContents_link contain site name.
above code work while load local page, but not load server page or site
I'm trying to get this image to pop up when the page loads. It's JQuery (it's already loaded on my server so I don't have to place it in the script
Anyway, I'm stuck. Do I need to add a div within the body? Or is there something else I need to do.
Code:
I use jQuery load function to load another page into part ofcurrent page in asp.net. it is work correctly but insecond page i haveone instance ofCKEditor that is not loaded in first page after use load function.
View 1 Replies View RelatedI know the question begs a question. Why? I have no control over the DB or the Forms. Using 3rd Party based web app. I have this: $(document).ready(function() {
$("#MyButton").click(function (){ $('#CurrentPageInputTextArea').load('jqloadFrom.htm #OtherPageInputTextArea');
});
});
I thought I had this licked. How do I load a file with an onclick AND replace the current page with another page?
<span return true">
<img border="0" src="../img/ok.gif" width="30" height="30"></span>
I have a query. What is the best way to fade in an image on a page load so that the image is visible if javascript is not supported and does not jump around all over the place if it is supported. What I have found is that I can make it work using either document ready or on window onload however the images all load first and the page goes all crazy for a few seconds before the script actually does what it is supposed to. What I do not want to do is hard code the css display as none for the image as a property as either an element style or in the css file. The reason being that if the script does not run... the image will never load.
OPTION 1
$(
document
).ready (
function (){
$('#logo'
).hide().
fadeIn(
3000
);});
OPTION 2
window.onload =
function(){
$('#logo').
hide().fadeIn(
3000 );};
How can we show the image before the page is getting fully load.
something like page is loading. basically i want to show loading image before my whole fetched data's/images not comes or loaded on that page.
can anyone here tell me how can i do that?
The pop up opens up and using the property id loads the data for that record.
in this pop up there is a javascript application, when the user clicks on one of the small images.. it loads full size in the span..
now i didnt write this javascript.. someone in a forum wrote it for me.. i have been able to edit it to suit my layout requirements..
my problem is that when the page loads, the span is empty..
i need an image to load in the span immediately as it looks wrong when it loads..
the picture i want loaded is 'out2' from my database..if anyone knows how to do this i would be very happy.. i tried just placing an img tag in the span but that didnt work.. thanks.
Code:
I want to slide an image or a page on page load..the below is an example
[URL]
Can someone point me to method for loading random image (in container) on pageload? I have three image containers and I want to load a new image in each one at each pageload, but I want to be sure no two images are the same at the same time (if that makes sense!).
View 6 Replies View RelatedI have an unordered list (ul#garment_selector) sitting in a div (div#program_scroller) and each of the list items has a link that I'd like to display an image and some text into a div on the same page. I don't want any fancy animations or anything like that, I just need to display an image and a related description/price into a new div, preferably without reloading. I have quite a few different lists of links and they change all the time so using an array to define the image/text is impractical for my needs.
View 16 Replies View RelatedI am building a site with ads that I want to rotate positions (this way I can keep it fair for advertisers- the bottom ad rotates up to the top) upon refreshing the page, searching through the site, or each time the user visits. I have three images (sponsor1.jpg, sponsor2.jpg,sponsor3.jpg) that are always displayed vertically in the right banner. I assume this is just a simple javascript slideshow tweaked a bit but can't figure it out.
I find plenty of js scripts that will rotate several images through one image location, but I want image POSITION 1 to start with sponsor1.jpg, image POSITION 2 to start with sponsor2.jpg..and so on... then upon refreshing the page image POSITION 1 is holding sponsor2.jpg, image POSITION 2 is holding sponsor3.jpg... etc
I wanted help for a JavaScript code. You might think I'm lazy for not writing it myself, but the truth is I am not a JavaScript coder. I just have a really simple website and I am trying to do something for which I know JS is required but I don't know how to do it. I've also searched around but couldn't find the appropriate code.
What I want to do is to make an html page load a different background image every time it refreshes.I will have a list of background images and I want to be able to add in this list, without having to change anything else in the codes after I do this (I think this is made by making an array of images and by putting .length somewhere in the codes, but I don't know exactly how I should do this).I already know how to do an external file (.js) and link to it from my .html page.Now I want the code to put in the .js file, and the code to put in the <body> of my .html file.
I'm trying to make it so that when a user clicks on a radio button, the image that is related to the radio button is displayed next to it (without reloading the page). At the moment all it shows is the image related to the currently saved option, which I'd like to keep on page load. Is this possible?
Here is my code for the radio buttons.
I have questions related to three operations using jQuery:refresh a div element on page lo append an element on top of the other elements in div change an image (pending/accepted) from the div's elements I know that there are tutorials for that, but i am so short in time.I just finished my PHP courses, and i am too tired to get into the jQuery magic right now.ere is the situation that i am confronting. I have to files: propune.php (which is basically the page that has the form and the div that should be refreshed/appended) and propuneri.php (the file that is handling ajax calls).
propune.php
(partial) http://pastebin.com/SFJ7zSRJ
propuneri.php
[code].....
Here is what I'm trying to do but the problem is "source.html" is not on a server somewhere. I am running everything locally. $('#container').load(source.html #sourceContent) Is there a way to do this exact thing but with a local file?
View 3 Replies View RelatedI have a question about load(). I created a php script that simply returns <img src="something.jpg" class="myimage">
To test I created this code, the image loads fine and the mouseover works fine showing the alert dialog :
However, my trouble seems to be that if I bind mouseover to the class "myimage" nothing happens, like so :
Seems that the document would load the html first then the mouseover bound to the class (myimage) would fire off.
The code is supposed to generate this: PS: This is generated by a PHP Function that the Ajax Load Method Calls.
[Code]...
I've been noticing a lot of problems when loading these stuff, Sometimes I have to remake the HTML Tags because its not showing anything. Is there any option? I want it to load EXACTLY how it is, I don't know if this is some kind of protection for bad code, but if it is I would like to disable. But also, this code is really clean. no problem, I don't know.
I have a problem when trying to load an HTML5 element with Ajax (jQuery.load ()).Here is a simplified example of the problem.
Main page :
<!DOCTYPE HTML>
<html>
<head>
<title>Title</title>
<!--[if lt IE 9]>
[Code]...
Basically there are 2 elements on the target page that I would like to load into the calling page, but I would like to do it without making 2 calls to the page if possible.
View 11 Replies View Relatedonly first image in the all_images array loads and the rest stays hidden. it works first time i load the page, but any other time it loads only one image. i understand it might have to do with the cache. what could be possible cause for breaking the .each() loop after first iteration? i'm using jquery 1.3.2, png fix and php
[Code]...
