Basically there are 2 elements on the target page that I would like to load into the calling page, but I would like to do it without making 2 calls to the page if possible.
View 11 RepliesI am trying to update 2 div with a .ajax (i tried also .get ) call and i make this code working, so that the updating is realized within 2 url calls. but i can 't figure out how to do it within 1 call?
if i try the read the data var then i get the innerHTML of the clicked node (dhis) i thought i could read up the data var and extract somehow the innerHTML of #checkout_basketList but i can't because .ajax/.get somehow takes the innerHTML of the clicked node (dhis). so i have to make a new call that i do with .load (because of the partial load capabillities) but then again its stupid to do 2 call when all the info is already in the first call, is mine approch not good.
jQuery(document).ready( function($) {
$('.link').live('click', function() {
dhis = $(this);
RETURN_POSTID = do_some_js( dhis, 1 );
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Firebug reports "Failed to load source for: [URL]...environment: Apache 2.2.16 on Debian 6.0 (Squeeze) 64-bit using virtual host by IP:port. Here's the virtual host configuration:
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How do i animate10-15 divs without using 10-15 animate methods?
View 1 Replies View RelatedI am trying to assess why the slider that I've linked to in the head tag of my source code will not load properly on my page. My site's link is : [url]
View 1 Replies View RelatedUsing Jquery Cycle Plugin i have multiple containers on the same page. they have a next and prev button. the problem is, when i click the next button it will cause the containers on the pageadvance simultaneously, same goes for the previous button. it works fine when i click just on the images (they will go to the next image) but not with the prev. and next. button. i know i have to add some kind of var. to it. and i tried it but with no luck.
Here is my code.
$('div[id^=slide]').each(function(index) {
$('#slide'+ (index+1)).cycle({
fx: 'fade',
speed: 'fast',
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Playing with the wonderful Cycle plugin. Rather than using container ID's and having specific options for each, I want to use the same settings for multiple containers of the same class. In other words, rather than:
$('div#containerName').cycle({
fx: 'scrollHorz',
speed: 'slow',
timeout: 0,
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Here is what I'm trying to do but the problem is "source.html" is not on a server somewhere. I am running everything locally. $('#container').load(source.html #sourceContent) Is there a way to do this exact thing but with a local file?
View 3 Replies View RelatedI have a question about load(). I created a php script that simply returns <img src="something.jpg" class="myimage">
To test I created this code, the image loads fine and the mouseover works fine showing the alert dialog :
However, my trouble seems to be that if I bind mouseover to the class "myimage" nothing happens, like so :
Seems that the document would load the html first then the mouseover bound to the class (myimage) would fire off.
The code is supposed to generate this: PS: This is generated by a PHP Function that the Ajax Load Method Calls.
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I've been noticing a lot of problems when loading these stuff, Sometimes I have to remake the HTML Tags because its not showing anything. Is there any option? I want it to load EXACTLY how it is, I don't know if this is some kind of protection for bad code, but if it is I would like to disable. But also, this code is really clean. no problem, I don't know.
Is it faster/more beneficial to have two snippets of code be generated by php at 2 different urls and then have a load function for each url? Or have the two snippets on one page, surrounded by id's and then load them that way?
View 1 Replies View RelatedI have a problem when trying to load an HTML5 element with Ajax (jQuery.load ()).Here is a simplified example of the problem.
Main page :
<!DOCTYPE HTML>
<html>
<head>
<title>Title</title>
<!--[if lt IE 9]>
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I'm trying to use the function once which is .load() and fetch my content from there,then after that I'd like to seperate the class's or div's I'll be using such as <div d="test1">This content will show in the external website</div>But I'm having trouble doing that, I've used multiple lines just to load the same page and take small bits of content out and it doesn't work well together as some load's results will be different compared to the others.Heres my code:
$('#". $Server['ServiceName'] ."').fadeOut('slow', function(){ $('#". $Server['ServiceName'] ."').load('./includes/serversinfo.php #servers #". $Server['ServiceName'] ."', function(){ $('#". $Server['ServiceName'] ."').fadeIn('slow'); }); });
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unable to find through google or search here relevant answer to the question, so sorry if repetitiveI used this function provided by a member in this forum
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i don't know so much about jquery so just i use them with indication from their web site. so my problem is how can i use multiple source of jquery without one source stop the other,and that what i need:
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I have a site structured with a main html page that loadother pages that have some javascript code. Somejs have to be executed immediatly and some other js I need. I have a code like following
<!-- ********************** THIS SCRIPT SHOULD BE EXECUTED ON FORM SUBMIT -->
<script type="text/javascript">
myNewLine="
";
function inviaRichiesta(){var msg="";
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I have the following code to load some pages into a div using the load function. When I click one of the links though, nothing happens. I have read a couple of books on JQuery and looking at the examples they give, this looks correct so I am at a loss.
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I have the following code:
$("#printme").queue("printQueue", function (next) {
$(this).load("print.html", function () {
$(this).ready(function () {
passPrint(next);
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I want the images on #printme to finish loading before the passPrint function runs, but everything I've tried does not work. The ready() in there does not work.
So I know that with .load I can load a specific chunk of html. What if I want to load 2 chunks of html in one request? For instance my current page has
#nav and #content. My loaded page has the same and I want to replace these 2 elements with the new one (or it contents).
$('#nav').load(loadUrl + " #nav");
$('#content').load(loadUrl + " #content");
So the above doesn't work for me for 2 reasons: 1. I load twice. I don't want to do that (but I also don't want to load the js and all because it will mess things up) 2. This puts #content inside #content
This is my current script
<script type="text/javascript">
$(document).ready(function(){
$("div.content1").load("content_1.txt");
$("div.content2").load("content_2.txt");
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What I'm trying to do is get the script to look for class names div.content"x" and then correctly load content_"x".txt
Can the .load() function load .php pages? example: $('#element').load('mynews.php');
View 3 Replies View RelatedI use jQuery load function to load another page into part ofcurrent page in asp.net. it is work correctly but insecond page i haveone instance ofCKEditor that is not loaded in first page after use load function.
View 1 Replies View RelatedI was trying to display a pdf file inside a HTML div and was using JQuery $('#divid').load(url) to load the file inside a div. While other HTML files are loading properly, i am facing problem loading a pdf file.
The content does not get rendered properly, i am not sure whether this load function is supposed to handle this, but is there any other way to load a pdf inside a div?
This is my actual code:
var sub_listings_url = "index.php?option=com_mtree&task=listcats" + " #sub_listings > *";
var pagination1_url = "index.php?option=com_mtree&task=listcats"+ " .#pagination1 > *";
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Would it be possible to fill #sub_listings and #pagination1 with only one .load?
Is there a way to load more than one html fragment using .load()? That is, I want my homepage to pull in multiple pages of content into the main page so that I can create a one-page site that slides vertically.
An example of what I've got is
$(document).ready(function(){
$('#footer').load('about.html #content');
$('#footer').load('locations.html #content');
$('#footer').load('contact.html #content');
});
Which of course only loads the first about.html page's #content into the #footer of the home page.
I have a page that contains 15 tabs. When each tab is pressed, it calls a function that uses .load() to load that tab. In my initial testing, all seems to go smoothly (loading in less than a second). However, once you click about 10 tabs, the pages start to load slower, and by click 13, it takes more than 30 seconds to load.If you refresh the page this process starts over and the outcome is the same (by click 12-13 it is unusable). Below is the code. FYI the reload_timer was an attempt to reload the page if the query was taking more than 10 seconds It didn't work. I left it in for feedback in case I don't find a suitable solution to the actual issue.
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