why would my hide() call reset the entire page? the code is the mode basic:
Code:
$("#text").bind("click", function() {
$("#productContainer").hide(); //hides the containers });
it hides the div for few seconds and then the entire page reloads
I have a little tabbed content window that uses jquery and I have an annoying little problem: whenever I click on one of the tabs, the page resets to the top, so if you click on the last tab, you have to scroll down to see it again.
Here's a link: [URL]
If you look at this page in IE, I know, it displays all screwed up. I'm too tired to tackle IE today.
I'm trying to make a table that will hide multiple rows in single js functions... now I put together a way to do it, but it requires multiple id declarations in the functions, is there any way to do it with classes instead of IDs, so that I can have a blanket class that I can use?See:
Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">[code]......
i'm trying to make jquery UI's button and dialog plugins work with my form. i want the reset button
[Code]...
then on a Continue response the button should continue with its original purposewhich doesn't happen. i get a return: false type of behavior w/o return: false anywhere. can anyone point me in the right direction?
I own a GPT site that offers member Daily SUrveys. When a daily survey is completed, the time of completion is stored in SQL in Unix time format. I hired a guy to code a Countdown timer for me that would be placed next to every completed offer in member's panel and that would show how much time is remaining till the Daily surveys resets and becomes available to the member for completion again(Daily Surveys reset every 24 hours)
[Code]....
Page "A" has a function that pops up Page "B". When something is done on Page "B", I'd like Page "A" to reload.
Very much like here at DevShed when you click in the "Rep" button, a small pop-up opens, and when you finish giving whomever maximum positive rep, the original page reloads.
Im having some troubles with some functions i launch in $(document).ready() to initialize the page. Then if i click on browser refresh everything goes fine... even more strange when i place alerts between then calls to these functions everything goes fine too... but the first time the page is loaded it seems that the functions are not executed at all.
View 3 Replies View RelatedI am loading a page dynamically using .load with jquery and then i have another button on that page that allows you to go back to the previous page using livequery click function. However, when I go back to the original page, none of the page functions defined previously are working anymore! Is there a way to force the browser to reinitialize the script? How does one get around this problem with jquery?
View 2 Replies View RelatedI'm having trouble calling javascript functions that are loaded in the main window.
Here's what happens:
- when a link is clicked on my page, the contents of a div are reloaded with new contents from another file.
- The new file only contains the new contents of the div.
- I want the new contents of the div to call a function that was originally loaded before the new contents were reloaded.
- So, the main page loads the information and the javascript functions. Then, when the link is clicked, the new contents are loaded into the div with a link that calls a function that was already loaded.
- However, nothing happens when I click on the link to call the function.
Is there something I need to do to call the function?
I have a nproblem with running commands from a loaded page;[code]Now i want to execute the alert() on page BB.html when doing the load on page AA.html.
View 2 Replies View RelatedI'm writing this web app.For each view, when required, I'll have one or more script files named after the view. Some functions are shared across the site. So I extracted and put them into separate .js files. Some views may have sub-views (such as the login box).
And I ended up with 10 <script> tags per page (includes 3 jquery must-haves). Although in some pages I can lower it to 6, I still think this is a pretty big number, as lots of extra HTTP transaction is required when loading the page.
I put the <script> tags at the end of the page, before closing <body>. Most scripts didn't use $(document).ready().
So is it bad to have 10 <script> tags on each page? Is there a magic number I should never surpass? Is it a good idea to put lots of (unrelated) functions into a single .js?
And is it bad to have scripts executing at the end of the page rather than $(document).ready ?
This is hard to explain but here's my predicament. I have 2 drop down menus in a form for "Main Category" and "Restaurant Type". My boss wants it so when Restaurant is chosen from the first drop down, the 2nd drop down appears, which is what this code below is already doing.
The problem is if you submit the form, then decide to go back and change your Restaurant type, the drop down for Restaurant Type is missing. You can get it to come back by switching to another main category, then switching back to Restaurant. Code:
I found this slide show [URL]. I got it to work on my website [URL] using Firefox, but when it is viewed in Internet Explorer it will not work. Second question, When the slide show gets to the last image, after the last image all photos disappear and it resets itself changing the format of the webpage. Any way to not have the images disappear while it loops itself or is there a code to have it stop on the last photo and not loop.
View 1 Replies View RelatedI am writing a form that grows using ajax server responses to info as the form is filled in and everything is fine in standards compliant browsers but IE is having a problem. I have two js functions on the page that collect form data, send it to the server, and then write the server response as innerHTML to specified divs on the page. This works great in FF but in IE it runs the first function but fails on the second function and the two functions are identical except for the server routine.
The div that is populated with the server response so it doesn't seem to be a problem with the coding because if one works, and they are identical, the other should work too so perhaps IE is choking with the way it is handling two ajax objects on the same page? You will need to add something to the shopping cart first at [uRL] and proceed to checkout, then on the checkout page look in the url and change ste_chkout_proc to ste_checkout_proc and load the new url to see the dev checkout vs. the live checkout.
I have a single javascript file that contains all of my javascript functions. Each of the these functions are particular to different pages on my entire site. How can I create logic that will only allow those functions to work when certain elements or identifiers are present on a page?
View 9 Replies View RelatedI download the jquery library, when i include it as such:
It loads but i always get some sort of error in the functions in the page or something...as if the js is loaded but not correctly or as if it's missing, even though the download itself is correct
If i change the include path to (which is the exact same file i downloaded):
Everything works fine i am thinking maybe it could be something that has to do with encoding maybe? am not sure...any clue? it's only happening with the jquery JS files, the rest are working fine.
I have four links that use graphics to create an unvisited and visited state (using CSS). The link actually changes a section of text elsewhere on that page, so the user doesn't leave the page. The clicked, visited graphic reflects what text you are reading. You can then select a different link, and new text reflects the link you clicked on. What goes wrong is that if you click all four links, you eventually get all four visited graphics showing.
What I want is this. You click on the graphic and the graphic changes to visited. You then select a different link and that state goes to visited but the previous link that is visited too, changes back to unvisited. Therefore when you click on any link, that visited state is shown, and all others always reset to unvisited. The results is that the visited graphic reflects the current text on that page.
I have a problem with adding new inputs to a form (if and when required),Internet Explorer is fine but in Firefox if any previous input fields are filled when the more button is clicked they get reset to blank.JS:
fields = 0;
function addInput() {
if (fields != 100) {
[code].....
I am trying to figure out how to make a random number I can plug into a script count down from that number at certain times of the day until it reaches 0. I would like it to reset itself at midnight every day. I'm trying to make it work with a script I found on here that resets itself at midnight every day. So instead of it counting down too fast, it would count down to the next number after a randomly generated number of minutes until it reaches 0. But it wouldn't necessarily have to end at 0 at midnight. It could go from 845 to 323 at the end of the day at a slower pace. Is that possible?
View 5 Replies View Relatedhow to use Javascripts and using Prototype framework by following a step by step tutorial from a book. Unfortunately when I stepping through the following code:
Code:
<html>
<head>
<title>
[Code]....
The prototype file can be acquired at Prototype website download
I have a page that inserts a div after another div on my page. Basically this div and its content are generated by the server and outputted via Ajax when the user clicks a button.I have something like:
//Listener function
$("div").click( function () {
alert("thing");
});
Clicking any of the divs that were loaded on the page will give this alert however, clicking on this div that was inserted after the user clicks a button does not respond to this listener. I put my rendered html into the w3c validator and my page has no errors (because I thought that maybe I had a missing end tag which would cause jquery to not work).
I use the wonderful .animate() method to create a "parallax website". It's still in developpement, but you can see the result : www.ohnewgarden.fr My problem : When you are at the very right, the animate effect reset my left property before animating. Which is weird is that this "reset" is applied only to two layers, without any sense. I'm going crazy !
So if someone could help me, it will be very nice ! It's probably my code which is wrong, but I can't see the mistake.
[Code]...
I said for my defense, I have tried to remove .stop(), tried to change parameters of .stop(), tried to reset (like there) the left property with a .css() method, and I have also tried to animate with "+=" (like there), but nothing works. If you follow to the link I gave, you could see very easily by clicking on "Contact" and after animation by clicking on "Accueil".
I have written a number of functions designed to return frequency data on 1000 randomly chosen numbers using different math functions for the rounding. I would like to include all of these functions within the wrapper of another function so that only one call is needed to get returns from all of the 'inner' functions. However, while each of the functions works in isolation, the moment I wrap them in another function they stop working. :confused:
The following code is one of the functions 'frequencyWrapperOne' that has been wrapped in the function 'testWrapper'. A call to testWrapper does nothing.
function testWrapper()
{
function frequencyWrapperOne()
{
[Code]....
$(something).split(something),this is a function with a function as a property for that function.
View 8 Replies View RelatedI have to make a servlet for controlling all other servlets. The
browser should show only one url. eg:
http://www.ourdomain.com/ControllerServlet what I have to do for this?
I am currently using
onload="document.getElementById("hidepage").style.visibility="hidden";"
to try to hide a div box. Yet this will not work. I've tried FF, IEpp4 (IE platform preview 4) and IE9beta. This is the correct <div> id, and I do not know why this will not work.