Passing Current Value Of Fields To MYSQL Dropdown

Sep 27, 2010

i have a form with fields (30+), and about 5 of them are fields that need to pass into my dropdown (actually a dynmaic dropdown, select SOURCE, then whatever source u select it'll show options that are mysql source=$source), so it can go into my mysql query, and filter out the best results. (i.e date_of_birth, min_credits, state, etc). Needs to be done without submitting, hence javascript. Im echo'ing my query and its saying the variables i'm trying to pass are UNDEFINED. Am I not passing the vars correctly? do i need to prep the vars to "grab" them in the current field?

[Code]...

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Passing Current Value Of Fields Into Dynamic Dropdown?

Sep 27, 2010

So i have a form with fields (30+), and about 5 of them are fields that need to pass into my dropdown (actually a dynmaic dropdown, select SOURCE, then whatever source u select it'll show options that are mysql source=$source), so it can go into my mysql query, and filter out the best results. (i.e date_of_birth, min_credits, state, etc). Needs to be done without submitting, hence javascript. Im echo'ing my query and its saying the variables i'm trying to pass are UNDEFINED. Am I not passing the vars correctly? do i need to prep the vars to "grab" them in the current field?

this is what i have in my <head>
<script language="javascript" type="text/javascript">
function getXMLHTTP() { //fuction to return the xml http object
var xmlhttp=false;

[Code].....

The only var that is passing is SOURCE, and that's because its the name of the first dropdown

i need to set up like a GET method on my RECEIVING page? or can i just pass variables through? Do i need to get the "existing" data in the fields first?

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Apr 7, 2009

I have a mysql database (name) which helds 3 fields, id, naam, email. In php I've made the connection and create a selection menu and with javascript I was able to display, (when I selected for example "Bas" in the selection menu), bas his name into a first input text field. Now a couple of things I still want but can't seem to get it right.

First: I also want to display "bas" his email address in a second input text field. (the database contains more names, but this an example).

Second: The selection menu starts with the first name in the database, but can I make it for example "Select name" as beginning.

[Code]...

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Here is my form fields:

Here is my java script:

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<select name="type" id="type">
<option value="1">Accessories</option>
<option value="2">Cables</option>

[code]....

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If I have a jquery var, such as:

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Code:
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Apr 12, 2010

I'm trying to make 3 drop downs (based off of mysql tables), to narrow down the selection. Source, School, and Program. So when when they select SOURCE(source), all the SCHOOLs in drop2 will be based on the SOURCE selected in the previous dropdown, and whatever school(cid) is selected, the program will be based off that school(cid) and display all the programs for that school. I've google'd high and low for something, and no avail. Here is what I have, I am just trying to make 3 drop downs narrow in, without pressing submit (I am new to ajax and javascript etc) The issue may be in that java part, I've look in the php and mysql, but nothing.

PHP Code:
<table width="517" border="1"><tr>
<td width="87">Source:</td><td width="414">
<? echo'<select name="source" onChange="showUser(this.value)">
<option value="">--Select--</option><?php while() { } ?>'; .....

My javascript
Code:
var xmlhttp;
function showUser(str){
xmlhttp=GetXmlHttpObject();
if (xmlhttp==null){
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return;
} .....

Right now, the results display in a table, I don't want that - I need them to display as results in the next dropdown.

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Oct 24, 2009

i have a script which i found on the internet. i modify that script according to my needs. what is in that script is there are three form fields with two buttons. one button is "Give me more fields" clicking on this button will give you more fields. and second button is submit so the data goes to server side and will be added to db. the problem is when i click give me more fields it gives me three more fields which is right but when i fill all these fields and click submit button it adds to the db but the data in the first three fields adds in the one row and the other three fields data adds in separate row which is not fine for me. so how can i do this so all the data will be added to only one row.

here is js code

Code:

var counter = 0;
//Start a counter. Yes, at 0
function add_phone() {
counter++;

[Code]....

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Code:
<script type="text/javascript">
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Dec 30, 2011

This one should be easy. In fact, it was working for a long time as far as I know. Then I upgraded from jQuery 1.4.4 to 1.7.1 and a few things stopped working. (This is according to my client; it's possible it's been broken for a long time.)

So a customer logs in and sees his/her registration information. Name, address, phone number, etc... It gets this information from a MySQL database. For the customer's home address, there's a dropdown for the state (MA, NH, etc...) Rather than displaying the default specified in the HTML code, I have a bit of jQuery code that is supposed to change the dropdown selection to the user's home state as stored in the MySQL database.

Unfortunately, nothing happens. It rather than changing to the user's home state, it just displays the default state (AL, the first alphabetically).

[Code]..

I verified that $row['state'] contains valid data by outputting it as HTML on the page (my test data outputs "MA"). And I'm reasonably sure that this used to work in the past.

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[Code]...

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[Code]...

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[Code]...

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_____
<script type="text/javascript">
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[code]....

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Apr 19, 2010

I am using a system called CMS Made Simple which has a quotes feature. This will generate a quote randomly from a MySQL database. To refer to this quote feature you have to use the {quote} tag which has a few parameters.

The parameter I am interested in is {quote group=""} because I want my users to be able to see a random quote from a group that they select through a dropdown list.

Head section:

Code:
<script type="text/javascript" src="path/to/jquery.js"></script>
{literal}
<script type="text/javascript">
$(document).ready(function(){

[Code]....

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<!DOCTYPE html PUBLIC "-W3CDTD XHTML 1.0 StrictEN"
"http:www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>

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Everything works beautifully except the Room and Board area. The code:

<?php
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Room and Board primaries

[Code]....

The Javascript portion works fine. The items display only when they are supposed to. However, the form fields within the Javascript affected areas are not passing values to the PHP form handling on submit.

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