What i want to do is populate a dropdown with data brought from mysql. However there is are two radio buttons i have which i want to choose what data the dropdown i populated with. This is the code i have so far. I don't have no js yet as my skill is php and mysql, not javascript. Code:
View 3 RepliesI want to populate a combobox with data pulled from a mysql db . The value of second combobox depends on what's been selected in first combobox. I assume pulling the data completely when loading the combobox and then filtering it locally to populate the second combobox based on the selection in first combobox will suit my needs so that i do not have to query server.What is the best way of doing it?
View 3 Replies View RelatedUsing Jquery I want to populate a 2nd dropdown from the choice of the first dropdown.
View 1 Replies View RelatedThe first dropdown has some options as :
abc(a)
bcd(a)
cde(b)
[Code]....
On selecting abc(a) in first dropdown the 'a' must get selected in second dropdown,on selecting cde(b) second dropdown must have 'b' and so on,also the second dropdown value should be disabled(grayed out) for user.Need the code in javascript.
[URL] Refer to the link, using the sample, I'm able to use php ajax to populate 1 text box which I've already pre-define (not using "echo '<input type='text'..") -- the info came from a table
e.g.
Search: [jo ]
Name: [John doe]
sql
---
select name from customer where name like '%jo%';
[Code]...
I am absolutely newbie to Ajax and I need to have this fixed by tomorrow as I have a project to complete so anyone
[Code]...
Below is the code I use to populate a textboxes (compaddress) when I select the compname from the dropdown. I would like to be able to populate other textboxes such as the compdescription, compmaincontact and others when I select the compname from the dropdown. I think that I need an array but I really would like some advice on how to do it as all of my attempts have failed so far
Code:
<script type="text/javascript">
function showname(what)
{
what.form.textfield.value=what.options[what.selectedIndex].title
}
window.onload=function() {
showname(document.form1.number)
}
[Code]...
I want to populate the right text box with the result of the drop down multiplied by the left text box. I'm able to do this already but with only one set. I want to be able to have multiple rows.
Here is the code I currently am using for the single.
Code:
$(function() {
$('#DropDownList1').click(function() {
$("input#TextBox1").val(
(
[Code]....
I have 2 dropdown list in my html. Is possible for me to populate the option values in the second dropdown list depend on what I select in the first one?
View 3 Replies View RelatedI am creating a site that has to do w/ pets. I want users to be able to select the type of pet they have from the first dropdown and then select from the second dropdown from choices dependant upon what they chose in the first dropdown.
So if they choose 'dog' as a pet type in the first drop down. I want the second drop down to display 'dog breeds'. If the choose 'cat' as a pet type I want the second drop down to display 'cat breeds'. This is what I have thus far.
My data table: Contains PetType(Column 1) and BreedType(Column 2)
My page form calls these two criteria Pet Type and Breed
I want to be able to insert this script into my form's HTML footer. Code:
I am trying to create a dropdown that selects mysql with php. For example I have two select dropdowns the first with types and second with products. So when the types select is click the products from that category are listed in the product select.
<select name="type" id="type">
<option value="1">Accessories</option>
<option value="2">Cables</option>
[code]....
I'm trying to make 3 drop downs (based off of mysql tables), to narrow down the selection. Source, School, and Program. So when when they select SOURCE(source), all the SCHOOLs in drop2 will be based on the SOURCE selected in the previous dropdown, and whatever school(cid) is selected, the program will be based off that school(cid) and display all the programs for that school. I've google'd high and low for something, and no avail. Here is what I have, I am just trying to make 3 drop downs narrow in, without pressing submit (I am new to ajax and javascript etc) The issue may be in that java part, I've look in the php and mysql, but nothing.
PHP Code:
<table width="517" border="1"> <tr>
<td width="87">Source:</td> <td width="414">
<? echo'<select name="source" onChange="showUser(this.value)">
<option value="">--Select--</option><?php while() { } ?>'; .....
My javascript
Code:
var xmlhttp;
function showUser(str){
xmlhttp=GetXmlHttpObject();
if (xmlhttp==null){
alert ("Browser does not support HTTP Request");
return;
} .....
Right now, the results display in a table, I don't want that - I need them to display as results in the next dropdown.
What I'm trying to do is auto populate the foreign key with help of dropdown box that contains names of clients so if i select a name from dropdown box a textfield above should populate with it's ID(primary key).
Code:
<td>Client ID : </td>
<td><input type="text" id="cl_id" name="cl_id" value="<?
$query = "SELECT * FROM client ";[code]......
This one should be easy. In fact, it was working for a long time as far as I know. Then I upgraded from jQuery 1.4.4 to 1.7.1 and a few things stopped working. (This is according to my client; it's possible it's been broken for a long time.)
So a customer logs in and sees his/her registration information. Name, address, phone number, etc... It gets this information from a MySQL database. For the customer's home address, there's a dropdown for the state (MA, NH, etc...) Rather than displaying the default specified in the HTML code, I have a bit of jQuery code that is supposed to change the dropdown selection to the user's home state as stored in the MySQL database.
Unfortunately, nothing happens. It rather than changing to the user's home state, it just displays the default state (AL, the first alphabetically).
[Code]..
I verified that $row['state'] contains valid data by outputting it as HTML on the page (my test data outputs "MA"). And I'm reasonably sure that this used to work in the past.
I have a mysql database (name) which helds 3 fields, id, naam, email. In php I've made the connection and create a selection menu and with javascript I was able to display, (when I selected for example "Bas" in the selection menu), bas his name into a first input text field. Now a couple of things I still want but can't seem to get it right.
First: I also want to display "bas" his email address in a second input text field. (the database contains more names, but this an example).
Second: The selection menu starts with the first name in the database, but can I make it for example "Select name" as beginning.
[Code]...
i have a form with fields (30+), and about 5 of them are fields that need to pass into my dropdown (actually a dynmaic dropdown, select SOURCE, then whatever source u select it'll show options that are mysql source=$source), so it can go into my mysql query, and filter out the best results. (i.e date_of_birth, min_credits, state, etc). Needs to be done without submitting, hence javascript. Im echo'ing my query and its saying the variables i'm trying to pass are UNDEFINED. Am I not passing the vars correctly? do i need to prep the vars to "grab" them in the current field?
[Code]...
I have a product select page that is really slow to use because 6 dropdowns must be populated and the page reloads after selecting each box, to get the options for the next box.
I want to speed it up as follows:
1) User selects one of 50 products from a dropdown list.
2) Page reloads, and all the possible options for the remaining 5 dropdown boxes are now populated (ie. list options all stored client side)
3) User can freely input the remaining 5 dropdowns without the page reloading.
Have a WAMP setup with Apache, PHP and Mysql service and I�m working on a HTML form which will have two drop-down controls where information is extracted from two tables in my DB.The first drop-down list called (name="sel_ControlArea") will decide what information the second drop-down list will have.So far I have managed to populate them when the page is loaded using PHP but run into problem when I make a change on the first drop-down list.Question one: What is the best/correct way to solve this problem?Is it to load all information into PHP arrays and then translate these to Javascript arrays, or should I go for AJAX, or XML or are there any other better ways ?I have tried to solve this using the first method, put data in a PHP array but run into problem with this data not properly loaded.This is first time for me to pose a question so please let me know if I have left out some important information or if I should describe this problem in a different way.
<table class="exemption" border="0" cellpadding="2"
cellspacing="5" bgcolor="#eeeeee">
<th colspan="2" align="center">Security Exemption Request</th>
[code]....
I have quite a few calls on my page at different points to populate dropdowns using jSon responses from the server. It is all working fine now apart from one issue. The name of the field that sets the value and text of the new Option(s) being put into the dropdown.
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I am populating a number of Select boxes on the server-side with a large number of options. I'd like to get the response size down without taxing the client browser too much. What do you think is the most efficient way to approach this problem?
Here are some considerations: The option text/values do not change very often, but could potentially change in the future. The page that holds the select boxes should never be cached, there are other aspects of the page that need to remain fresh. Firebug with YSlow is saying that the primed cache size of the page is 300Kb with all the select dropdowns and options, if I remove the options, the primed cache size of the page is 80Kb. I am considering breaking out the text/value pairs for the select boxes into a separate file that is cache-able calling it "valueTextPairs.js" and referencing it with a query string and some sort of server-generated MD5 hash of the data, so that if any of the values change, the client's cached version will be replaced by the latest version. Like so:[URL]...
Provided I do this, I anticipate that the primed cache size of the page will be reduced down to 80Kb (which I like) -- however, before I take the plunge, I am curious what you all think the performance effect will be?
I know the number of bytes on the wire will be reduced, but will this put a lot of additional pressure on the client's browser because I'd need to traverse the name/value pairs and add the options to the select boxes dynamically on the client end? If it seems reasonable to do this, what jQuery approach would be the most efficient? $('#selectId').html(options) with options = one big string? Adding each child option to the select in a loop? Something else?
Some client end folks are using IE6 so I am trying to tax the browser as little as possible, while also reducing the size of each request, trying to find a happy medium..
I've looked around and from what I can tell, the code seems right. Basically crating a JS array and passing PHP values to it to use in an onChange to fill a text field. The dropdown gets populated fine but the text field does not autopopulate onChange. I'm not too fluent with JS but have a good analytical mind and from what I can see, the logic seems right.
<?php
include('connectdb.php');
$CENTRE = $_SESSION['centreAFB'];
$qryFormList = mysql_query("SELECT * FROM tblLogin WHERE ACCT_TYPE = '2' AND loginCENTRE = '$CENTRE' ORDER BY loginNOM");
echo "<script type='text/javascript'> var formCourriel = new Array()";
while($resFormList = mysql_fetch_assoc($qryFormList))
[Code]....
how to populate checkboxes based on the dropdown menu selection
View 2 Replies View RelatedI need to create three dropdown boxes (box 1:colour, box 2: price, box 3:brand) and when the user presses "GO" they are returned with the correct information, pulled from corresponding fields in my MYSQL database.
For example, colour: silver, price £100-£200, brand:samsung...should return 5 items on the page. I do not need the dropdown boxes to populate depending on ther previous selection - they are static, so to speak. If possible, I would like the information to be retuned to my page without the URL changing, which leads me to think I will need to be ausing ajax....?
I am trying to populate data from an xml file when a certain catergory from the dropdown menu is selected. The dropdown menu is also populated from a xml source different from the one where the data is stored that needs to be pulled. so when a category is selected from the dropdown - the selected value will populate the data from the xml source. I am having trouble displaying the data when a category is selected from the drop down menu.
[Code]..
I created two drop downs, where the second one dynamically updates according to first selection. Now I jus have 2 members in first drop down and 20 in second drop down. I hard coded using javascript. But by the end of this year the number increases to 100's, then we cannot hard code it. I use html,javascript,jsp for the webpage. Is there a way to populate the dropdowns with data in a text file where they can update the text file with new members.
View 5 Replies View RelatedI have two drop-down fields that are populated separately from the database. Here is my HTML/PHP code
Drop-down field #1
<tr class=bodyTRstyle>
<td width="35%"><p align="left">Venue</td>
<td class=fieldTDstyle width="269"><p align="left">
<select name="VenueName" class=VenueName><option selected><?php echo $VenueName?></option
<?php
$SelectVenueQuery="select * from venue order by VenueName";
$SelectVenueResult=mysql_query($SelectVenueQuery);
while ($VenueRow=mysql_fetch_array($SelectVenueResult)){
extract($VenueRow);
echo "<option value='$VenueName'>$VenueName";}?>
</select></td></tr>
Drop-down Field #2
<tr class=bodyTRstyle>
<td width="35%"><p align="left">Results</td>
<td class=fieldTDstyle width="269"><p align="left">
<select name="GameResults" class=GameResults><option selected>
<?php echo $GameResults?></option
<?php
$ResultsQuery="select * from result order by ResultDate";
$ResultsQueryResult=mysql_query($ResultsQuery);
While ($ResultsRow=mysql_fetch_array($ResultsQueryResult)){
extract($ResultsRow);
echo "<option value='$ResultDate'>$ResultDate";}?>
</select></td></tr>
This code works well as long as the two drop-downs are independent of each other. The result table has VenueName as an element, so each venue has a set of result records in the result table. This is how I want to change it: The Venue dropdown will remain as it is. Once the Venue Name is selected I want the result dropdown to populate with ONLY the result records containing a match on VenueName that was selected in the venue dropdown. How do I do that? Is it with a onChange Event? What are the changes that need to be made? How do I communicate to the second drop-down what was selected in the Venue drop-down??