OnChange Event - Populate Dropdown Fields Separately From Database
Dec 17, 2011
I have two drop-down fields that are populated separately from the database. Here is my HTML/PHP code
Drop-down field #1
<tr class=bodyTRstyle>
<td width="35%"><p align="left">Venue</td>
<td class=fieldTDstyle width="269"><p align="left">
<select name="VenueName" class=VenueName><option selected><?php echo $VenueName?></option
<?php
$SelectVenueQuery="select * from venue order by VenueName";
$SelectVenueResult=mysql_query($SelectVenueQuery);
while ($VenueRow=mysql_fetch_array($SelectVenueResult)){
extract($VenueRow);
echo "<option value='$VenueName'>$VenueName";}?>
</select></td></tr>
Drop-down Field #2
<tr class=bodyTRstyle>
<td width="35%"><p align="left">Results</td>
<td class=fieldTDstyle width="269"><p align="left">
<select name="GameResults" class=GameResults><option selected>
<?php echo $GameResults?></option
<?php
$ResultsQuery="select * from result order by ResultDate";
$ResultsQueryResult=mysql_query($ResultsQuery);
While ($ResultsRow=mysql_fetch_array($ResultsQueryResult)){
extract($ResultsRow);
echo "<option value='$ResultDate'>$ResultDate";}?>
</select></td></tr>
This code works well as long as the two drop-downs are independent of each other. The result table has VenueName as an element, so each venue has a set of result records in the result table. This is how I want to change it: The Venue dropdown will remain as it is. Once the Venue Name is selected I want the result dropdown to populate with ONLY the result records containing a match on VenueName that was selected in the venue dropdown. How do I do that? Is it with a onChange Event? What are the changes that need to be made? How do I communicate to the second drop-down what was selected in the Venue drop-down??
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Mar 31, 2009
I have a situation where I need to populate form fields by grabbing information from a database when the user enters information in a specific field. I got this to work with a single field just to make sure I had the basics in place:
* User fills out "Field A" onchange event triggers Javascript function that uses Ajax to search and retrieve info from database (PHP/MySQL) Javascript function autofills "Field B" with Ajax response
Works perfectly. My trouble is that I need to do this with a whole series of fields at once, not just one. I tried using the PHP to output a Javascript array and then use the values from the array to populate the fields, but that didn't work. I got a message saying that my array was undefined. I'm not even sure this was the proper way to approach this, but it's all I could think of.
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<select id="mylist">
<option value="White">White</option>
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[code]....
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[Code]....
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Code:
<script type="text/javascript">
function showname(what)
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[Code]...
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Code:
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<?php
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function get_flagmastcountry_list($name, $selected = '', $parameters) {
[code].....
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Code:
$(function() {
$('#DropDownList1').click(function() {
$("input#TextBox1").val(
(
[Code]....
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Code:
<div class="coupon1">
<hr />
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cellspacing="5" bgcolor="#eeeeee">
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[code]....
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[Code]...
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<?php
include('connectdb.php');
$CENTRE = $_SESSION['centreAFB'];
$qryFormList = mysql_query("SELECT * FROM tblLogin WHERE ACCT_TYPE = '2' AND loginCENTRE = '$CENTRE' ORDER BY loginNOM");
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[Code]....
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