JQuery :: Animate And Click Together - When The User Clicks On The Div The Image Should Stay In The Hover Position
Jun 2, 2009
I've been looking for an "Ajax CMS" but decided to learn jQuery to learn how to code it myself in order to earn some geek-girl cred among my male colleagues. I've learn a lot about jQuery in a week but as you can imagine I still have a lot to learn.
I have successfully animated an image (move to the left and increase opacity) when the mouse hovers a div and reset the image (move it back to its original position and reset the opacity) when the mouse move outside the div. So far so good...
Here comes the question: What I need to do -and don't know how to - is when the user clicks on the div the image should stay in the hover position while still being able to hover any other divs and activate the animation normally.
When a different div is clicked the previous "Clicked" div should return (animate) to its original position and the new "Clicked" div should stay in the hover position. Content will be loaded when the divs are clicked but there won't be page refresh since I'm loading the content by using the load funtion of jQuery.
I am looking for a simple parallax/animate like effect, i have a single image and if i hover on it the image should move like the parallax effect. So if i put my mouse in the topleft corner the image should move in the direction bottomright. I know this i very simple but i cant seem to get it working or how to get this working.
I am trying to pop-up a window when the user clicks on an image. The problem is that when the user clicks on the image and the window pops up OK, but the window underneath also proceeds to the image. The desired behavior is that when the pop-up is invoked, I want the underlying window to stay put. Code:
when the user clicks on a thumbnail the image displays. I actually managed to make this work with just two images, but wasn't sure how to make the script work with, say 6 images. Anyway this is what I have so far:
HTML Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Gallery</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link href="style.css" rel="stylesheet" type="text/css" /> [Code]...
I have a chart (class="chart") that sits behind another graphic element and which only has a tab portion visible. What I need to happen is this: Click on the graphic -- the exposed tab part -- and it slides down an x amount of pixels. Click on it again, and it slides back up. I'm not using the toggle function, since as far as I know there is no way of preventing it from hiding the whole graphic, and I need a portion of it to show. What would I add to the code below to make this happen? Is there a better way to do this than how I've started it?
<form> <input type="button" value="Click here to see" onclick="window.open('http://www.yahoo.com')" />
I am building a page using a sort of tab format. You click a link and underneath it the text changes to suit the link. It all works great. But... I want the image link that they click to stay in the mouseover position. (The image changes from gray and black to white and blue) I want the image to stay white and blue.
I found this code sample that when a user clicks somewhere on the image, then an "X" will appear. I would like to have the "X"s remain visible even when the user clicks on a different area of the image. As you can imagine, a user clicks clicks clicks then there are "X"s everywhere. How do I do this? Do I need to create more "div" tags with the mouse click locations?
I am looking for a version of lightbox that would allow the user to click on a single reference image and when the "lightboxed" version appears a strip of thumbnails would be available at the top or bottom of that image. Thus, the user could navigate between images within the lightbox by clicking on a different thumbnail. If such beast exists a URL would appreciated. Extensive Googling hasn't turned up what I'm looking for at all.
I'm using jquery.animate() to scroll a certain DIV out of my screen at the top. Now I want that same DIV to fade out when it reaches a position which is 150px from the top (so before actually sliding off the screen). How do I achieve this? The code I have for the animation itself is as follows:
First of all, this is the first time that I use JQuery in my life. I have no idea of what I am doing. I have been following the following guide to animate a menu: [URL]... But as some of the people commenting on the guide I wanted the menu to animate with mouse over and mouse out. So I found the hover-function and the following comments on the guide:
I want to make 3 panel that functionally like we browse files in mac. I already suceed made 2 panel, the problem is, at the first load, the second panel already shown. I want it keep hide, until people clicked the button.
I have a horizontal menu with some subitems. At the moment when I click on the main menu the submenu is being shown and it remains open even if I click anywhere on the page. But here is the tricky part, when I click on a menu item (in the submenu) I want the submenu to display the items on which the page is.For example the menu looks like this:home
This is what I'm trying to do: I want a simple image container to swap the image inside it by clicking the nav buttons on the right like 1, 2, 3.Here's my code:
HTML Code HTML4Strict: <div id="item1"> <div class="img-container shadow" style="background-image:url(images/gallery/tcg1.jpg)">[code].....
My jQuery code is not right. I want it to turn off the "hover" class and the "show" class of the others when you click one. I think I need some kind of if..else? how to write it? I have a bg image set on the container div so there's an initial image to view.I also need multiple of these on the same page!
I want to do a simple animation where an image fades and expands at the same time. Works beautifully in chrome/safari etc but because of the IE opacity thing not IE. Can I use fadeIn() and get this to work at the same time as the animate()? or is there another solution?