Page To Start With An Image And Then Start The Rotation
Dec 22, 2010
I have found this nice background rotator:
Code:
<style>
body
{
/*Remove below line to make bgimage NOT fixed*/
background-color:black;
background-attachment:fixed;
background-repeat: no-repeat;
[Code]...
when i run it, i have to wait the 9000 timer to c the first image, and i need the page to start with an image and then start the rotation, i have assigned background-image by css, and tried also to use document.body.background, but when i do this the rotator doesnt work.
I'm using this tutorial to create a simple list of images that fade between each other.I can get it working fine following the instructions.However, i wonder if any genius's on here can tweak it so when the page loads it randomly picked image from the group and then carries on with its fades?Basically the image will be on a home page so each time you visit i want it to be a random image from the group and then fade through the rest..
I created that function for an image slider: $(document).ready(function(){ $("#gallery").click(function(){ $(this).find("li.third").fadeOut(800).removeClass("third").next().addClass("third").fadeIn(800); $(this).find("li.second").fadeOut(800).removeClass("second").next().addClass("second").fadeIn(800); $(this).find("li.first").next().addClass("first").fadeIn(800); $($(this).find("li.first")[0]).removeAttr("class").hide().appendTo($(this)).fadeIn(800); }); });
Actually I want to fade in the first picture first. Than the second and at the end the third. To achieve that I changed the order of these following three lines: $(this).find("li.first").next().addClass("first").fadeIn(800); $(this).find("li.second").fadeOut(800).removeClass("second").next().addClass("second").fadeIn(800); $(this).find("li.third").fadeOut(800).removeClass("third").next().addClass("third").fadeIn(800);Unfortunately it doesn't work.
I launched the following scripts but only the "Auto Start Page Rotator" page appeared.
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html><head> <meta content="text/html; charset=ISO-8859-1" http-equiv="content-type">
I found a script that puts a JavaScript countdown timer on a web page. The timer uses a PHP session so the timer does not reset until it reaches zero even if the user refreshes the page or leaves and comes back. When the timer reaches zero, the user is redirected to a different page.
The problem I have is when the user goes back to the timer page, after the redirect, the timer is still at zero and the user is immediately redirected again.
The timer does not restart until the user accesses the page for a second time.
If the redirect function is removed and you let the countdown go to zero, the page has to be refreshed twice to restart the countdown. I don't know if this is a PHP or JavaScript issue.
Can this be fixed so the countdown resets as soon as the user revisits the page after the redirect?
PHP Code:
<?php session_start(); if (!isset($_SESSION['endOfTimer'])){ $endOfTimer = time() + 10;
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I found some code on the 'net that loads images in sequence on each page load, but it only works with the current viewing session, and once the viewer leaves the site the last image they viewed is not kept and the sequence starts from the beginning instead of where they left off.
The code is below, but I can't figure out how to modify it to do what I want.
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var ermtext = response.match(/<START>(.*?)<END>/i); if (ermtext) { result.ermtext = ermtext.replace("$1");
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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head>
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