Repeating Blocks Into For Loop - Alert Never Show Up

May 14, 2010

I had some code that kept repeating itself over and over again, with the only variance being some named elements changing. All the named elements ended in a sequential number, so I figured I'd just put one of the repeating blocks into a "for" loop and then make that sequential number at the end of the named elements into the variable in the loop. Again, the code worked fine when copied/pasted over and over, but now it doesn't do anything. Here's one of the code snippets outside of the loop (which worked):

Code:
$(document).ready(function () {
$("#SelectDiv1").change(function() {
if ($("#DD1").val() != "0") {
$('#SelectDiv2').hide();
$('#SelectDiv3').hide();
$('#SelectDiv4').hide();
$('#SelectDiv2').show();
$.ajax({ .....

You can see there's an "alert" as the first part of the loop. That "alert" never shows up. However, if you comment out everything in the loop after the "alert", then the "alert" works. So something else in that loop is causing the whole thing to not work. I find it odd that the first "alert" wouldn't work, though, since it should be the first thing that happens before any of the other code is executed in the loop, right???

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