It is a beginners problem I'm sure but I'm making a menu and when hovered, the submenu appear. However, when moving the mouse the submenu keeps fading in and out a few times. Why? Can I stop the function from repeating itself over and over? [code]...
View 3 Repliesi am making a request using Ajax (JQuery) and it keeps repeating the request, it almost seems like it is inside a loop even though it is not inside a loop.
jQuery.ajax({
type: "GET",
cache: false,
url: "<?php echo Yii::app()->request->baseUrl; ?>/member/updatememberinfobox/query/",
[Code]..
var scrollSpeed = 1;
// Speed in milliseconds
var step = 1;
// How many pixels to move per step
[Code]....
My basic code is something like
<div class="insidepost">
paragraph 1
paragraph 2
[code].....
I have an xml with nested repeatingentries. I want to parse it using jquery, I have tried .find methodbut it ignores the child parent relation and consider all as child nodesI want to parse it inhierarchy like first it should show top level categories then if have nested categories and then if have products and so on.
<products>
<category>
<categoryid>2</categoryid>
[code].....
I have applied the fadeIn() and fadeOut() effects to a li>ul in my html, but if the user leaves the ul briefly then re-enters it before it has finished fading out, the ul fades back in again. This can happen many times over by accident and it's very annoying.
If the user leaves the ul I want it to fadeOut() and NOT fadeIn() again until the user re-enters the parent li element.Is there a way of ensuring this? I have done a quick search for while and if/then/else functions but haven't been getting anywhere. This is what I have, very simple indeed:
$(document).ready(function() {
$(".nav ul").hide();
$(".nav li.conductor").hover(function() {
[code]....
I'm using mouseenter and mouseleave to call a slideToggle on a dropdown menu. What's bothering me though is if my mouse moves in and out of the menu a few times before the toggle animation is complete and replays the open close a few times before stopping. [URL]... Is there a way to kill the queue so that it doesn't play if the mouse is not over it anymore?
View 2 Replies View Relatedeach time I hover on #demo, the piece of code below works, but it will not stop doing it even if I'm not on hover, it is like it will repeat the process all the times I hovered and didn't have time to repeat it.
$('#demo').hover(function () {
$(this).animate(
{ height: 40, paddingTop: "15px"},
[code]....
I want to repeat 3 .html file in every page of my site. (header.html, footer.html and navigation.html), I read something about php's include() function. but I like to use JQuery's .ajax() or get() function. How can I do that?
View 1 Replies View RelatedLet's put it this way.I have the following repeating DIVs:
<asp:TextBox ID="txtInsertComments" AutoPostBack="false" CssClass="expanding" runat="server" Width="400px" Text='<%# Bind("comments") %>' TextMode="MultiLine" />
<div id="commands" style="display: none;">
<table cellpadding="0" cellspacing="0" width="400px" id="tblCommands">
[Code].....
How do I use jQuery to determine which textbox control is being clicked and then show the div that relates to that TextBox? Again, both the textbox along with the div=command are all repeating. It could repeat more than just twice as showing in the example above. I need the jQuery to only show the div=command that the user has clicked on the TextBox for commenting.
Im using $.post and have a lot of repeating elements I need to post like the cat elements in the example code below.
I could use a loop in some way to add the repeating elements rather than listing them one by one.
$.post("save.php",{
id:$('#id').val(),
save:$('#submit').val(),
name:$('#name').val(),
[Code].....
I have a SharePoint page that is filled with the text string "12:00 AM" that I would like to remove, the underlying HTML is
<td class="ms-cal-workitem">
<table>
<tr>
<td class="ms-cal-monthitem">
[Code]....
I displaying mysql data in a webpage using div's and tables. Each row of data has 4 div's, and a certain style. The 4 div's will be repeated for each row of the query result. I want to repeat the style for each set of div's as they are created. I imagine this would/could be achieved using and array of style id's such as:
ID1a, ID1b, ID1c, ID1d
ID2a, ID2b, ID2c, ID2d
etc,
etc....
How can I create/repeat these style ID's as I create/repeat the div's?
I'm making a webpage for a school project and I need modifying this timer here: [URL]I want it to countdown from 48 hours, and as soon as it counts down, I need it to reset. I need an endless countdown of 48 hours.
View 37 Replies View RelatedI want to display 4 random images and I would like to get them to NOT repeat themselves. So if image one is randomly selected as "aceclubs.png" I don't want image two to be the same and so on for the other images. This currently the code I'm using right now. I've been duplicating this function with different names for each of the 4 images. However it sometimes produces two of the same image and I don't want that.
function random_ace(){
var cardace = new Array(4)
cardace[0] = "aceclubs.png";
cardace[1] = "acediamonds.png";
cardace[2] = "acehearts.png";
cardace[3] = "acespades.png";
var randomace = Math.floor(Math.random()*cardace.length);
var ace = cardace[randomace];
card1.src=ace
}
I've found this code elsewhere and am currently using it to load 5 random pages that automatically refresh to another in the array after 10 seconds. This works great. But is there a way of altering this code so it doesn't repeat any of the pages - atleast until it's displayed each page once?
At the moment it can display 'page5' 3 or 4 times before I even see 'page2' for example - which is annoying!. [code]...
I have an object that looks like this:
"Jan 2005 120"
"Jan 2005 123"
"Jan 2005 126"
"Jan 2005 128"
"Jan 2005 130"
"Jan 2005 132"
"Feb 2005 135"
"Feb 2005 143"
"Mar 2005 120"
"Mar 2005 123"
"Mar 2005 126"
"Jul 2005 128"
"Jul 2005 130"
I want to output:
Jan
Fed
Mar
Jul
How can i most efficiently accomplish this?
How would I go about repeating an entire program? I know it's a loop, not sure which one. I've tried a while loop.For example:
Q: Do you want to play a game of Rock, Paper, Scissors?
A: Yes -Program Runs-
Now, how would I have it ask if the user wants to play again?
Q: Do you want to play a game of Rock, Paper, Scissors?
A: Yes -Program Runs-
Q: Do you want to play again?
A: Yes -Program runs again-
Q: Do you want to play a game of Rock, Paper, Scissors?
A: Yes -Program Runs-
Q: Do you want to play again?
A: No -Program terminates-
Random non-repeating images script. You can see an example at [URL]. Refresh and you'll see the PS3 boxarts on the top left will show randomly, with no repeats.
In your html page
in head tag
<style>
img.boxart{
margin:0;
border: none;
display:block;
float:left}</style>
<script type="text/javascript" src="ps3boxart.js"></script>
In body tag (place whereever in the body you want the pictures to show)
<script type="text/javascript">
randomorder(ps3ba, '')
</script> .....
function randomorder(targetarray) {
var randomorder=new Array()
var the_one
var z=0
for (i=0;i<targetarray.length;i++)
randomorder[i]=i
while (z<targetarray.length) {
the_one=Math.floor(Math.random()*targetarray.length)
if (targetarray[the_one]!="_selected!"){
document.write(targetarray[the_one])
targetarray[the_one]="_selected!"
z++
}}}
Then obviously, you would use this as a baseline and change your .js file name to whatever your pictures are for, like ads.js or whichever. Change the links in ahref to whereever you want each page to link. Change the image locations in img src to whereever your images are saved. Remember, where it says var z=0... this is where you hide extra random images. For example, my 200px cell only fits 9 22px wide images (they equal 198px). I only have 9 in my ps3 boxart image folder. If I want 50 in there... I would upload the pics to the folder with the other ones, add them to the list in the .js file. Such as ps3ba[9]=, ps3ba[10]=, etc. up to [49] (49 + 1 for [0] = 50). Then since I can only fit 9 in my cell, I would have to change the variable to var z=41 (to hide 41 of them and only show 9).
I have a web page that contains a bunch of advertisements. What I need to do it randomly shuffle these images each time the page is refreshed. I cannot have any repeating ads.
View 5 Replies View RelatedI got this code and it generates random numbers but with repeating code...
View 3 Replies View RelatedI had some code that kept repeating itself over and over again, with the only variance being some named elements changing. All the named elements ended in a sequential number, so I figured I'd just put one of the repeating blocks into a "for" loop and then make that sequential number at the end of the named elements into the variable in the loop. Again, the code worked fine when copied/pasted over and over, but now it doesn't do anything. Here's one of the code snippets outside of the loop (which worked):
Code:
$(document).ready(function () {
$("#SelectDiv1").change(function() {
if ($("#DD1").val() != "0") {
$('#SelectDiv2').hide();
$('#SelectDiv3').hide();
$('#SelectDiv4').hide();
$('#SelectDiv2').show();
$.ajax({ .....
You can see there's an "alert" as the first part of the loop. That "alert" never shows up. However, if you comment out everything in the loop after the "alert", then the "alert" works. So something else in that loop is causing the whole thing to not work. I find it odd that the first "alert" wouldn't work, though, since it should be the first thing that happens before any of the other code is executed in the loop, right???
I'm using the script below in a custom HTML to generate a random line of text (not with the text shown here). This works fine BUT; I want it to go randomly through the WHOLE list without repeating lines that already have been printed. As it is now, a line of text might be printed several times in a row, which is a little annoying. I'm using a refresh button for generating a new line of text.
How can I just make it display in the order shown and just re-arrange the content so it seems random to the user? Random would the best though...
<script language="JavaScript">
<!--
var r_text = new Array ();
r_text[0] = "All the leaves are brown";
[Code]....
I am having a single row which repeat dynamically. My issue is i want to make alternate colors in rows. (i.e white n gray) I can put the class for the row. but when it repeats it get the same bg color. How can i do the alternate thing.?
View 5 Replies View RelatedI've hacked together a calculator, it features one row to begin with that accepts user inputs to specify height (from dropdown), width, depth, qty (text fields).It then performs a calculation (width+depth) * multiplier +12
The multiplier is defined by an IF based on the selected height.I want to add 10 or more rows which are identical, and then get a grand total for all the rows' totals added together.Where I am stuck is how to change the drawerPrice function to handle extra rows.I basically know nothing about js, this is a result of day 1.
Code JavaScript:
<script type = "text/javascript">
//<![CDATA[[code].....
I've looked for a solution to this issue, but it seems like a little different scenario than other situations. I made a system for generating friend requests on Facebook. I have a grid that is 6 x 3, for a total of 18 cells. Each cell has a picture in it, and the picture is linked to the Facebook friend request page. My problem is that since each cell is populated at random from the array, I'm getting lots of repeats. For example, some picutures are in 5 cells, and some are in none. I'm trying to figure out how to make it so that once a picture is used once in the grid, it does not get used again in the same grid.I still want every cell filled at random on each page load, I just want to prevent the repeating.
Here's my current code:
<script type="text/javascript">
var vip_list=new Array(
new Array('http://profile.ak.fbcdn.net/v225/1616/88/s1220771654_2158.jpg','http://www.facebook.com/addfriend.php?id=1220771654'),
new Array('http://profile.ak.fbcdn.net/v223/1233/29/s904885342_9055.jpg','http://www.facebook.com/addfriend.php?id=904885342'),
[Code]...