Make Result 2 Stay On Same Page?

Oct 2, 2010

When I hit the submit button, the result are display on a new page. how do I force it to stay on the same page, here's my code.

Code:

<HTML>
<HEAD>
<TITLE>Test Input</TITLE>

[code]....

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I got a page on which on the left side there is a Tree with branches, on the right side of the page i got an <EMBED> tag that shows a pdf file, User can click on tree branches to expand them and can click on the leafs to view different pdf in on the right side of the page...

The problem is that if a user expand several branches the tree grows down and than the user scrolls down the page. to click some leaf of the tree... and by doing the scroll the <EMBED> tag with the pdf becomes invisible (because the user scrolled up)..

how can i make the <EMBED> tag stay allways on top of the page even if the user scrolls down....?

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$(document).ready(function() {
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[Code]..

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I'm sure it will be php code that will enable me to complete the following:

print"<table border=1 FRAME=BOX CELLPADDING=2>";

print"<tr BGCOLOR=#0CADE4>";
print"<td width=&#3930;px'>";
print"<div class=white ALIGN=CENTER>";
print"<strong>Select</strong>";
print"</font>";
print"</div>";
print"</td>";

print"<td width=ï`px'>";
print"<div class=white ALIGN=CENTER>";
print"<strong>Casino Name</strong>";
print"</div>";
print"</td>";

print"<td width=&#3960;px'>";
print"<div class=white ALIGN=CENTER>";
print"<strong>Download <br> Software</strong>";
print"</div>";
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$username = "username";
$password = "password";
$database = "database";

#CONNECT TO MYSQL
$dbcnx = @mysql_connect('mysql5.streamline.net',$username,$password) or die("Unable to connect to MySQL");

#CONNECT TO DATABASE
@mysql_select_db($database) or die( "Unable to select database");

$result = mysql_query($sql);

if (!$result) { echo("<P>Error performing query: " . mysql_error() . "</P>"); exit(); }
$i = 0;

while ( $row = mysql_fetch_array($result) ) {

$i ++;
echo "<tr>";
echo "<td BORDERCOLOR=#9B9B9B ALIGN=CENTER>";
echo "<INPUT TYPE=checkbox NAME='" .$i. "' value=".$row['id']. ">";
echo "</td>";

echo "<td class=blue3 ALIGN=CENTER width=100px>";
echo "<div align=left>";
echo "<a href=" .$row['textlink']. " target='_blank'>";
echo $row["name"];
echo "</a>";
echo "</div>";
echo "</td>";

echo "<td class=blue3 ALIGN=CENTER>";

if ($row['downlandlink'] != &#390;'){
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echo "</a>";
}
echo "</td></tr>";

}
?>
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Because there are loads and loads of rows added to the table, when scrollong down the table, the header columns dissapear. Is there any way of making the header column always appear on the page when scrolling down to the bottom of the page?

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I have the following form that on submit launch a php script to upload a file.

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<input value="img/uploads/*.*" size="95" type="file" name="file" id="file" />
<br /><img class="skypebutton_submit_img" src="img/ClearGreenButton.png" />
<input type="submit" name="submit" value="Continue" class="skypebutton_submit" />
</form>

but the problem is that i need to stay on the actual page and the actual code i have send me to upload.php... witch is a script that displays nothing it just upload a file to the server.

Is there a way to run upload.php and stay on actual page? In other words run the form and stay on the actual page.

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// JavaScript Document
/* This script and many more are available free online at
The JavaScript Source :: http://javascript.internet.com

[code]....

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Mar 18, 2010

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(benalman.com/code/projects/jquery-bbq/)
bldd.nl/stackoverflow/pagination/indexBBQAjax2.php
bldd.nl/stackoverflow/pagination/indexBBQAjax3.php

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[Code]...

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Display Result On Same Page?

Oct 2, 2010

When I hit the submit button, the result are display on a new page. how do I force it to stay on the same page, here's my code.

Code:

<HTML>
<HEAD>
<TITLE>Test Input</TITLE>
<script type="text/javascript">

[Code]......

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Dec 27, 2011

I'm far from a JQ guru but I built a page using two plug ins (slides and pagination) If I run just the pagination plug in ( for the images thumbnails ) and the slides plug in ( WITHOUT) the function code both seem to work OK. But I need the slide function code for the slides plug in to rotate the images as well and when I do this I get a grey area displaying the image numbers in between the div containing the slide and the footer, rendering the thumbnails not to work as well as the footer pop up menu does not function either see links below

http:[url]....

slides - images display fine / thumbnails work ( no function for rotating slides )
viewport / footer - working
http://dagwaremedia.com/ScotchSodaFiles/index.htm
slides - images display fine / rotating images work ( with function for rotating slides )
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why all of these plug ins do not work all together on this page?

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javascript:q = "" + (window.getSelection ? window.getSelection() :
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document.selection.createRange().text);
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Jan 29, 2010

I have a page A with form:

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this form look up some holiday destination which appears on this page with url: [URL] Now, I dont want to display result on this page, but on page B, in iframe.I found a way how to redirect output as a link to properly show in iframe on page B.

Page A contains:

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[code]....

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Hit The Submit Button, The Result Are Display On A New Page?

Oct 2, 2010

When I hit the submit button, the result are display on a new page. how do I force it to stay on the same page, here's my code.

[Code]....

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I am using Javascript to display options in a form with 2 dropdown lists. However, despite using the target='_self', the result opens in a new window.

// JavaScript Document
function setOptions(chosen) {
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[code]....

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This is my code :
-------------
on Head
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/iframe.js"></script>
on Body

[Code]....

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