I have been working on this issue for a couple of days. I have image names stored in my mysq. database. I need to somehow get those image names from the mysql database to a jquery array.Here is what I have so far.
<style type="text/css" media="all">
.frame {
border:solid 1px #00F;[code].....
I am loading a phph mysql result set into a div via jquery load. In ff, chrome, everything but ie7 it works fine. in ie7 it only returns one result when it should return many. This is the js im using:
Code:
The page if anyone would like to view is:[url]
I am not a javascript programmer, however are checking as I would like to investigate if I can do following:
I have a calculator that check the price for the properties for a choosen date, I use php and mysql to get the result and the result are displayed on the same page refreshing the page using this in the form: action="<?=$_SERVER['SCRIPT_NAME']?>#formdestination">
I know you can print the result using ajax or other javascripts to do this without having to refresh the page and jump to the result.
Was doing a research and I quckly found this link:[URL]..It does not look so complicated, however as I can see the form is done in javascript so I suppose if you have javascript disabled you cant use the calculator.
I would like to have a non javascript solution with the way I am doing it to work if javascript is disabled. An exampel of the calculator can be viewed on this link for exampel:[URL]..
Does anyone know how to set a javascript variable as a query result from a MySQL database.
As an example, like this:
Set this query:
I just can't do it. I've tried doing it like this:
But the thing stops my <body onLoad=""> function from working. I'm no expert in Javascript.
I am absolutely newbie to Ajax and I need to have this fixed by tomorrow as I have a project to complete so anyone
[Code]...
This is the first question I couldn't find answered by Google! No doubt the answer is out there, but...
So I have a function that is being passed an array of nodes: some of them plain vanilla DOM nodes, (say, those created by document.createElement), others are jQuery nodes (say $("<div></div>").
What's the best way to determine if a node is of each type? I can obviously look at the node contents, but I wondered if there was a "best practices" here?
I have a form on a web page, with one field to enter a code, to search for a property.On clicking 'submit' I want to be able to run a script asynchronously in the background.The script will need to run a MYSQL statement which will have one of these results:
1. The property code does not exist, so display a Javascript Alert saying it does not exist.
2. The property is for sale, so call an existing javscript function 'saleSubmit(propertyCode)' to overwrite the exsiting web page with a new page sale.php for that property code
3. The property is for rent, so call an existing javscript function 'rentSubmit(propertyCode)' to overwrite the exsiting web page with a new page rent.php for that property code
My slills are in PHP and MySQL and I have no knowledge of tools like Ajax, jQuery and I am currently having problems getting my head around it. I have spent ages visiting lots of websites looking for examples on how to do this with little success.
Your table-driven application has a MySQL table on the server side and you want a Javascript associative array on the client side to do rapid look-ups.For example: My application uses the value selected from the form’s drop-down menu to choose which other form fields to hide or show. This choice of a 'Long Form' is table-driven from product data in a MySQL table.
Convert the MySQL table to an associative array in JavaScript.I am using the jQuery library to manage the presentation and form validation on the client side and PHP and MySQL on the server side.Since a JavaScript Object is an associative array and the MySQL table is being used as a look-up table (associative array) I use the PHP function json_encode to create a JSON string - JSON is JavaScript Object Notation - on the server which is then evaluated as a JavaScript Object on the client. The two parts (server and client) of the code are listed below.All very straightforward then. So why the blog?This is what I do (here's the PHP code):
do { $key = $row['ProductKind'];
$value = ($row['LongForm'] ? True : False);
$arr[$key] = $value;
[code]...
As a newcomer to jQuery this is a good opportunity to show my appreciation to John Resig and the people that have contributed to the jQuery library ... not forgetting those who have integrated all the MySQL and JSON stuff into PHP. It's all very neat ... when you get to understand it!You could just eval(data) to turn the JSON string into a JavaScript Object (a.k.a. associative array), but JSON.parse protects your code against evaluating malicious scripts that could be embedded in the JSON string. This function is found in the json2.js downloadable until included in native browser JavaScript engines.The PHP Booleans translate automatically into JavaScript Boolean types.
[Skip this: My application has a MySQL table of product categories that tell me whether I need to present the administrator with a long form or a short form in the HTML. So, as products are added over time, I want to the administrator to choose whether a new product category can take the short form plus some default values or will require the explicit input of all product values in the long form. As the administrator assigns a category to a new product - and changes his mind half a dozen times - I don’t want to keep on going to the server to do the look-up but want to have the table in Javascript to keep the form presentation responsive. Also, the MySQL tables are on a third party’s server remote from the web server.]
Im trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear).
However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that thisblank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably.
I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
I found this---but havent figured out how to implement it in my scenario:
I found this---but havent figured out how to implement it in my scenario:
Code:
Source: [url]
I am trying to match a passed parameter on a url to an area on an image map. So far I can find the correct area using
Code:
$('#mediummap area').each(function(i){
href = $(this).attr('href');
if (href == id) {
alert('Found ID ' + id);
}});}});
But next I need to retrieve the co-ordinates for the Area. I have tried
Code:
coords = $('this').attr('coords');
And
Code:
coords = $('this').coords();
I can not seem to get the value back, just an undefined return. What I want to do is to find the point on the image map and then centre that point with in the viewport for the image (large image, small viewport).
i am using the jquery multi day-plugin ([URL] and have a problem with inArray. here is my code
var arr = ['10.11.2010','11.11.2010'];
if ($.inArray(
[day.getDate(), (day.getMonth() + 1), day.getFullYear()].join('.'),
[code]....
[code]My problem is simply that i have say 5 columns in the database placing the jquery script in that section allows that to be on each and every post. That works fine. the problem is though only the first one works the rest do not. It simply just doesn't have any action while the first one works fine.
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<head>
<title>Variable - Examples 1</title>
[code]....
How do i use a function to find the average of the values in an array of numbers passed as argument to a function.(using java script) thank you for your help...
View 1 Replies View Relatedhow would i build a multidimensional array? would it be: PHP Code:
var rinksAndPriceArray = new Array();
rinksAndPriceArray[0] = new Array();
rinksAndPriceArray[1] = new Array();
i've figured that out so far.
now, i want to be able to access a part of one of the arrays based on a variable that is passed into the function
the variable i'll send in will be the first part of the array ex: rinksAndPriceArray[0][0] and i'll want to return the rinksAndPriceArray[0][1] value.
I have a series of links in a list.And by an onmouseover event I want to get a message <li> with an explaination between the last link and the previous one.
View 2 Replies View Relatedhow can I insert data from mysql table into a javascript array?
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The Problem
---------------------------------
I have made the following structure which uses Dynamic Object Module (DOM) to
add/remove a field on the page which works perfectly fine.
I have a database whose structure contains tag,date and ip as field.
Now I want to send whatever data has been written on the tags field to be
stored in the database in the tag field of the db.
I read on a forum to use implode function or serialze function and then post
the data (which is combined) to the database.
I didnot understand how to use the implode function WITH REFERENCE TO THE GIVEN TASK.
I am storing whatever the contatenated data from all the tags fields (the no. depends
on the click on add button) in a variable 'tag'
And I want all the individual data of the field using DOM in variable tagarray.
Please tell me what will be relationship between the tag and arraytag so all the
array of tags field are concatenated and stored in tag variable.
How do I define the index of tag array and the the variable tag. Code:
I have the following code ...
This is a small piece of code from an Information Scroller I'm using as a news ticker. I have the title of each News Article in a MySQL table. What I need help with is how to take each article's title from the database and place each one into the array above. I'd be happy to clarify if you don't understand what I'm asking.
I have an mysql array with several radio buttons,
I want to make a button validation:
For some reason when I have more that one button in the array only the first counts, meaning only when first is clicked is the button validation checked=true.[/quote]
I'm trying to create two array's on this page: [URL]
Both array's would be activated by clicking their respective links -- the "I've got more to say" graphic would activate the text array in the bubble.
The "Meet my friends" graphic would activate the image array that changes the picture of the celebrities (ignore the terrible formatting of the 2nd pic).
I'm going to have a relatively large amount of text array variables and probably 5-10 image array variables.
Currently, the meet my friends button changes one image, but then it won't change back and is basically broken. The text array is currently activated by refreshing the page and I can't get that button to work at all.
I have put together an image gallery that contains links to each individual image, however, I would like to link to individual images on a separate html document and cannot for the life of me determine how to go about doing this.
rnmix
Code:
<html>
<head>
<script type="text/javascript">
[Code]....
I'm wondering if anyone would be most kind as to give me a few pointers on the subject of arrays! I'm trying to create an array of an unspecified length, the length is based on the result of another task that is performed in my code:
I am running through a MySQL database using PHP and extracting all of the makes of cars in that database and trying to create a JavaScript array named after each make. Then I am trying to fill each array will all of the models for that make. When I just try to display each Make and Model in an alert box it seems to come up right. And my arrays seem to be getting created but they won't populate with the models (even though my alert msg shows the loops and everything is working).
PHP Code:
while ($row = mysql_fetch_array($result)) {
$i=0;
//Used so each model is added to the array starting at 0 and ++
$make = $row['make'];//PHP var used to extract data from MySQL
[Code]....
Haven't used JavaScript since a college class a couple of years ago and haven't used it in the real world for even longer. Never with PHP like this. But I am working on this marketing site and need to be able to list products by type according to each brand and as they can be added to a MySQL database it needs to be dynamic. I have the whole thing working by stepping through separate pages using PHP to populate select fields with the data but I want to be able to dynamically add the content to select field using JavaScript so it can all be done on one page and thought that if I could create these arrays on page load then the right information could be selected client side.
I'm far from a JQ guru but I built a page using two plug ins (slides and pagination) If I run just the pagination plug in ( for the images thumbnails ) and the slides plug in ( WITHOUT) the function code both seem to work OK. But I need the slide function code for the slides plug in to rotate the images as well and when I do this I get a grey area displaying the image numbers in between the div containing the slide and the footer, rendering the thumbnails not to work as well as the footer pop up menu does not function either see links below
http:[url]....
slides - images display fine / thumbnails work ( no function for rotating slides )
viewport / footer - working
http://dagwaremedia.com/ScotchSodaFiles/index.htm
slides - images display fine / rotating images work ( with function for rotating slides )
thumbnails DO NOT WORK
viewport - DOES NOT WORK.
why all of these plug ins do not work all together on this page?
need urgent help with javascript arrays. I need to store the checked value of the radiobutton into an array and then display the result from that array.I have created an empty array to store the input from the textbox of the form using the JS insert() function and then used show() function to display the result... but I am unable to display which option the user has selected from the radiobutton.if you look at it in the browser, and type in a name in the name textbox and click submit....it displays the result (which was stored in the inputarray) but the radiobutton doesnt work...gives.."undefined" and should give either Male or Female, depending on what the user selects.
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