I have an mysql array with several radio buttons,
I want to make a button validation:
For some reason when I have more that one button in the array only the first counts, meaning only when first is clicked is the button validation checked=true.[/quote]
I'm trying to get a radio button validation for different sets of radio buttons that simply contains Yes & No buttons.
Here's what I'm trying to do:
Question 1: if Yes, then (Alert 1) if No, then (Alert 2) (if Yes, then Question 2 appears) *Up to here I'm happy- can't figure out the rest*
Question 2: if Yes, then (Alert 1) if No, then (Alert 2) (if Yes, then Question 3 appears)
I need the Alerts to be swapped from this point*
Question 3: if Yes, then (Alert 2) if No, then (Alert 1) (if NO, then Question 4 appears)
Identical for Question 5, and for Last Question 6 Alerts swapped back again.)
Here's the script that I managed to piece together:
i'm running a validation script to check if my radio buttons are selected, but i can't seem to get it to read the value of the field.
heres my form
<form name="cases" action="cases_process.php" method="post" onsubmit="return validate(this)">
<input name="uscan" id="uscan" value="n" checked="checked" type="hidden" />
<input type="radio" name="uscan" id="uscan" value="us" class="radial" tabindex="1" /><label>United States</label>
[Code]....
everything works up until the if(uscan == "n") so idk why it cant find what the value of the field is, because ive tested it and it seems to know even know what the value is.
In "validateField" function radio is not exists and I don't know how can I add a validation rule for radio buttons. My code is attached.
View 1 Replies View RelatedSo i have a form that has 3 radio buttons and i want to validate so that you must select at least 2 Yes's. I am new to javascript so excuse my poorly written statement. It is non-functional, how to change this in order to make it functional.
Code:
How do i begin a validation script for a form with radio buttons & check box & text area.
View 2 Replies View RelatedI'm trying to create a questionnaire style series of radio buttons which are hidden and then a different set of radio buttons displayed depending on the previous answer. eg
Q1 Is it a man? (if select yes then display)
Q2 Is he called John? (if no then display)
Q3 Is he called Gary? and so on...
I've been testing using the code below but wondered if anyone had any ideas on how this could be done easily?
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Is there any way to prevent the onclick event from triggering if the radio button is already checked?
I have 3 radio buttons with the same name ("myradio"). The value of each is a different URL (eg. value="http:[url]...)I have a link underneath these (<a href="#">Send</a>). I would like the selected radio button's value to be inserted into the href of the link, and if the user selects a different radio button that this changes.
View 1 Replies View RelatedI have a form with 4 radio buttons, the scenario is, when a user click on a radio button a hidden content will be displayed and the other three radio buttons will be disabled so that at one time a user can only click and view single radio button and the hidden content.Here is my code to show hide the hidden content but i need when the user select one radio button the other radio buttons should disable.
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />[code]......
what i need to do to add all the radio botton and check box. i already finish the add formula on the checkbox but i do not know how to add the two selected radio buttons to my checkbox buttons.for example:
O selected is 80
O 60
O 60
O selected is 15
O 15
O 25[code].....
I have a form with multiple fieldsets which are visible conditionally. There are three submit buttons "Abandon", "Save" and "Save & Continue". Each button should validate specific controls of the form and submit it. I tried setting "onsubmit: false" and checking for "$('#myForm').valid ()" on click of these buttons., but that validates all controls of the form.
View 1 Replies View RelatedI want my radio buttons to become submit buttons as well. So when a user clicks on a radio button it submits the action and refreshes the page accordingly. As of now using only using onclick="this.form.submit()" the page only refreshes with no change. Here is a copy of the entire form. It is a custom shipping options form (I did not create it).
<!-- Custom shipping form -->
<form action="" method="post" name="update_shipping">
<table width="300">
<tr>
<td><label>
<input <?php if (!(strcmp($_SESSION['shippingmethod'],"1"))) {echo "checked="checked"";} ?>
[Code]...
Ajax and jQuery is something I'm new to, but PHP, Javascript, and MySQL I'm pretty well seasoned with.For starters, I want to create a simple form where there are these fields:Name (text field)E-mail (text feld)Zip Code (text field)Cell Phone Number (text field)Phone Carrier (dropdown menu)Thing is, I want to check the database to see if an e-mail address has already been entered. I'd like for that to happen after they enter the email address and tab or click out of the e-mail text field. For instance, after they enter an e-mail address and tab to the Zip Code field, the script queries the database to see if that e-mail exists already. If it does, it notifies the user and greys out the submit button. If not, they're allowed to finish filling the form out and submit. It'll be a huge time saver if this Ajax script is in place.
View 1 Replies View RelatedI am trying to use the jquery radio buttons and everything looks well until I press the submit button.What is passed on in my POST variable for the radio buttons is the string "on" and not at all the name of the button. All of the buttons just returns "on".[URL]
View 3 Replies View Relatedhow can I insert data from mysql table into a javascript array?
View 5 Replies View Related---------------------------------
The Problem
---------------------------------
I have made the following structure which uses Dynamic Object Module (DOM) to
add/remove a field on the page which works perfectly fine.
I have a database whose structure contains tag,date and ip as field.
Now I want to send whatever data has been written on the tags field to be
stored in the database in the tag field of the db.
I read on a forum to use implode function or serialze function and then post
the data (which is combined) to the database.
I didnot understand how to use the implode function WITH REFERENCE TO THE GIVEN TASK.
I am storing whatever the contatenated data from all the tags fields (the no. depends
on the click on add button) in a variable 'tag'
And I want all the individual data of the field using DOM in variable tagarray.
Please tell me what will be relationship between the tag and arraytag so all the
array of tags field are concatenated and stored in tag variable.
How do I define the index of tag array and the the variable tag. Code:
Your table-driven application has a MySQL table on the server side and you want a Javascript associative array on the client side to do rapid look-ups.For example: My application uses the value selected from the form’s drop-down menu to choose which other form fields to hide or show. This choice of a 'Long Form' is table-driven from product data in a MySQL table.
Convert the MySQL table to an associative array in JavaScript.I am using the jQuery library to manage the presentation and form validation on the client side and PHP and MySQL on the server side.Since a JavaScript Object is an associative array and the MySQL table is being used as a look-up table (associative array) I use the PHP function json_encode to create a JSON string - JSON is JavaScript Object Notation - on the server which is then evaluated as a JavaScript Object on the client. The two parts (server and client) of the code are listed below.All very straightforward then. So why the blog?This is what I do (here's the PHP code):
do { $key = $row['ProductKind'];
$value = ($row['LongForm'] ? True : False);
$arr[$key] = $value;
[code]...
As a newcomer to jQuery this is a good opportunity to show my appreciation to John Resig and the people that have contributed to the jQuery library ... not forgetting those who have integrated all the MySQL and JSON stuff into PHP. It's all very neat ... when you get to understand it!You could just eval(data) to turn the JSON string into a JavaScript Object (a.k.a. associative array), but JSON.parse protects your code against evaluating malicious scripts that could be embedded in the JSON string. This function is found in the json2.js downloadable until included in native browser JavaScript engines.The PHP Booleans translate automatically into JavaScript Boolean types.
[Skip this: My application has a MySQL table of product categories that tell me whether I need to present the administrator with a long form or a short form in the HTML. So, as products are added over time, I want to the administrator to choose whether a new product category can take the short form plus some default values or will require the explicit input of all product values in the long form. As the administrator assigns a category to a new product - and changes his mind half a dozen times - I don’t want to keep on going to the server to do the look-up but want to have the table in Javascript to keep the form presentation responsive. Also, the MySQL tables are on a third party’s server remote from the web server.]
I have the following code ...
This is a small piece of code from an Information Scroller I'm using as a news ticker. I have the title of each News Article in a MySQL table. What I need help with is how to take each article's title from the database and place each one into the array above. I'd be happy to clarify if you don't understand what I'm asking.
I am running through a MySQL database using PHP and extracting all of the makes of cars in that database and trying to create a JavaScript array named after each make. Then I am trying to fill each array will all of the models for that make. When I just try to display each Make and Model in an alert box it seems to come up right. And my arrays seem to be getting created but they won't populate with the models (even though my alert msg shows the loops and everything is working).
PHP Code:
while ($row = mysql_fetch_array($result)) {
$i=0;
//Used so each model is added to the array starting at 0 and ++
$make = $row['make'];//PHP var used to extract data from MySQL
[Code]....
Haven't used JavaScript since a college class a couple of years ago and haven't used it in the real world for even longer. Never with PHP like this. But I am working on this marketing site and need to be able to list products by type according to each brand and as they can be added to a MySQL database it needs to be dynamic. I have the whole thing working by stepping through separate pages using PHP to populate select fields with the data but I want to be able to dynamically add the content to select field using JavaScript so it can all be done on one page and thought that if I could create these arrays on page load then the right information could be selected client side.
I have been working on this issue for a couple of days. I have image names stored in my mysq. database. I need to somehow get those image names from the mysql database to a jquery array.Here is what I have so far.
<style type="text/css" media="all">
.frame {
border:solid 1px #00F;[code].....
[code]My problem is simply that i have say 5 columns in the database placing the jquery script in that section allows that to be on each and every post. That works fine. the problem is though only the first one works the rest do not. It simply just doesn't have any action while the first one works fine.
View 1 Replies View RelatedI've seen several messages in this group with this question and no reply.
Simply stated, how do you send the status of a group of radio buttons to
a JavaScript function? I have a large project that needs this. Since I
cannot figure it out, I wrote a small page to experiment with it. Here
it is....
i have a list of 10 radio buttons all with the same ID=R100 i need a javascript to select (checked) say the 4th radio button AFTER the form is created.
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