i was using $.ajax method to get my ajax page on my main page,which is working great.But now if i have links in that ajax page then i can't open them in that same div,the links are opening in new window,but i want to open in same part,i tried google it and then found, i have to use iframe instead of div.how to do with only use jquery and div.
View 3 RepliesI would like to achieve such thing, as to load some part of other page, like this:
$("#content").load("example.com/main.htm #content > div");
but I need to do a beforeSend callback, to fade out the current content, wait until it is fully hidden, and only then fade in with the received ajax request. But doing this, for example, with .ajaxSend, the content loads much quicker, then fadeOut is complete.
I am currently programming Script Adds data to the database but if i want to Shown the data that have been added Requires refresh the page to show the Data that have been added . and I do not want this method.I want to when adding data to show updates as soon as the addition of data.This can be done by Ajax , and An example of this method used Google Gmail.
View 3 Replies View RelatedI tried finding a similar situation in the forums, but was unable to discover anything sepcific. I think I may be way off here, and or trying to do something bizarre, but what I am trying to do is change only part of the the url for all of the links on a page. So say I want to change:
href="/something/something/all"
to
href="/something/something/specific"
I think I need to use each() in combination with attr but I am not exactly sure how. This is what I have so far (with no luck):
$('a').each( {
$(this).attr('href').replace('all','specific');
});
I've successfully changed part of a single link based of it's enclosing div id, but if there is more than one link in the div, it replaces the entire href of all the other links in that div to be the same as the first one. So that's why I think I need to use each(). But again, I'm not sure how to do this properly in this case.
I have an ajax script which loads new content onto the page when the main navigation links is clicked. I also have a jquery script which fades divs in and out when another subset of links are clicked.
I guess these scripts essentially do the same thing but the first basically is loading in 'pages' without the page having to refresh. The second is just fading in and out divs that are on a page.
The problem is is that the second script only seems to work once, when the page is loaded.
Here they are:
I'll admit to being a newbie with JQuery, XML and Ajax. I'm trying to create a page which pulls dynamic links from an XML file. Here is the page: [URL] Here is the link to the xml file: [URL] I can get the url to pull as text, but I cannot make it into a link, no matter what I seem to try. I'm sure it's a syntax error - but I just don't know enough to know what it is. I'm also going to need to pull a URL for an image, and I am guessing that the process is similar.
View 2 Replies View Relatedon the top of the page with the pictures scrolling with news and links inside of them without using flash. like with ajax or something? and if it can be done... how would i go about it?
View 2 Replies View RelatedWhen you load part of pageB with ajax into pageA, what happen with the head section (title, meta, css link and script link...)
I mean, what is the best practice when you insert into the DOM a part of pageB with all the code (title, meta, etc...) that is associated with pageB. (initially i was inserting the whole pageB because of "gracefull degradation", but this inserts the whole pageB DOM into the pageA DOM).
I want to develop a multi-tab browser plugin, which requires all links in a page could open in new tabs within this multi-tab browser plugin. It's very similar to Multi-Tab functions of Firefox/IE, when opening a page in one tab, then any links in that Tab will open in another new tab(after setup from pref), i want to know this principle(how to implement this). I am thinking try this:$('a').click(...), while i am not sure whether it's good/enough.
View 5 Replies View RelatedIn my browser, I make an AJAX request. The server sends me a fragment
of an HTML document. That fragment has some JavaScript inside some
script tags. How do I run these scripts when the fragment arrives at
the browser?
I'm trying to come up with what is probably a kludge. What I'd like to do is take the responseText from an AJAX request -- which will be a full HTML page -- and parse it first to find if there is a <form>...</form> in it. If not I'll display a success message and all is fine, but if it's there, then I want to extract just that form section and display it within a <div> in the page.
This is where my JS skills are failing me. Can anyone point me to the applicable functions, tutorial, or whatever that would show me how to find the <form> and extract it and then replace my div contents with it (just innerHTML?).
I'm creating an AJAX page that is built using a PHP Class, ie the php looks a bit like this: PHP Code:
$wp_page->addjs('../var/savepolicies.js')
$wp_parser->page = "userpolicywindow.php";
$wp_parser->addlink("Home","../index.php","");
$wp_parser->addlink("Logout","javascript:logout();","");
$wp_parser->getpageid("501");
[Code]...
within this page that has been created, there is an AJAX tree folder which calls another page to be loaded into a DIV by AJAX again. Code:
[Code]...
I don't know why it doesn't work because the page has been loaded with the JS file, but as soon as the link is added afterwards it doesn't work. I take it this is because it doesn't know where to find the JS, but how can I overcome this?
Tabs jQuery v2.7.4 of stilbuero. I want to use Ajax Mode and open the links in a specifically container. For example:
<div id="box">
<ul id="tabs">
<li><a href="01.html"><span>Tab one</span></a></li>
<li><a href="02.html"><span>Tab two</span></a></li>
<li><a href="03.html"><span>Tab three</span></a></li>
</ul></div>
...
<div id="container"></div><!-- Open external links here (01.html, 02.html and 03.html) -->
I'm using jquery/ajax to create some links with window.open method. Here's the relevant code:
$("#content").empty();
$.ajax({
type: "GET",[code]..........
Basically, when you click a link a function is called with a parameter based on the particular link you run. Then the code runs through an xml file, and if the parent of the nodes I've cyling through has a value equal to the parameter past to the function, that node is used to create a new link with window.open function attached to it.It all works, or seems to, and when I alert what is being built, it looks right to me, yet the links don't work.I've attached a copy of one of the alerts of one of the links as it's built.
I´ve gone thru a few exaples of the 'hello world' equivalent for ajax; the classic example having main.html with div id="main_panel", then having ON THE SAME folder of the main.html file, the few files for getting via ajax and then render it´s content inside div id=main_panel and so on, happy with that;my question is: All of those examples, always get those 'few files', lets say, one.html, two.html, and so, in the same folder where main.html resides; I want to achieve to have the 'some files' in a different folder, let´s say, /editors/ relative to the path where main.html is; I´ve done this, the ajax call works fine; the PROBLEM is that the xmlhttpresponse (consumed ajax text) wich is basically html 4, changes the links (hrefs) in those to the path of main, let´s say, for example, one.html has a link that points to itself, not an anchor, just a link pointing to itself as we often use for pagination of a grid, well, that link href attribute is changed to the path of the main.html file, and not preserving the original href attribute... why? where should I start from? changing the context parametere prior to calling ajax get?
View 1 Replies View RelatedBeen trying to get this working for a while now, and I keep getting the error 'ajaxpage is not defined' Code copied from Dynamic Drive
[Code]....
At the moment I have a link in a div that targets an ASP page to remove an item from the database.
<a class="small" href="/products.asp?Action=RemoveProduct&ID=<%=(rsCartItems.Fields.Item("ID").Value)%>">remove</a>
What I could like to do is use JQuery .click and .ajaxmethods but the only thing I am unsure of is hot to get the ID of the a href tag containing the unique item ID that relates to the db record. Can I use this.id?
<script>
$(document).ready(function
(){
$(".removecartitem"
[Code]....
I have a page whit many links ( for example a Dictionary ) ,I want all links in this page open in the special window size whitout scroll ,statusbar,toolbar,.....
I have script for one link but I want a one code for all links or the script which I can insert in head of main page for all links .
I am trying to open some SWF videos from an HTML page. When the user clicks the link, I would like to have the videos open in a transparent window (not a separate browser wndow).
I have figured out how to embed the files and have them open in a transparent window as soon as you load/refresh the page but I want to open the SWF using a link.
On a webpage, I have a table (generated on page load through php/html) on the side that has several links (one on each row), and when you click any of them it calls a javascript function (href='javascript:newtable()') that uses an ajax requests to populate the table again (performed by a php file echoing an html table that is placed into a div innerHTML on the page), this time with new items and links on each row/cell. In this second table, none of the javascript links or buttons work after the first row.
For whatever reason, after calling consecutive ajax requests to re-populate an HTML table, the links in the first row of the 2nd table work and call javascript functions, but for any row thereafter the links or buttons no longer work.
<form id="mylists" name="mylists">
<div id="table" style="overflow: auto; height: 250px; width: 250px;">
<table id="myplaylists" cellspacing="0" cellpadding="2" width="225px" style="position: relative; left: -7%;">
<tr height='8px'><td><a href='javascript:getUserPlaylist(0)'>title</a></td></tr>
[Code]....
I have a column of links that use ajax to load content into the adjacent DIV, and I have used the loadobs function to load the JS and CSS files along with the external file. Now within the external file I have used javascript to create a 3 tab section; when you first load the page it is fine BUT if you navigate away from the page and then try going back and loading the same external page then the tabs stop working and all the content of the tabbed sections stack ontop of one another as though the javacript isnt working?
It is a work in progress but the page I am having the problems on can be found at [url] if you click on the top link in the left hand column called Tara - Female vocalist you will be able to see where the tabs are.
is there any way to get this AJAX to be called on a button click? I know how to use buttons to call JS functions but I'm not sure where to add the open and closing parentheses with this AJAX...I've tried encasing different parts, but to no avail.So guessing I have to do something different here? I'm not sure, really new to this.And yes I've tried searching, again it's very specific and a bit vague.
$(document).ready(function(){
$('#xavisys-logo').live('click', function(e) {
var r1='';[code]....
jquery provides ajaxStart() and ajaxStop() events. Those two events do not seem to be triggered if the ajax requests are made by Microsoft Ajax tool Kit (from ASP.Net code). Is there any way to bridge those two event models? If not currently possible, is there any future initiative or plan out there to make this happen?
View 2 Replies View RelatedIs it possible for an AJAX request to be left open for multiple responses? This could avoid repetitive polling of the server.
View 17 Replies View RelatedCode... I can open it up in the current page, but the menu is in a frame and I need to open it in a fram called "home".
How can I do that?
I'm trying to write code where an ajax function, at a specified interval, calls php script to query a table and open a certian window according to the response(variable) received. After that, the ajax function will continue to call the same php script but will open another window only if the response or variable is different from the previous request(s). What kind of method should I use to achieve this?
View 7 Replies View Related