JQuery :: How To Start With Making Call
Aug 10, 2009I m very new to use ajax. but i know the basics of ajaxcall and basics of javascript. Please help me how to start with makingajax call ..please give me also sample code
View 1 RepliesI m very new to use ajax. but i know the basics of ajaxcall and basics of javascript. Please help me how to start with makingajax call ..please give me also sample code
View 1 RepliesI need to make a $.post call on the beforeSend event of another $.ajax call.I read the documentation and I see that if the beforeSend return false the ajax call will be interrupt.So I made this code but doesn't work, because the real value of the beforesend function isn't true or false, is the value of the post.I have to do this because when you click on a link I need to verify before if you are able to do this via db permission of my webapp.I think you don't understand...This is the code:
$.ajax({
async: true,
beforeSend: function(){[code]....
});I see always the alert of success event, so the return of the beforesend is not correctly done.
I want to know your opinion on where to start to make a floating box script, and why.
I've thought about making a floating div with css and javascript to make the box move.
I haven't really used javasript in my site so far, but I think I need it here. I have a large text box where the user can enter several lines of text. The problem is, that I want the enter key to start a new line when the user is entering text, rather than submitting what has so far been entered. What I've got so far has stopped the enter key from submitting, but has also prevented it from starting a new line:
<form action='aaa.[php]' method='POST'>
<input type='text' name='text' onkeydown="if (event.keyCode==13){return false}" >
<input type='submit' name='zzz' value='Submit'>
This completely disables the enter key. How to make it so that the enter key starts new lines?
I have a requirement....I have a timer on a page. If the user leave the page (mouse goes off of that page) the timer starts and continues...and when the user comes into that page(mouse over that page) the timer goes off/STOP....Is this can be done?? using javascript?
View 1 Replies View RelatedI use $.getJSON for making an ajax call. This is the code.
$.getJSON("json/",
{cname:$("#customerNameId").val(),email:$("#customerEmailId").val()},
function(data){
alert(data);
});
The data is sent to the server, I also get a response from the server. My firebug shows the response as the value I sent from the server.
But the callback function is not called... The alert never happens
I am calling a page which uses a jquery plugin(lightbox) which functions perfectly by itself, but whenever an ajax call is made and this page is retrieved the plugin stops functioning.
This is the line for using the plugin which i have stored in a .js file which is imported in all html files, but still it does not work.
I have link but the link was made by <a href=javascript:run()> How can I make it run when enter will be pressed. How can I set default Enter button to run my run() function.
View 1 Replies View RelatedI am making a call to a perl script using AJAX, this is basically updating a shopping cart item quantity, however; it only works about half the time.. Code:
function UpdateItem(Qty, ProdID, Size){
var XMLHttp;
var ee;
if(navigator.appName == "Microsoft Internet Explorer") {
XMLHttp = new ActiveXObject("Microsoft.XMLHTTP");
} else {
XMLHttp = new XMLHttpRequest();
}
[Code]...
I got 2 sliders in a List:
<li data-role="fieldcontain">
<label for="slider_year"><big>Jahr auswählen</big></label>
<input type="range" name="slider_year" id="slider_year" value="2000" min="2000" max="2011" />
[Code]....
Both alerts wont get called...
I know this should be very easy, but i dont get it.
I have found this nice background rotator:
Code:
<style>
body
{
/*Remove below line to make bgimage NOT fixed*/
background-color:black;
background-attachment:fixed;
background-repeat: no-repeat;
[Code]...
when i run it, i have to wait the 9000 timer to c the first image, and i need the page to start with an image and then start the rotation, i have assigned background-image by css, and tried also to use document.body.background, but when i do this the rotator doesnt work.
Problem: I have a piece of HTML-content, with <hr/> as section breaks. I want to replace the <hr/> with a new <div>. Thus, original: <div>Test test test<hr/>Test test test</div> Result: <div>Test test test </div<div>Test test test</div> With $('hr').replaceWith('</div><div>') it does not work, because the replacement is not valid HTML.
I want to create columns, with <hr/> the column-divider. Perhaps there is also a better solution. The editor is creating the content and inserting HR's where a new column should start.
I created a progress bar with timer, every second = 1% in the progress bar. The problem is that the progress bar does not start.
This is the code I use:
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
[Code].....
I have been using JQuery from last 1 year with IBM RAD 7.0 as IDE and WebSphere 6.1 as app Server without any problem.Now my development environment is upgraded wtih IBM RAD 7.5 and WebSphere 7.0 server.After writing the code in jsp within <JavaScript> tags as [code]i am getting the following error.The function $(HTMLDocument) is undefined.I have included jquery-1.4.2.min.js and even replaced with jquery.min.js.But there is no use.
View 4 Replies View RelatedI use simple code
[Code]...
I have a page on a site that features a list with clickable items in it. When one item is clicked, a div slides down that displays another div with more clickable items. What I am finding is that when I click on two items in the first div quickly, two divs drop down and clutter up the space on the site forcing everything else on the page downward.
$('#cars').click(function () {$("li").removeClass("active_class");
$("#cars").addClass("active_class");
$(".car_type").hide();
$("#cars_div").slideDown("slow");
[Code]..
So basically, the <li> with the id of "cars" removes any active class from the list items, adds the class to the currently selected <li> hides the .car_type and slides down the matching #cars_div. If I click on "cars" and "trucks" quickly, both divs with the class car_type are displayed at the same time.
Is there an easier way to complete all these tasks while toggling between the div that is displayed so only one shows at a time?
I have simple problem in which I want to set the difference of 2 datesmax 60 days.I am able to select dates from past in 2 textboxes and I want whenuser select start date , the end date calender should disableeverything after 60 days..here is the code I am using:
Date.format = 'mm/dd/yyyy';
//this function is used to show only past dates in calendar.
$('.date-pick').datePicker(
[code]....
I have requirement to manually insert div tag at select locations, I have shown the html and my requirement, please see if you have a solution
Existing
Requirement:
So I dont have access to exact id, but atleast I know the id would start with t1.
Looking for a script that will start a website at a custom location [URL]tarts page at top: 800px, left: 400px) I am NOT looking for any sort of popup window positioning. When a visitor access the site using their browser I want that page to start at a location I specify like this website does: Please note, I realize this site uses anchor tags to accomplish this. I'm not good enough at Jquery to know how they did it, or modify it so that it also handles points left as well as top.The ideal script would position this point in the center of the browser window.
View 1 Replies View RelatedI am using the toggle function to hide and show a div. Is there any way I can get the div to be hidden on the page load, and then when when toggle is called, it will show it (since it would be currently hidden).
The way I toggle works for me so far, the div is visible as default, and then once the toggle is activated, it is hidden. I want it to be the opposite.
I'm having my first attempt as using JQuery (and working my way through my sitepoint books) and am a little stuck on the following.I am trying to put the cycle plugin into a web page (on my local machine using xampp) and whilst my 1st images appears it looks as though the actual plugin will no start.
View 1 Replies View RelatedI have 1 img when you click on it start an ajax call that call a php script. I know the ajaxStart function but what I have to do for having that when I press the img, it replace this with a loading gif and when the call is complete replace with the original img?
View 2 Replies View RelatedI created that function for an image slider:
$(document).ready(function(){
$("#gallery").click(function(){
$(this).find("li.third").fadeOut(800).removeClass("third").next().addClass("third").fadeIn(800);
$(this).find("li.second").fadeOut(800).removeClass("second").next().addClass("second").fadeIn(800);
$(this).find("li.first").next().addClass("first").fadeIn(800); $($(this).find("li.first")[0]).removeAttr("class").hide().appendTo($(this)).fadeIn(800);
});
});
Actually I want to fade in the first picture first. Than the second and at the end the third. To achieve that I changed the order of these following three lines:
$(this).find("li.first").next().addClass("first").fadeIn(800);
$(this).find("li.second").fadeOut(800).removeClass("second").next().addClass("second").fadeIn(800);
$(this).find("li.third").fadeOut(800).removeClass("third").next().addClass("third").fadeIn(800);Unfortunately it doesn't work.
How to open the activ ul from the start at a site [url]
View 1 Replies View RelatedCode:
function getCount1(){
sndReq("count&queue=1");
newCount1 = document.getElementById("count1").innerHTML;
if(count1 != newCount1){
[Code].....
I have no other animations on my page, yet "updateQueue1()" happens way before the animation...
I have 3 sliders on my home page and I would like to make them start one after the other, so 1st would start immediately, then after a short delay the second one, and later the 3rd, so they don't make the transition at the same time. The slider I am using is Avia Slider [url]
Trying this code but they are still running synchronously:
Code:
How can I achieve what I need?