I use $.getJSON for making an ajax call. This is the code.
$.getJSON("json/",
{cname:$("#customerNameId").val(),email:$("#customerEmailId").val()},
function(data){
alert(data);
});
The data is sent to the server, I also get a response from the server. My firebug shows the response as the value I sent from the server.
But the callback function is not called... The alert never happens
Can you see an ajax call in Firebug when using $.getJSON? If so, does it return the jsonobject correct? Maybe there are some enters or something in front of the json?
View 4 Replies View RelatedI am calling a page which uses a jquery plugin(lightbox) which functions perfectly by itself, but whenever an ajax call is made and this page is retrieved the plugin stops functioning.
This is the line for using the plugin which i have stored in a .js file which is imported in all html files, but still it does not work.
I am making a call to a perl script using AJAX, this is basically updating a shopping cart item quantity, however; it only works about half the time.. Code:
function UpdateItem(Qty, ProdID, Size){
var XMLHttp;
var ee;
if(navigator.appName == "Microsoft Internet Explorer") {
XMLHttp = new ActiveXObject("Microsoft.XMLHTTP");
} else {
XMLHttp = new XMLHttpRequest();
}
[Code]...
I need to make a $.post call on the beforeSend event of another $.ajax call.I read the documentation and I see that if the beforeSend return false the ajax call will be interrupt.So I made this code but doesn't work, because the real value of the beforesend function isn't true or false, is the value of the post.I have to do this because when you click on a link I need to verify before if you are able to do this via db permission of my webapp.I think you don't understand...This is the code:
$.ajax({
async: true,
beforeSend: function(){[code]....
});I see always the alert of success event, so the return of the beforesend is not correctly done.
I'm using Christophe Beyls' Slimbox 2 to get the lightbox effect on a gallery of Flickr images on my site, and I'm trying to modify it to grab the description of the image and put it in the title of the lightbox. The photo id is already given, but I'm not sure how to get the description out of the anonymous function so I can concatenate it to the linkMapper return (el.title).
Code JavaScript:
linkMapper = linkMapper || function(el) {
var uri = 'http://api.flickr.com/services/rest/?api_key=[key]&format=json&method=flickr.photos.getInfo&photo_id=' + el.id + '&jsoncallback=?';
$.getJSON(uri, function(data) {
[Code].....
I m very new to use ajax. but i know the basics of ajaxcall and basics of javascript. Please help me how to start with makingajax call ..please give me also sample code
View 1 Replies View RelatedI'm using $.getJSON to get data from WCF service in the form om json. this is working fine in IE7 but in mozilla it returns nothing. My code is
$.getJSON("http://localhost:3162/VirtualService/Settings.svc/
GetAllCountries",
function(data) {
alert(data);
});
this code returning me the list of countries in json format. so what to do in the case of mozilla..
I am trying out $.ajax instead of getJSON for debugging purposes. Because getJSON did not report an error in IE (6,7 or 8) and I am
trying to figure out why a jQuery plug-in is not painting my returned images to the screen in IE but is in other browsers. So I tried this. Interestingly enough, it hits the error event in IE but not firefox, safari and the rest and I don't know why (this code works great and renders my data just fine in FireFox and the rest). I know my returned json is valid:
$.ajax({
type: "GET",
url: "http://localhost:59396/sss/sssHandler.ashx?
action=getproducts&ids=" + ids,
[code]....
I don't know what else to do to troubleshoot why IE is having so much trouble with the returned JSON or just executing the function(data)
using either getJSON OR this. I have set the headers not the cache also in the response. IE refuses to enter my function(data) on the response.
[
{
"ImageTag": "u003cdiv class="CarouselItem
"u003e<p><img src="http://www.xxx.com/image/
[code]....
Same result. Firefox and the rest had no issue. IE still exited the $.ajax and my error method kicked in. No rhyme or reason whatsoever and I tried the IE Dev tools... nothing. About the only thing I get is this: Line: 163 Error: System error: -1072896658.Line 163 which is simply the line: function() { alert("An error has occurred. try again."); This has got to be the most f*d up situation I've been in and I need to get this working! I just cannot understand why IE can't parse a getJSON or $.ajax response, that is impossible or else there would be a huge meltdown with jQuery.
I have link but the link was made by <a href=javascript:run()> How can I make it run when enter will be pressed. How can I set default Enter button to run my run() function.
View 1 Replies View RelatedI'm trying to access a variable that is created after an AJAX request was successful, to re-use it in parts of my code:
$.ajax({
url: 'http://api.twitter.com/1/statuses/user_timeline.json?callback=?',
data: {screen_name: 'danmofo', count:amount},
type:'GET',
[Code].....
Is there an alternative method to making the variable tweets usable outside of $.ajax ?
I got 2 sliders in a List:
<li data-role="fieldcontain">
<label for="slider_year"><big>Jahr auswählen</big></label>
<input type="range" name="slider_year" id="slider_year" value="2000" min="2000" max="2011" />
[Code]....
Both alerts wont get called...
I know this should be very easy, but i dont get it.
The general framework is a simple user login function. The user name is selected and a password entered as usual. The function grabs the element values and passes them to a php page that queries the database. An AJAX call returns the password to the function and then I want the innerHTML to be a choice of two web pages, depending on success or failure of validation. There are existing AJAX functions available on the internet but they are overly complicated for what I think should be a simple, quick to load function.
Where I am stuck is that the standard procedure to make an AJAX call is the browser window event. How do you make the call from within the function? I have tried creating two new variables, "success" and "again" to replace xmlhttp, but still stumble on the event to assign a value. I left the blank password protection (if statement) with that variable to demonstrate what I mean.
I've put in my code below, which is in development and successfully alters the innerHTML text depending on user input but I can't figure out how to insert the relevant php page. I have '// out' the testing bits, but left them for info. (I have tried full 'scripting' as the innerHTML, but it's messy.)
I want to use prototype js to have it submitted without refreshing the page.
View 4 Replies View RelatedIm making a fact system, and I need a refresh script, For example when someone clicks on the "next fact" button, the "div" part (where the fact is displayed) refreshes. ONLY the div part. and the javascript below is externally loaded...
List of facts!
Fact[0] = "You are born with 300 bones but only have 206 as an adult because many of your bones fuse together and make bigger more solid bones.";
Fact[1] = "The word "queue" is the only word in the English language that is still pronounced the same way when the last four letters are removed.";
Fact[2] = "Beetles taste like apples, wasps like pine nuts, and worms like fried bacon.";
Fact[3] = "In 1386, a pig in France was executed by public hanging for the murder of a child";
Fact[4] = "Scientist have believed that there are more chicken in the world than any human beings.";
Generate the facts
I wrote the following code with Dreamweaver:
If I run it in Dreamweaver It works and the alert success is raised, but If I run this code into Safari or Chrome the Error alert is always raised.
My goal is to get some HTML content including some UI widgets and other stuff via an ajax call. To clarify my goal and the strange behavior, I attached some HTML files, that you can run for yourself. Open the index.html will show you some UI widgets, which are pulled from the ajax.html via ajax. When you scroll to the bottom you can see the same content inserted a second time. But this time, the widgets are not "rendered". It looks if the "button()" calls etc. are not executed.
The only difference is the way I insert the result of the ajax call. The first time I insert the hole content received by the ajax call, the second time I only insert the content of a special div. The goal in this is to get various chunks of content with one ajax request and replace "div#one" and "div#two" with different parts of my site. Which is not working. Is it generally okay to receive html content which has some script parts to be executed via ajax and what is wrong with my second approach?
I'm currently using the dialog functionality (modal form) from UI library to submit data to the database. All the validation checks have been running ok until one of the validation checks requires a ajax call to check if a username exist in the database. I'm fairly new to both javascript and jquery so this could be a fairly basic blunder. Initially, i thought it was an synchronicity problem, but I changed the $.ajax async option to true but still no joy, so maybe it something to do with scope etc?
Here's the code:
function checkIfUsername(){
$.ajax({
type: "POST",
url: ""+CI_ROOT+"index.php/admin/check_if_username",
data: ({username: username.val()}),
async: false,
dataType: "json",
success: function(data){
returnUsernameBool(username, data);
}});
}function returnUsernameBool(o, data){
if(data.bool == true){
o.addClass('ui-state-error');
updateTips("Your username must be unique");
alert('false'); //this works
return false; //still can't return bool
}else{
alert('true'); //this works
return true; //still can't return bool
}}
bValid = bValid && checkIfUsername(username);
alert(bValid); //still gives undefined
I am trying to set an html attribute after an AJAX call. Works great on the initial tab I can't get it to work on the rest [code]...
View 1 Replies View RelatedIs it possible to get a return value from a page call within an ajax call? For example,
$("#new_request").click(function(e){
$.ajax({
url:"_insert_new_request.php",
type:"GET",
[Code]....
Here I make an ajax call from a click on a div. I then call "_insert_new_request.php" page, with a param of "partner_id_link".
Can I return a value from the "_insert_new_request.php"? and how?
I am planning to use an AJAX call to a PHP script that accesses a REST servlet. My php script would be very simple; something like:
[Code]..
I'm an experienced programmer, but I'm fairly new to web development, so I am having trouble interpreting this error. What have I done wrong? Is this the proper way to call a PHP script with AJAX?
There is a flash image slider on the top of Sky.com which makes the hovered image large and when clicked, does some action.
View 4 Replies View RelatedI have a page that creates one unordered list from the contents of another list. The second list is created from a database query and is hidden on the page. I have written a JQuery function shown below that does an AJAX call which causes the hidden list to be created and that is working perfectly. The problem is that when the code following the AJAX call is executed it doesn't see the hidden list. The alert message displays 0 the first time. clicking on the Load button a second time results in the first list being displayed. If I click on the Load button a third time, the previously loaded list is displayed; click on a fourth time and the new list is displayed.
In other words, it takes two cycles to display the correct list. I am at a loss as to what might be the problem. Other than this issue the code does what I need it to do.
$(function() {
Strange behaviour: User enters text into textarea - text includes URL with protocol e.g. [URL]. JSON call fails with 403 forbidden. It seems the the serialised content is being interpreted as a cross domain call (my guess). Any other text works - Even if the user enters "http://www.u", but as soon as the input qualifies as a url, I get a 403.
The code extract:
var formText = $("#contributioncontrol").serialize();
$.getJSON('[URL]',formText, function(response) {
if (response.ERROR != true) {
var output = response.HTML;
$(output).hide().prependTo("#results").fadeIn("slow");}
}
If the user enters http://www.url.com in the textarea on the form then The request looks like this: [URL]. The '/' chars in the line above are replaced by% 3 A % 2 F % 2 F (without spaces - Don't know how to stop browser interpreting the encoded stuff).
And the response like this:
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>403 Forbidden</title>
</head><body>
<h1>Forbidden</h1>
<p>You don't have permission to access /API/createcontribution.php on this server.</p>
<p>Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.</p>
<hr>
<address>Apache mod_fcgid/2.3.5 mod_auth_passthrough/2.1 mod_bwlimited/1.4 FrontPage/5.0.2.2635 Server at www.mysite.com Port 80</address>
</body></html>
i have a set of select fields, which when selected, send a value via ajax, to return a sub-selection for further choice. I have 3 levels of sub-categories like this. For some reason it works in FF only - not IE. [URl]..
View 12 Replies View RelatedI am using an ajax call when clicked on a link... It asks whether you want to continue or not and if you say "ok" then it uses a perl script to delete something from the db.[code]So I was able to call confirm on each of those links and if agreed use an ajax call to a perl script to wipe the user from database. The thing is that I had to usereturn false; in the end of my js call (after ajax) otherwise the link would take me to the script, which I dont want to. I want to remain at main level (to be able to see all users)... Now how do i refresh the page after such deletion? Lets image this scenario:
User clicks on link_to_delete Brad => confirm => he confirms by clicking ok => ajax call to perl script that handles the deletion of Brad => return false (I want to remain at index.pl) => HOW DO I REALOAD INDEX.pl ? I deleted Brad but I can still see him cause the page has old data.