I have a bunch of floated divs and I want to increment a variable every time they 'jump' to the next line. When I try using offset() for this I get the same top,left cords for every single element. Is there any way of getting the actual offset? (I get the same result in FF and Chrome)
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I am using after() to add a div after another floated div. However because the div is floated the added one is not being positioned at the bottom of it. How to get the added div to appear after the floated one.
View 2 Replies View Related$().offset() does not return values on Chrome. Works well in IE and FF.
var element = r.circle(cx, cy, radius); // r.circle is from raphaeljs library.
var offset = $(element.node).offset();
Is there a work/fix around for this?
getting first line coordinates of multiple line inline element.
Example HTML
aaa bbb ccc ddd <span id="target">eee fff ggg
hhh iii jjj</span>kkk lll mmm nnn ooo ppp qqq
$(document).ready(function() {
[Code]....
Assume that span#target has a line break, when I see a browser. Then I click span#target, above function returns the head of coordinates which second line ("hhh") has. I want to have the coordinates which first line ("eee") has. How can I get that?
I am doing this code that has multiple elements of the same type.... to select the parent DIV I had to use this code:
$(this).parent().parent().parent().parent().append($('#grid_show_columns'));
How can I do it without using that many parent() ?
I got a pice of html that i want to transform to UI Tabs. This code is aouto generated and wrong, so I want to correct it before calling tabs() function
<div id="localtabs" class="list">
<ul>
<li id="tab1"><a href="#tone" title="Local Tab One"><span>Local Tab One</span></a></li>
[Code].....
My target is to move the divs currently inside the UL tags outside.
My thought was to select the divs with this statement:
var tabdivs = $('#'+options.id+' ul').children('div');
alert('tabdivs.length '+tabdivs.length);
This works fine in Firefox he told me tabdivs.length 2 but in IE6 i got an alert tabdivs.length 0 .
Why IE6 found no childrens?
If you look at this page [url] you will see that if you hover over the photo the text block goes up, and if you hover over the text it slides down and covers the photo. It's all pretty basic and it works fine. But ones I try to get them animated during the sliding up and down the trouble starts.
It works fine if you take the time and wait for them to go back to their starting position, but if you move over the items quickly it becomes a mess. You can see what I mean on this page [url]
I hoped that by adding a stop() before the animation if would fix the problem, but it doesn't really improve at all. It still quickly becomes a mess if you hover from one item to the next one.
How I could get the animations to work properly without it becoming a mess? I now there are double id's in the html, but unfortunately I can't really change the html.
I'm having a problem with my radio buttons. On FF and Chrome they work just fine, but in IE, they does'nt appear as sellected. In other words: they do their job, but when you click'em, they stay unckeched. The genetarion code:
var item = $('<input type="radio" />').attr('value',pid).attr('name',name);
self.append($('<p />').append(item).append('<label>'+desc+'</label>'));
i am following the example ajaxSubmit[URL].... here my code[URL]... i realized that the showRequest work correctly, shown all my form submit values But it doesn't respond "showResponse(responseText, statusText, xhr, $form)" is not execute. the respond prompt is not pop up
View 2 Replies View RelatedI'm having problems getting my popup menu to work correctly. I have the following script:
[Code] .....
I'm looking for some guidance on a part of some coding practice I'm stuck on!
I've created a shopping cart using javascript, the items save to the arrays etc and it all works fine. If the user adds the same product again to the cart the quantity is added onto the previous quantity that is already in the cart.
To check if the item is already in the cart I've ued the below code, but what it does is update the quantity for the first cart, and when it updates the quantity for the second item it updates the quantity but keeps adding the same product to the cart in seperate elements of the array as well (if that makes sense?
here are the two functions used [code]...
It may jsut be a simple mistake I've made but it's been bugging me a lot and I can't seem to fix it.
I am sorry if this is a stupid question. I have never really used javascript before. I found some code online that I tried to piece together so I might not even be going about this the right way.
I want the background to take up 100% and resize with the browser. That works fine. I also want the text "welcome to the ahi life" stick to the bottom left hand corner and the enter button to stick to the bottom right. I would like these to resize with the browser as well. It all kind of works, except the first time you load the page the text and the button are much smaller than I would like them to be. If you refresh the page everything is correct.
[Code]...
I have a page with a textbox that I want to have a message written inside it that will dissapear when the user clicks in the text box and writes something and it will show up again if the user clicks somewhere else but hasn't written anything inside the textbox. So I am using the onfocus event in order to write "Enter your email here" and the onfocus event in order to show the "Enter your email here" message inside the textbox if the user clicks somewhere else in the webpage but has left the textbox blank. If however the user has written, for exampl "jim@yahoo.com", I want this to remain in the textbox.What am I doing wrong?
Code:
<html>
<head>
[code]....
Code:
Red part in the code above is for conditional statement.
But the conditional statement doesn't work correctly.
How can I make the conditional statement correct in javascript?
I am trying to make a textbox enter input by pressing the enter key, not just clicking a submit button. For some reason or another it is not working correctly for me. I found this snipet of code that works for me but I was wondering if someone can explain it to me. I get the basic of what it is doing, I just want to understand it better.
.Attributes.Add("onkeydown", "if(event.which || event.keyCode){if ((event.which == 13) || (event.keyCode == 13)) {document.getElementById('" + btnSearch.UniqueID + "').click();return false;}} else {return true}; ")
I am trying to use JS to change the display.style property of a div from �block� to �none� in order to hide and show it. I find that my code works in Firefox but not in IE. Furthermore, I find that the code works fine in IE if the div I�m trying to show/hide is not floated, but when it IS floated then I�m able to hide the div but unable to re-show it once it�s been hidden. Finally, I find that when the div I�m trying to show/hide is floated left and is the left-most element on the page, it works fine, but when I have another element floated left before it, then it fails to re-show once it�s hidden. Here is my code. In order to solve this problem I have removed all other code form my website, so this is the only code. The HTML:
[Code]...
Take a look at my testing website: [url]
You'll find the following javascript in the source code:
Now this all works...well, sorta.
The DIV elements specified are hidden when the page is first loaded.
These DIV elements then re-appear (as programmed above) when the mouse pointer is hovered over them.
These DIV elements are listed on the right-hand side of the test webiste.
They contain the Google Ad's you will see listed along the right-hand side of the website.
However, you were not suppose to see the Google Ad's when the website first loads up.
The DIV elements are initially hidden, but the Google Ad's contained in the DIV elements are always visible!
I want the Google Ad's to only appear if a mouse pointer happens to hover over them ( a little test of mine.)
I don't get it...the DIV elements disappears when appropriate, why not their contents: the Adsense?
I'm using a script to display a floating menu. I don't know how to set an offset for the footer so that it does not go all the way to the bottom. I'd like a 100px margin to the bottom of the screen. Here's my code:
[Code]...
I'm trying to create a scrolling menu. Example here [URL] I don't think there's an issue with the javascript necessarily. I've tried alternatively using jquery's animate function with scrollLeft and I still get the flickering. I'm thinking it's more to do with the HTML/CSS. For instance I'm wondering if using a table instead of a floated list for the menu might be a step in the right direction.
Code PHP:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Gallery</title>
<style type="text/css">
* { /* default styles */
[Code]....
I'm making a drop down box using offset so it's below the correct option, but if I resize the window, the dropdown box keeps the same offset as when the page was originally loaded.
View 3 Replies View RelatedI am having an transparent image and that image having image content at the right most corner of the image. Is there any way to get the offset of the image content(Actual content of the image) in Jquery.
View 1 Replies View RelatedI have this bit of jQuery:
$(document).ready(function() {
$('article').click(function(e) {
e.stopPropagation();
[code]....
It works in Chrome, but not Firefox or IE.[URL]
I have problems setting an offset of the LocalScroll-plugin (and the ScrollTo)[URL]If you click on one of the links (main-section), you'll see the divs are not lining up right. I guess it's about scroll to goes to div+padding+margin. Right? So, I'll have to adjust an offset.
My code:
$(document).ready(function(){
$('#Main').localScroll({
[code]....
I think the offset() function returns node's position relative to document. The attached html file prints the offset value to console when the box is clicked. I expect the same value would be printed every times. However, when the script is run on iPad (with simulator), it print different value when I zoom and scroll to different position. This problem does not occurred in iPhone.
Attachments
test.html.gz
Size : 388 Bytes
Download : 505
There is a long thread about this in the posiiton() reference page, but I am not finding a thread here in the forums, let alone a solution. I have some code that is trying to do calculations on the left and top attribute of child DOM elements. So, I have 5 divs (floated left, with width and height assigned), contained in another div. If I iterate over the 5 divs and call either position(), offset() or even css('left'), they always return 0. I have tried setting margin: 0px as well, but same result.
View 3 Replies View RelatedI have the below code to calculate how tall a 3rd div needs to be. This code works except for one flaw. It always seems to read the previous .top and .height() values.As .annoucement-area-880 and .content-annoucement-bottom-880 are dynamic (two different types of accordions) they resize depending on what element gets clicked.One uses the .animate() method while the other .slideDown().I tried enclosing the below within a $(document).ready(function(){...}); but this doesn't help.In conclusion, below code works fine except it reports previous (aka old) values which in effect cause it to calculate an currently invalid height.
Code:
var div1 = $( ".annoucement-area-880.id1" );
var div1_offset = div1.offset();
[code]....
