I am having trouble submitting a form by clicking on a button "<input type='submit' />" while I am waiting for the callback of the $.getJSON function to fire. Is there a way to allow the form to submit even if the callback is never called?
View 5 RepliesIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIs it possible to read a web page on some web site that contains a form. Then identify the fields in the forms. Then fills the fields with my data. and then submits the form as it submitted normally. I need to do this to automate for my final proyect , i need to fill many web pages remotly
View 2 Replies View RelatedThe following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I'm trying to get an upload popup working with the jQuery form plugin[URL].. When I click a link I load a form html from the server and add it to a container div by setting the div's html attribute. I then attach a submit handler to the form so I can call the ajaxSubmit function of the form plugin.
[Code]...
Malsup's most excellent and comprehensive Form plugin has me completely stuck on just one thing.Take a look at this: http:[url]....At the bottom are a variety of submit buttons, and when you click one, it knows which one has been clicked.And I've been through the js and the source and the examples and I can't figure out how the bleep it's done!I'll tell you why I'm asking, then perhaps you can probably tell me I'm doing it wrong anyway!Let's say a blind person logs in, and want to edit their presets.I don't want the form to be too complex or clever or ajaxy, as screenreaders don't like that, so it just iterates through as many presets as they have, and populates a form with edit boxes.But there's no point "pushing back" 29 unchanged items just to edit one row.
So my idea was I'd just "fieldSerialize()" the details of the row that was currently being edited and submit that to my little php routine that updates the db. Then they can do a refresh just to hear the list again.The js looks like:
$(document).ready(function() {
$('#myForm').ajaxForm(function() {
var queryString = $('#myForm').formSerialize(); [code]....
All works fine like that. But if I change line 3 to: var queryString = $('#myForm :button').fieldSerialize(); it doesn't work. I've also tried:
'#myForm :button'
'#myForm .button'
':button'[code]....
Maybe I should just generate as many separate forms as there are presets, but then I'm going to need as many ready(function)'s as there are rows, which is going to be very messy.
I have a php form and it has 3 submit buttons namely "delete" , "update_quantity" and "place_order".They all work fine but I want to build in a check for each one just in case the user click one of the buttons by mistake.So Each one must have a different message like for delete it must be, "Are you sure you want to delete Record nr ......" OK or Cancle.
And for update " Are you sure you want to update Quantity to....." OK or Cancle.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....
So, here's my problem :
I've created a table in my document, presenting a list of items, one
can 'select' by clicking on it... (Kinda like a menu, you make your
choice from) But since this table can get very long, I've put
something of a 'search-form' on top, which enables the user to make a
selection of products from the list.
Now, the form uses a "post" method, and submits to itself, using the
form action. Some PHP script will make sure that the form is filled
out already, the next time it's presented.
The table, containing a list of products is presented, below the form.
When a user clicks on a product, the product should be "selected". At
first i just used a <a href="zoeken.php?prod_id=24"> link to do this,
but the problem is that my form won't remain in tact.
So now, the global idea is to submit the form after setting a hidden
form-field using JavaScript, using a onClick event.
Here's my code :
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
I have a form in my webpage that I would like to submit to a different action in a _blank window, but without changing the original form.So I've tried this :
$('#myform').clone().attr('action', '/something/else').attr('target', '_blank').submit();
But it won't submit unless I append the new form in the page (which I don't want).
I am trying to use jquery's ajax framework to check if the data that is entered is valid or not. The form works properly except i cannot get the page to go to action="something.php" file in the form part.
[Code]...
I enter a company into the form and hit submit The form will send the data to my validate company.php file. Validate company will return either "good" or "bad" If "bad" the form works as expected. it will stop the function by returning false and alert you that it is already in the database If "good" the page just sits there, basically returned false. however if you click submit again on the html form the function will go through and do what return: true should do.
This should be so simple but it isn't working. I just want to check that the value of a form element isn't empty before the form is submitted, if it is empty display an error, if not,submit the form. 101 right?[code]So how do I make the form not submit on fail?
View 1 Replies View RelatedI have been strugleing with this for day now - my submit does work i have put in the form1 part the value of TEST1 through TEST41 on the server side php script I am getting all NULLS with my $_POST - So either the values stored are getting clobered and being replaced with nulls or the ajax is happening and maybe that is the problem but the submit of the form is not? [code]
View 16 Replies View RelatedI have piece of the code:
<script type="text/javascript">
$(document).ready(function(){
$('.warning').remove();
$.get("token.php",function(txt){
[Code].....
but when I will submit the form, runthis.php script is not executed.
i have a form
<form id="login" autocomplete="off" action="<?php echo $_SERVER['PHP_SELF'] ?>" method="POST">User:<br/><input type="text" name="user"><i></i><br/>
Password:<br/><input type="password" name="password"><i></i><br/>
<input value="Login" onSubmit="setTimeout(2000); return false;" class="submit" type="submit" name="login">
[Code]..
I have a couple of simple forms:
[Code]...
but it doesn't work, because it's not passing the variables correctly I don't think. I don't know how to simulate a simple GET posting of a form.. the data line in this code is from another script which uses POST, but POST doesn't work for my purposes so I have to use GET.
I am currently using jquery .post ajax code to submit a form.
The problem is that when I click on submit it takes me to the php file page. Which is blank.
I don't want this... this functions just like if I made the form in html meaning when submit it takes you to the .php file well opens it in a page.
I want to use ajax that when you click submit it submits the form and then shows a message on screen.
When I click the submit button my message gets shown on the screen saying it submittedsuccessful then with at least 2 seconds it sends the user to the php file meaning opens the page up in the browser not a new tab or new window but sends the user to the php file. Which I don't want it to happen. So the page is blank.
I used the .post and serialized the form. Is this the right thing to do?
I don't want to send the user to the php file. Just use ajax and check if it updated the database and if so send either 1 or 0 depending if it went threw then the form page willreceivethat data and then fade in a message saying either error or success depending what went on.
I would like to know how you can use jquery ajax to submit a form without refreshing the page. I do know about the serialization function but would like to see an example of what is submit().
I currently tried to get my form working but but can't get it to work meaning to submit something from the form.
I am trying to submit XML values via a form using jQuery. I then need to process the returned XML.
I am testing using the following jQuery:
And the following HTML form:
I am tring to submit the form to the URL [url]. It is not working.