JQuery :: Unable To Place Images To The Right Of A Cube?
Nov 9, 2011
I have created a jquery cube that has rotating images within it, and I have defaulted the margin to display left. I am now attempting to place a few images to the right of the jquery cube, but no matter what I've tried I am not able to get the unassociated images to display to the right. Instead they are displayed below the bottom of the jquery cube.
There is a slideshow on my website that reads in the address of local images and puts them in a slideshow rotation to be displayed on the page. I currently have to "hard code" the addresses in, similar to the JavaScript below:
However, I want to be able to place images in the Images directory without having to make sure the files are named the same as in the code. I would like JavaScript to go out to a local directory, see what's in there, grab anything in jpeg format (regardless of the name), and put it in the slideshow rotation.
I am using Image cube(URL...). But there are lags and image cube does not rotate smoothly but with some "jumps". Does anybody know how to escape that leaving alone those teeth on cube borders when it is rotating? Or it is javascript engine lags?
I was wondering: You know how you're able to left-click and hold the mouse-button down on a image and then drag it around? Everybody must know that; Is there a way to "lock" the picture, so that isn't possible? I'm not talking about removing the right-click features, like saving the picture, etc. I just want the users not to be able to drag it all over the place - like a background for example. In HTML, of course
I have a question about this image cube [URL]. I would like to make it like this [URL]. How to make that thumbnail scroller with highlighting function and linked properly to the cube.
In this code i used 2 coloums.in 1st coloum i used 3 buttons(images). so when i move mouse on any particular button on leftside it should display respective image on right side.Even if we move mouse over right side image it must show same image. But here when i move mouse over second image it shows respective image on right side, but igf i place cursor on that image, it displays 1st,2nd image.if i do samething for 3rd image it displays 1st,2nd,3rd image. so I am facing problem to hide images in rightside for 2nd, 3rd part
<!--head part--> <script type="text/javascript" language="Javascript"> function HideDIV(d) [code]....
I am unsure what is going on with my website? I had flash on it, and I have removed the flash and installed javascript. Everything is installed correctly from what I can see, when I go to the view page button on Dreamweaver the images rotate. When I upload it to my server they stop rotating.I have download all of the files needed for this to work, and have added them all to my server. Here is a copy of the coding.
I am new to javascript, and am having an issue, which I'm sure is elementary.. I found a script for expandable content, it suffices fine. As it stands, the script toggles images onclick. For example, whence the menu is collapsed, it displays "plus.gif" next to it, and when the menu is expanded, it displays "minus.gif" next to it.
Basically, what I would like to know is, thus: how would I change it to display text icons next to it? For example, in place of "plus.gif" I should like it to display "+" as actual text. I've dredged a number of places, however, I've found nothing. Furthermore, I cannot figure out how to do it.
I use a Time Date Picker Javascript code [URL]. It works fine with a placement problem. When you click one of the last pair input fields on the page, a drop-down list will appear from the input field. In my case, the drop-down list shows on the bottom of a page instead. I can't find the code controls the location of the list.
I have the following code: '<div class="Comment">' + $.each(post.Comments, function (i, comment) { document.write(comment.Description); }) + '</div>' ); The document.write() is not working, it erase all the content of my page in fact. What I want is just write the HTML contained in 'comment.Description' for each iteration (comment.Description contains a DIV with multiple elements in it!)
I have a small function which is not entirely correct. Although it produces correct results, syntactically it's wrong. Here's the function, then I'll explain.
function displayLabelErrors(selector) { $(selector).each(function () { var valError = false; $('.validation-error', this ).each(function () { if (!$(this).attr("isvalid")) { valError = true; }}); $(this).toggleClass('input-error', valError); });}
The var 'selector' is an ID and can therefore only ever be 1 object. The foreach in blue isn't required and the red 'this' (context) should be the selector. The issue I have is when I remove the loop, I'm struggling to understand how the var selector fits in the place of 'this'. I've tried a few different ways and still failing.
I am working on a slider for a client site and all works fine when I place the css directly in the page - but when I move it to external file it does not pick up any of the styles that are required to make the slider work.
I have a jQuery plugin that creates a list of news items and appends the <ul> to the element(s) calling the plugin. Each <li> gets a document key added to its data.
A brief snippet of the code:
(function ($){ $.fn.NewsList=function (options){
[Code].....
None of the <li>'s have the data attached to them. I've tested the selector shown above in line 3, and it does pick up the correct <li>'s. The data is not visible in Firebug as it is on the other page. Both functions are called after document.ready and insert the elements after page load.
The onlydiscernible differences between these two circumstances is that in the working case, the plugin is called against an ID, whereas in the nonworking instance, it is called against a CLASS. In addition, in the working case, only one DIV is affected, and in the nonworking case, there are two DIVs that receive the treatment.
I have a four buttons in the page and I want when I click on one of the buttons, contents of div tag are displayed in one place of page. and when I clicked another button, contents of another div tag are displayed insame place of page and previous dive is hide. I prefer divs are displayed with an effect.I am a novice in jquery.Is it possible show me solution with an example?
My problem is that my site has a fixed element in the right side but when looking at the site from a HI-resolution device like TV or something, the element moves about 1000px to right. I want it to scroll down when I scroll the site down. But I want it to stay in the same place on x line.angsti.net if you need more information.
We are using JQuery for one of our software projects, and it's a very nice library. It's making things far easier. We are also using the Validation plugin, which is working wonders for form validation.However there's one wrinkle that we have not been able to figure out.Is there any way to run a function before the validation takes place?We have help text displayed in some of our text inputs and text areas,which are cleared onFocus (and restored onBlur if the user has not entered anything). We would like to clear those help text before validation is run, so that we don't get any false validations based on the help text, rather than the actual value of the field, which is blank.
I'm trying to create a multi-field in-place editing: basically I have a series of values that I'd like to display as a text but when I click a specific button those texts have to become text-fields.
I want to place a printable version in the web page. How to do it? see the image, I want to click or hoove over "Printable Version" then a clear web page pop out.