This is my first serious attempt at using a regular expression.My first name field should allow alpha characters only [A-Za-z], but it seems to be testing for the presence of 1 alpha character. If one is found in the string then anything else is allowed.Bob returns valid which is what I need.Bob1 returns valid but should NOT be valid..1 returns valid not valid which is what I need.My code.
function isValidFirstName(p1_firstName) {
//http://www.javascriptkit.com/jsref/regexp.shtml
var re = new RegExp("[A-Za-z]");
var str = "/dev/filler/test0/"; var patt = new RegExp("/test0/$"); var result = patt.exec(str); document.write(result); which returns: /test0/
in the var patt line I would like to replace the hardcoded test0 string with an expression that matches any characters between the two forward slashes. I have tried with little success.
am in need of escaping the regular expression special characters like '/', '.', '*', '+', '?', '|','(', ')', '[', ']', '{', '}', '\'.I have try with this by the following javascript but i can not achieve that.
RegExp.escape=function(str) { if (!arguments.callee.sRE) {
Attempting to use javascript's regular expression methods to match a particular lab number and building which would then be copied to a pair of textfields, I found that general matching characters needing a backslash were not recoginized. The following adapted code that finds a two-button radio selection shows my problem:
function labstat(){ for (i=1; i<3; i++){ if(document.tester.rm_mod[i-1].checked){ var lb = document.tester.elements["lab"+(i)].value;//either 214 or 215* var bld = document.tester.bldg.value; if(/*/.test(lb)){ //error:Undetermined comment // if(/*/.test(lb)){ //error:Syntax error // if(/5/.test(lb)){ //works to match only 215* // if(/5*/.test(lb)){ //true for all // if(/ddd/.test(lb)){ //false for all document.tester.room1.value = lb; document.tester.bldg1.value = bld; } } }
It appears that the escaped characters are not recognized, whichever form of the method is used, i.e var re = /*/; // or = new RegExp("*"); if(re.test(lb)){ -------- With the --.match(__) method I have the same problem.
I wanted to try creating a basic expression first. I want someone to enter a string that is 2 - 20 characters long and only has letters. This is what I use so far, and it doesn't work, nothing happens at all when I run it.
Code: // Check for a valid name. var namePattern = new RegExp("/^[a-zA-Z]{2,20}$/"); if (namePattern.test(name)) { window.alert("Invalid"); }
name comes from a input box I display on screen. Also, I would like to update the expression so that there can be one space in the string, but it cannot be at the beginning or end. So this string is like a persons name. Bob is OK, Bob Smith is also OK. Edit: Actually, it is doing something but its always coming back invalid.
With the code I had to acknowledge nothing had been inserted,(that is, still spaces, it was working. When I added the code to only accept alpha chars etc., I inserted numbers, nothing worked, with no error message. Would you, or can I send the whole code through for the form. I noticed that the form tags had been changed so I altered them as well according to your message.
It has to be flexible in that the extension can be either 4, 5, or 6 chars (.php, .html, .shtml for example) and needs to cater for and whether querystring parameters exist too.
--------------------------- Windows Internet Explorer --------------------------- <EMBED src=http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1& width=500 height=200 type=application/x-shockwave-flash allowfullscreen="true" allowscriptaccess="always"></EMBED>
how can i get "src" value in above code using regular expression?
does anyone know how I can build a regular expression e.g. for the string.search() function on runtime, depending on the content of variables? Should be something like this:
var strkey = "something"; var str = "Somethin like this";
I need a regular expression that will validate a double quote comma delimited list where the odd entries are numeric and the even are alphabetical. Each pair must also be on a separate line. For example:
"1","Peter" "2","Paul" "3","Mary"
I've used the following expression to validate comma delimited lists, but without the double quotes, numeric/alpha pairing and line return restriction.
Normally I can write regular expressions decently well but for some reason I am having trouble getting this to work. I am validating form data and need to throw an error if there are ANY spaces in the field. abc123 is fine, abc 123 is not. Any character is fine, just not a space.
All I'm trying to do is delete the lines which don't contain a particular string. Actually a filter to edit a log file. I can find and replace a thing with null, but can't figure out how to find the lines which do not contain the thing.
Going further, I want to generalize and use a JavaScript variable containing the decision string, but first I need to worry about the not-within-a-line problem.
Here is the form in question: spraytechDOTcom/download_form.asp I am so close to getting this to work the way that I want, but here is what I am having an issue with: I cannot seem to make it look for the 12 digits that are in the phone numbers that we are going to collect. Ex. 800-123-4567
It doesn't have require 12 characters if there is another way to get the number to validate looking like the example above. Here is my regular expression that I am struggling with:
var re = /[^d-]$/ It seems to block any letters, but it will accept only 1 number. I would really like it to make sure that the phone number is only entered like this: 800-123-4567.
I have looked for days trying to figure this out and have only gotten close.
I'm trying to validate data in a textbox for township (usually written as 12N or 23S for Township 12 North or Township 23 South). In Utah the townships range from 01N to 15N, and 01S to 44S. The expression "/[0-9][0-4][ns]/i" will allow 01n (or s) through 94n (or s). If I change it to "/[0-4][0-4][ns]/i" to limit it to 44n (or s), I then am not allowing for 05, 06, 07, 08, and 09. I hope the above is not too confusing. I'm just starting to work with regular expressions.
I am creating a regular expression for a URL where the domain name (i.e. .com|.edu etc) is optional. That is both http://xyz and http://xyz.com should be valid. If <.> is present then com|edu|.. will be there; but if <.> is absent then com|edu|.. will not be there. Also there can be any number of <.>, but every <.> will be followed by characters. So in other words the string can't end with <.>, it should only end with [a-zA-Z0-9]. So far I have created the following part -
var url=document.myform.addr.value; var str="^(http|https)://(([a-zA-Z0-9.-]+)*[a-zA-Z0-9-]+.(com|edu|gov|[a-zA-Z]{2})|[a-zA-Z0-9]+$)"; var regEx = new RegExp(str);
