I have the following code:
var str = "/dev/filler/test0/";
var patt = new RegExp("/test0/$");
var result = patt.exec(str);
document.write(result);
which returns: /test0/
in the var patt line I would like to replace the hardcoded test0 string with an expression that matches any characters between the two forward slashes. I have tried with little success.
Normally I can write regular expressions decently well but for some
reason I am having trouble getting this to work. I am validating form
data and need to throw an error if there are ANY spaces in the field.
abc123 is fine, abc 123 is not. Any character is fine, just not a
space.
[Code]...
I just want my regular expression to match a backslash. Thats all. Tried giving [\]. Aint working. Tried[x5c] not working. But this hexadecimal character match is working for all the other characters.
What regular expression will match ANY string that has 10 digits in it?
View 24 Replies View RelatedI found this regular expression on the internet and it works fine when I test it in various validators on the web.
Code:
^(((0?[1-9]|1[012])/(0?[1-9]|1d|2[0-8])|(0?[13456789]|1[012])/(29|30)|(0?[13578]|1[02])/31)/(19|[2-9]d)d{2}|0?2/29/((19|[2-9]d)(0[48]|[2468][048]|[13579][26])|(([2468][048]|[3579][26])00)))$
It's purpose is to check for valid date and allows formats mm/dd/yyyy, m/dd/yyyy, mm/d/yyyy or m/d/yyyy.
When I try it with the code below it always returns null.
Code:
function isValidDate(/* String */ p1_date) {
var x = "^(((0?[1-9]|1[012])/(0?[1-9]|1d|2[0-8])|(0?[13456789]|1[012])/(29|30)|(0?[13578]|1[02])/31)/(19|[2-9]d)d{2}|0?2/29/((19|[2-9]d)(0[48]|[2468][048]|[13579][26])|(([2468][048]|[3579][26])00)))$";
[Code].....
I'm trying to perform a very simple validation of user input. I
want to verify that the user entered a six-digit string consisting
entirely of numbers. So anything from 000000 to 999999 is considered
valid. The problem that I'm having is getting the validation to work on
the entire string. In other words, 000000 is okay but 000000000000 is
also returning as a match. Here's a quick code block...I have something
along these lines....
/*********************/
<html>
<body>
<INPUT name="txtNumberField" type="text" id="txtNumberField">
<INPUT onClick="fnTestNumberField()" id=Button1 type=button value="Test
Number!" name=btnTest>
<script language=javascript>
function fnTestNumberField()
{
var sNumberValue = document.getElementById("txtNumberField").value;
if (sNumberValue.match(/A[0-9]{6}z/))
{
alert("match");
} else {
alert("no match");
}
}
</script>
</body>
</html>
/******************/
That is failing when I enter 123456 into the textbox. Why, though? I
know I can replace...
if (sNumberValue.match(/A[0-9]{6}z/))
....with something like...
if (sNumberValue.length == 6 && sNumberValue.match(/[0-9]{6}/))
....or I could assign a maxlength to the input box, of course. The thing
is, I really want to know WHY the regular expression isn't responding
as I'd expect. Is there a syntax error somewhere in the code?
is there a way to select elements that match a regular expression? I have a set of divs with id = "wrap_n" where n is a progressive and I need to select them and for each 1 I have to add a function that togggle the "elem_n" div.
View 4 Replies View RelatedI need to figure out a pattern that can match each letter of the message, but leaves all the html entities alone.
For example, I have a input like this:
<div>
This is the content < Hello >
</div>
Just as an example to make it more clearer, If I wanted to replace the all letters of the message with the number "1" I would have this result:
<div>
1111 11 111 1111111 < 11111 >
</div>
This is my first serious attempt at using a regular expression.My first name field should allow alpha characters only [A-Za-z], but it seems to be testing for the presence of 1 alpha character. If one is found in the string then anything else is allowed.Bob returns valid which is what I need.Bob1 returns valid but should NOT be valid..1 returns valid not valid which is what I need.My code.
function isValidFirstName(p1_firstName) {
//http://www.javascriptkit.com/jsref/regexp.shtml
var re = new RegExp("[A-Za-z]");
[code]....
am in need of escaping the regular expression special characters like '/', '.', '*', '+', '?', '|','(', ')', '[', ']', '{', '}', '\'.I have try with this by the following javascript but i can not achieve that.
RegExp.escape=function(str)
{
if (!arguments.callee.sRE) {
[code]....
String must be minimum 6 charcters long and can only contain A-Z, a-z and 0-9 ....
View 2 Replies View RelatedAttempting to use javascript's regular expression methods to match a
particular lab number and building which would then be copied to a pair
of textfields, I found that general matching characters needing a
backslash were not recoginized. The following adapted code that finds
a two-button radio selection shows my problem:
function labstat(){
for (i=1; i<3; i++){
if(document.tester.rm_mod[i-1].checked){
var lb = document.tester.elements["lab"+(i)].value;//either
214 or 215*
var bld = document.tester.bldg.value;
if(/*/.test(lb)){ //error:Undetermined comment
// if(/*/.test(lb)){ //error:Syntax error
// if(/5/.test(lb)){ //works to match only 215*
// if(/5*/.test(lb)){ //true for all
// if(/ddd/.test(lb)){ //false for all
document.tester.room1.value = lb;
document.tester.bldg1.value = bld;
}
}
}
It appears that the escaped characters are not recognized, whichever
form of the method is used, i.e var re = /*/; // or = new
RegExp("*");
if(re.test(lb)){
--------
With the --.match(__) method I have the same problem.
I wanted to try creating a basic expression first. I want someone to enter a string that is 2 - 20 characters long and only has letters. This is what I use so far, and it doesn't work, nothing happens at all when I run it.
Code:
// Check for a valid name.
var namePattern = new RegExp("/^[a-zA-Z]{2,20}$/");
if (namePattern.test(name))
{
window.alert("Invalid");
}
name comes from a input box I display on screen. Also, I would like to update the expression so that there can be one space in the string, but it cannot be at the beginning or end. So this string is like a persons name. Bob is OK, Bob Smith is also OK. Edit: Actually, it is doing something but its always coming back invalid.
I am trying to test some strings against a regular expression, but have tried at least 10 different online testers with no success at all. Plus I've tried some code to do it myself, again with no success. I know for a fact that some of the strings should match and some shouldn't match, but I am getting "No match" returns from all the strings.
Does somebody have some page code that has the regular expression in some javascript code in the head section of a document, then a form in the body that I can enter the text string, click a button, and I get an alert saying if the string matches or not?
for the character classes [ ], if i want to match ,.[] i cannot put them into the square brackets so how to deal with that? what if the characters are . or ! or ." (<-- combined) it fails if the regexp is [.!(.")] which will treat ( as one of the element. also the book javascript: the definitive guide says that (?=p) requires that the following characters match the pattern p, but do not include those characters in the match. However, the browser failed to figure this out (IE8) i.e. "asd:ert".match(/(?=:)w/) returns null
View 9 Replies View RelatedI have a regular expression called mCheck and a variable called usrVal which contains Ƈ/20/41/11/22' I then use the usrVal.match(mCheck) so the code looks like the following
var mCheck = /^[0-9][0-9]/;
if(!usrVal.match(mCheck))
{
usrVal = Ɔ' + usrVal;
}
Now, I was under the impression that if there wasn't a match then the match method would return boolean 'False'. However it is returning 'null' instead... I have used this exact same check on other pages before and it returned false just fine....
I have seen lot of reg. expession with ?:
For dummy eg
(((XXX)ddd)ff)
The above expression is modified as
(?:(?:(XXX)ddd)ff)
Although both the above expr. gives same result. (RegExp.match() gives
same o/p), most of the places , i have seen second option.
Yes, but different matches r shown (using RegExp.exec())
Is the second expr. most efficient or in particular scenarios?
Any comments???
At the moment my code is like:
function telValid(inString) {
var regexp = /^[0-9 +()]+$/;
return (inString.match(regexp,''));
}
which is use to validate phone numbers (UK at the moment)
this works ok, but wont allow - (Dashes) which i need..
tried doing:
function telValid(inString) {
var regexp = /^[0-9 +-()]+$/;
return (inString.match(regexp,''));
}
I am finding it difficult to find a regular expression for following situation(replace)
a b c d = a,b,c d
a b c = a,b c
regular express to get the file name from a URL?
It has to be flexible in that the extension can be either 4, 5, or 6 chars (.php, .html, .shtml for example) and needs to cater for and whether querystring parameters exist too.
So, both
[URL]
and
[URL]
The regex should return newthread for both.
I.E.:
---------------------------
Windows Internet Explorer
---------------------------
<EMBED src=http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1& width=500 height=200 type=application/x-shockwave-flash allowfullscreen="true" allowscriptaccess="always"></EMBED>
how can i get "src" value in above code using regular expression?
<object width="500" height="200"><param name="movie" value="http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1&"><param name="allowFullScreen" value="true"><param name="allowscriptaccess" value="always"><embed src="http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="500" height="200"></object>
how can i get "src" value in above code using regular expression?
what will be the regular expression for this line:
Code JavaScript:
var id = $(this).attr("href").substring( $(this).attr("href").lastIndexOf('#'), $(this).attr("href").length);
Basically it gets the string after # in href attribute of clicked anchor tag.
I have this expression:
/(19|20)dd/)[- /.](0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])
to detect if my date:
2010-12-15
is valid. It's not working. What do I have wrong?
When Internet Explorer 5.01 for Windows hits the regular expression:
/(?=<)|>/
it complains about an unexpected quantifier. In fact, it seems to complain whenever I use a lookahead expression. Is there any way around this?
does anyone know how I can build a regular expression e.g. for the
string.search() function on runtime, depending on the content of
variables? Should be something like this:
var strkey = "something";
var str = "Somethin like this";
if( str.search( / + strkey + / ) > -1 )
{
...
}
I need a regular expression that will validate a double quote comma
delimited list where the odd entries are numeric and the even are
alphabetical. Each pair must also be on a separate line. For example:
"1","Peter"
"2","Paul"
"3","Mary"
I've used the following expression to validate comma delimited lists, but
without the double quotes, numeric/alpha pairing and line return
restriction.
^([A-Za-z0-9]?)+([,]s?([A-Za-z0-9]?)+)*$