Regular Expression For A Date?
Aug 26, 2010I have this expression:
/(19|20)dd/)[- /.](0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])
to detect if my date:
2010-12-15
is valid. It's not working. What do I have wrong?
I have this expression:
/(19|20)dd/)[- /.](0[1-9]|[12][0-9]|3[01])[- /.](0[1-9]|1[012])
to detect if my date:
2010-12-15
is valid. It's not working. What do I have wrong?
I have the following regular expression to test the validity of an input date:
([0-9][0-9]|[0-9])[s/-]([0-9][0-9]|[0-9])[s/-]([0-9][0-9][0-9][0-9]|[0-9][0-9])
It should allow 1 or two digits for the day of the month, then a separating character (" ", "/" or "-"), then 1 or two digits for the month, then 2 or 4 digits for the year.
Unfortunately it will accept anything above 2 digits for the year, which I understand why is happening but don't know how to fix!
I have the following regular expression to validate a date-time field
in European or d/m/y h:m:s format.
^((((31/(0?[13578]|1[02]))|((29|30)/(0?[1,3-9]|1[0-2])))/(1[6-9]|[2-9]d)?d{2})|(29/0?2/(((1[6-9]|[2-9]d)?(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))|(0?[1-9]|1d|2[0-8])/((0?[1-9])|(1[0-2]))/((1[6-9]|[2-9]d)?d{2}))
(20|21|22|23|[0-1]?d):[0-5]?d:[0-5]?d$
I wish to ammend it so that the time or h:m:s part is validated only if
supplied (i.e. I wish to make the time part optional). At present if a
time is not supplied the validation fails. I gather that the following
part of the above expression
(20|21|22|23|[0-1]?d):[0-5]?d:[0-5]?d$
validates the time, however I don't know the syntax to make it
optional.
I have seen lot of reg. expession with ?:
For dummy eg
(((XXX)ddd)ff)
The above expression is modified as
(?:(?:(XXX)ddd)ff)
Although both the above expr. gives same result. (RegExp.match() gives
same o/p), most of the places , i have seen second option.
Yes, but different matches r shown (using RegExp.exec())
Is the second expr. most efficient or in particular scenarios?
Any comments???
At the moment my code is like:
function telValid(inString) {
var regexp = /^[0-9 +()]+$/;
return (inString.match(regexp,''));
}
which is use to validate phone numbers (UK at the moment)
this works ok, but wont allow - (Dashes) which i need..
tried doing:
function telValid(inString) {
var regexp = /^[0-9 +-()]+$/;
return (inString.match(regexp,''));
}
I am finding it difficult to find a regular expression for following situation(replace)
a b c d = a,b,c d
a b c = a,b c
regular express to get the file name from a URL?
It has to be flexible in that the extension can be either 4, 5, or 6 chars (.php, .html, .shtml for example) and needs to cater for and whether querystring parameters exist too.
So, both
[URL]
and
[URL]
The regex should return newthread for both.
I.E.:
---------------------------
Windows Internet Explorer
---------------------------
<EMBED src=http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1& width=500 height=200 type=application/x-shockwave-flash allowfullscreen="true" allowscriptaccess="always"></EMBED>
how can i get "src" value in above code using regular expression?
<object width="500" height="200"><param name="movie" value="http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1&"><param name="allowFullScreen" value="true"><param name="allowscriptaccess" value="always"><embed src="http://www.youtube.com/v/JTmM3jut05Q&hl=en&fs=1&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="500" height="200"></object>
how can i get "src" value in above code using regular expression?
what will be the regular expression for this line:
Code JavaScript:
var id = $(this).attr("href").substring( $(this).attr("href").lastIndexOf('#'), $(this).attr("href").length);
Basically it gets the string after # in href attribute of clicked anchor tag.
When Internet Explorer 5.01 for Windows hits the regular expression:
/(?=<)|>/
it complains about an unexpected quantifier. In fact, it seems to complain whenever I use a lookahead expression. Is there any way around this?
does anyone know how I can build a regular expression e.g. for the
string.search() function on runtime, depending on the content of
variables? Should be something like this:
var strkey = "something";
var str = "Somethin like this";
if( str.search( / + strkey + / ) > -1 )
{
...
}
I need a regular expression that will validate a double quote comma
delimited list where the odd entries are numeric and the even are
alphabetical. Each pair must also be on a separate line. For example:
"1","Peter"
"2","Paul"
"3","Mary"
I've used the following expression to validate comma delimited lists, but
without the double quotes, numeric/alpha pairing and line return
restriction.
^([A-Za-z0-9]?)+([,]s?([A-Za-z0-9]?)+)*$
Normally I can write regular expressions decently well but for some
reason I am having trouble getting this to work. I am validating form
data and need to throw an error if there are ANY spaces in the field.
abc123 is fine, abc 123 is not. Any character is fine, just not a
space.
All I'm trying to do is delete the lines which don't contain a particular
string. Actually a filter to edit a log file. I can find and replace a thing
with null, but can't figure out how to find the lines which do not contain
the thing.
Going further, I want to generalize and use a JavaScript variable containing
the decision string, but first I need to worry about the not-within-a-line
problem.
I would like to validate a textbox that numbers cannot be entered into the text input, how do i do this??? With regular expression??
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parseCSVLine = function (line)
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var tmp = [];
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It doesn't have require 12 characters if there is another way to get the number to validate looking like the example above. Here is my regular expression that I am struggling with:
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I have looked for days trying to figure this out and have only gotten close.
I'm trying to validate data in a textbox for township (usually written as 12N or 23S for Township 12 North or Township 23 South). In Utah the townships range from 01N to 15N, and 01S to 44S. The expression "/[0-9][0-4][ns]/i" will allow 01n (or s) through 94n (or s). If I change it to "/[0-4][0-4][ns]/i" to limit it to 44n (or s), I then am not allowing for 05, 06, 07, 08, and 09. I hope the above is not too confusing. I'm just starting to work with regular expressions.
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I have huge amounts of knowledge doing this in PHP but trying out javascript.
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function isValidFirstName(p1_firstName) {
//http://www.javascriptkit.com/jsref/regexp.shtml
var re = new RegExp("[A-Za-z]");
[code]....
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var url=document.myform.addr.value;
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var regEx = new RegExp(str);
[Code]....
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The mounds of RegExp data will take me days to sift through can someone help me create a regular expression to find a file extension? (all characters after a period) I have already gotten this far: .+. to find everything before and including the period; and I was hoping to integrate the caret to say everything but .+. But I just can't get it to work.
Note: I will be writing a file to the server with JScript ASP. The file name will be passed to the script that writes the file, and I want to make sure that in addition to removing any possible code from the line being written, that I also prevent an executable file from being created. I will be searching for certain extensions and returning if anything else is found.
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