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1. What is the benifit of having the above code with "window.onload" and "for loop" and loop through the forms if I only have ONE form in html?
2. What is this line of code "document.forms[i].onsubmit" saying? Does it mean "Execute function() when submit button within form[i] has been pressed?"
3. function() - Does this empty function mean "run every following function below"??
i m trying to call multiple function when submit is pressed.i have tried wrapping the functions as well as onsubmit="return validateForm() && checkdate(mydate)"my 1st function is validating if all the columns in the form are filled or not AND.my 2nd function is validating date text box in my form....i m not able to call multiple functions onsubmit [code]
View 1 Replies View RelatedThis is from long complicated code so I can't show everything but how do I make the function only run if an image/button is pressed?
At the moment everything works properly in Chrome, FF and Safari just not IE. code...
I have piece of the code:
<script type="text/javascript">
$(document).ready(function(){
$('.warning').remove();
$.get("token.php",function(txt){
[Code].....
but when I will submit the form, runthis.php script is not executed.
Hope this is where I'm supposed to post, I'mlookingfor something for my site I'm trying to if a button is pressed a form comes up, I'm also trying to allow this to happen as many times as the user requires.
Eg button is pushed they input text and they hit add more code, they another text box comes up, then when they have done it they hit submit, it then goes through to the database
The following (likely far from imperfect code), reports a value of NaN
in the j4 display. I suppose the problem is I am not really passing
the "checked" value of the radio button via .value ... without having
to get this value via html, is there any way I can passed the checked
value via html .. maybe with syntax like n4.checked.value or
something.. Code:
I have a form, and i want two alternative submit links done as <a> links.Essentially, one will 'save changes' and remain on the same page, the other will 'save and preview' the final content.I've been playing for a while and can't seem to get it to workIf i just use one button and set the form action as normal all works fine.I'm told that i can set the form action within a javascript function and submit the form from there, but the problem is that clicking the link now just goes to the 'href' on the save button without submitting the form. (I believe the href is still required to make a working link).My code is as follows (ive simplified it to the essential components being used, theres also some php bits in the action being set) :
Code:
<script type="text/javascript">
function docSave()
[code].....
I have a form with a series of fields. Only certain fields need to be validated when certain buttons are pressed. The reason for this is mainly because I had to build my own wizard style setup with jquery so, even though it's one big form, only certain bits need to be checked as they progress. I tried to tweak the accordion example given by the creators but it can't really apply to my scenario.
I've simplified the code down a bit and it is behaving exactly the same way as the big form...which is to say it's not behaving at all.
In this code, I want it to only validate field txt1 if button 1 is pressed and text2 if field 2 is pressed. One odd thing to note, when I set it up exactly as the site recommended with one big mass validation and such, it would only acknowledge the existence of the first field even though they both had class="required" on them.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head >
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On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
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I have a form within an iframe that I want to use to refresh the location of the parent. I am using the form to set session variables that are used within the parent. So in the iframe I have:
<form name="MyForm" method="POST"
action="<?php echo $_SERVER['PHP_SELF'] . '?' . SID; ?>">
And to submit this form I'm using this link:
<a href="javascript: submitform()">Search</a>
Which refers to this script:
<SCRIPT LANGUAGE="JavaScript">
<!--
function loadParent()
{
parent.location.href = "/search_results.php?";
}
function submitform()
{
document.MyForm.submit();
loadParent();
}
//-->
</SCRIPT>
(I think!) my problem is this; it works fine if the MyForm action, i.e. ="<?php echo $_SERVER['PHP_SELF'] . '?' . SID; ?>", completes before loadParent() is executed but if there is a slight delay in the time it takes for the server to do this, loadParent() is executed too early and the input from MyForm is lost.
What I need is to tell the script to wait until the MyForm action has completed, i.e. the page has refreshed, before running loadParent(). I'm sure there are loads of different ways of doing this. Ideally I would like something that detects the page refresh within the iframe (caused by the MyForm action) and not something that relies on a timed delay loop.
I have a form on my page, which I want to validate on submit. The code looks something like this:
$('#form').submit(function(){ if ($('#field1').length == 4 && $('#field2').length == 3) {
$.ajax({
url: someAjaxUrl,
dataType: 'html',
type: 'get',
success: function(html){ if (html != '') {
//show error
} else {
//submit form
}}});
} else {
//show other error
} return false;
});
Now, if I try to use
$('#form').submit();
In the else statement within the success function, the validation keeps getting triggered in an endless loop.
But if I use
document.form.submit();
- or document.getElementById('kbaFormSearch').submit(); -
The form gets submitted correctly. Is this because the anonymous callback function within the earlier defined
$('#form).submit()
gets triggered again? And if so, is there a way to get this to work without using "native JS" (not that I'm against it, but it would not make much sense to me unless there is no other way).
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I have the following code and on it's own works fine, but I need to have it in a PHP while loop as there may be hundreds of records. This does not work, meaning it does not submit the form.
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I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I'm trying through a form to display a loading gif when pressed the submit button. I've found on the net this code, but something is wrong. If a keep the id="form33" I can see my loading.gif displayed in place of the submit button, but nothing else happen, form not send. If I delete id="form33", I don't see anymore the loading gif, but my form is correctly sent and after few seconds ping2.php is opened..
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I have form within a form and I would like to disable the submit button in the inner form.Currently I have this for some other forms, and it works just finePHP Code:
<form method="post" action="index.php" onkeypress="return event.keyCode!=13">
<input type="text" name="first" value="" />
<input type="text" name="last" value="" />
[code]....
I'm trying to do is replicate the iPhone's keypad screen. So when someone clicks on the number 1 button, a 1 is appended to the input box above. I have it working in jQuery, but the tablet that is displaying the page is slow to react to each button press. I was hoping if I could have the same functionality without having to load jQuery it may speed things up a bit.
View 2 Replies View RelatedI am trying to hide/show table when hide/show button is pressed
Problem: The code works fine when I remove 'slow' from line 10. But with 'slow' in line 10 content of toggleButton doesnt change from Hide to Show when pressed.
Code:
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
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when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
I have a very simple form. I start with the submit button disabled and once all of the fields have been validated I would like the submit button to enable. I only have required fields so the standard options that come with the validation plugin satisfy my needs. I only have this code along with the corresponding classes.
$(document).ready(function(){
$("#myForm").validate();
});
[code]....
I am trying to create a button that when clviked on it will pop up 9 error boxes at random and the user clicks onthem as fast as he/ she can and when the error oxes are done there is a message that asks if you want more here is my code:
View 1 Replies View RelatedI have my form working great as long as my submit button is contained within the form tags. But the design calls for the submit button to be outside of the form. Sample code and diagrams are below.
<form>
my form here
</form>
<div> </div>
<div> Submit button </div>
[Code].....