I show a form in the modal pop up which has several drop down lists in it. The problem is that if i select nething from the drop down list then my selected index change event fires and my form gets refresh..how to overcome this problem??
Can we use modal pop up wherein there are multiple post backs?? I also tried adding update panels etc.
I have created an entry form that I display in a modal dialog. I have two buttons on the form: "Add and close", and "Add and allow me to add another". However the only time my modal form will post back to the server is after the form has been closed. I want to do the following: The user opens the form in a modal dialog. The user enters data, and clicks the "Add and allow me to add another" button. The page sends the user input to the server, which adds the input to a database and updates a datagrid on the page. This updated datagrid is visible behind the modal form, so the user can see it happening in the background The form clears all input fields and the user goes again. Any code I write that calls the server (button click events, ajax calls, etc) are ignored, unless the modal form has been closed.
View 1 Replies View RelatedI have several form inputs with a submit link in a modal page, and when I click the submit link I call this function to download a personalized pdf with the GET params.
function download(){
window.parent.document.location = "admin.php?controller=Cat&action=downloadPDF&title=" + $("#title").val() + "&author=" + $("#author").val() + "&coment=" + $("#coment").val();
[code]....
I am trying to write code to allow a person select one photo to be their base image or Front cover image on a photo album. I am using jquery .post to get the form check box values which are the image file names and then use post to throw them to a php file and then update the database.
Now thats cool so far and that part works. Now the problem is that I need the main photo album picture to be replaced once the .post if completed or succeeded. I need to refresh the main image. Right now the only way to do it is to hit the refresh button on your web browser. Yet I want to do this without refreshing the page.
The Image displayed already is in a image html tag with a id named user_main I was thinking is it possible for .post to pass back to javascript a variable that has the image source and is there any way to update that image tag easily like where it says src="path to image" is located.
Would like to know the best way to refresh the image without having to refresh the page.
I have many tags. I want click each tag, then post/get the tag's value to another page. In another page, received the values and make a mysql query. Then return the resalt data to the first page(do not make an iframe).
[Code]...
I am trying to create dynamic content using append and appendTo functions. It seems to work fine and I can see the new elements on the fly using a Button to execute a customized function based on this jquery methods. something like this:
$('<div id="page-contents2"></div>')
$('<form class="cmxform" id="form1" method="get" action=""></form>')
.prepend('<div>TITLE HERE</div>')
[code]....
the problem is that when i refresh the page the new content disappear of the DOM.
I've been trying to figure out how to echo back error messages from a PHP edit page, for example. Say if I am editing a grid and sending that info with json to a php page to update a database, if there is a validation or other problem, how do I echo that back on the page with the jquery? Do I put that in a div container too for best practice?
View 7 Replies View RelatedI am struggling to produce a script that will call ajax content intoa uimodal dialog every timea relevant link is clicked. I wish to use multiple links calling different ajax content into mutliple useuimodal dialogs from a single page
View 2 Replies View RelatedI have adrop-downelement on the page. On the change event I am appending two labels to a text box. The problem is I am able to see the newly added elements on the page while debugging it. but as soon as thepost backoccurs the added elements seems to bedisappearingfrom the page.
View 6 Replies View RelatedIs it possible to post all (or more of one) forms simultaneosly?
document.forms.submit?
function ShowAvailability() {
View 1 Replies View RelatedI got this code that dealing with ajax..Basically the ajax code is to get the data from the html element and insert it to the database.
this is ajax and the html code ...
I'm struggling with a script for an e-commerce site.When the user clicks the add to cart button they are currently taken to a PHP shopping cart page, but the client wants them to stay on the same page after they press the button and get notified that an item has been added to the cart.The add to cart button is a form submit button, because there is also a quantity field for each item. I would have cracked this by now but there are multiple add to cart buttons on each page and when I submit the form only the data from the first form in the page is sent to the cart page.Here's a dummy version the JavaScript:
Code:
$(document).ready(function(){
$('.subbtn').click(function(){
$('<p id="add">Added To Cart</p>').insertAfter(this).fadeOut(3000);[code].....
At the moment I've got it set so that AJAX returns information to the page (just so I know it works), but this won't happen on the actual page.So, as far as I can tell, I need a way of POSTING $(this).parent(); $('[name=quantity]').val(), but I can't seem to find the correct syntax.
I know how to submit via a text link, using document.frmname.submit(), but you can not attach a value to the A tag, so you can't have several submit links within one form.
I need to do this however! I want to have several text links within one form - submitting to the actionpage, and based on the value of the submit, it will do something different.
Ok, so I know I can do this without problems using the input tag and submit buttons, or I could use seperate form tags for each link, but that would mean a lot of repeating code, and I want to make this as compact as possible.
I have a working code which allows the user to select one or multiple options from a drop down. Text appears alongside depending on their selection. I need to find a way for another area or text box to be populated depending on the original option(s) selected.
Example: At the moment if the user selects �Orange� as their favourite colour and submits it will display the text �Oranges are Orange� alongside. This is displayed within a <div>. I want it to also display another piece of text, for example �Oranges are a good source of vitamin C� in a seperate <div> and then another <div> showing �You should eat at least one orange a day�.
This must also work with multiple options. I am sure there is a way to use hidden values etc but I am stuck!code...
I have a problem where if a form submission (set up to submit via AJAX) fails validation, the next time the form is submitted, it doubles the number of post requests - which is definitely not what I want to happen. I'm using the jQuery ValidationEngine plugin to submit forms and bind validation messages to my fields. This is my code below. I think my problem is that I need to unbind from the validationEngine plugin when the form fails, but I can't figure out how to do this.
[Code]...
I am new to Jquery and am having trouble. I want a button on a modal form to open up another modal form but for some reason it isn't happening. The code below is basically the code from the jquery user interface demo, slightly modified. can anyone tell me what I am doing wrong? if your kind enough to take a look at my problem make sure you change the src's where the JQuery files are!
Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
[Code]...
I'm looking to have a lightbox pop up when a user clicks the Back button in their browser rather than just navigating back. The purpose is to ask a question with a Yes/No answer, and if they click No, I allow them to go back. The only thing I've found anything like this is the onUnload event, but that doesn't prevent them from going back. How should this be handled?
View 1 Replies View RelatedI am trying to write a script that uses the IF statement to see wether or not a user clicked the back button to come to a page, and then if it's true to not let the page load and kick them back X number of pages (say 4) This is what I have so far:
<script language="JavaScript"><!--
if javascript:window.history.back == 1
{
javascript:window.history.back(4);
return false;
}
//--></script>
I want to run an external function outside the post.
This is what I have currently.
On success of the post I want to run the setGrandTotal(); function which will do some calculating for me.
How can I post array of controls through &.post() in jQuery??I have some of checkboxs in my page and declare them like this
<input name="mycheckbox[]" "value="myvalue" type="checkbox">
I can get it works if I using <form> tag with an action="post" and a submit button to post to another php page by using this statement to get all controls in receiver's page _GET['mycheckbox'];I have tried
$.post('ajax/test.php", {checkbox: $
(
'input[name="mycheckbox"]'
)});
[code]....
I just started using jQuery, but i can't get it working. On the index.php page I want a search form, that post's to search.php. Following next, I want that the html of search.php (which will only be a table with the results), is show into the 'results' div in the index.php.
This is the code im using:
<script type="text/javascript">
/* attach a submit handler to the form */
$(document).ready(function(){
alert("Ok - 1");
[Code].....
The alert's are for debugging, but none of them show's up.
[Code]....
how do i cause the form to post to another page? Am I doing it correct? I want this to happen ONLY if validation passes.
I have a webpage popup (lets call it POPUP) which refreshes the opener window (this one we call PARENT) when we close it, saying we want to save data. For this, we use
top.oWndOpener.refresh();
When we don't want to save the POPUP data, we just close the popup and
don't refresh the PARENT. In the PARENT we have a "Back" link which executes a simple
history.back()
The problem is:
If we refresh parent, we need to go back 2 pages, because the refresh
method adds another page to the history. But we have no (easy) way of
knowing in the PARENT if it had been refreshed. With this, our users
are forced to click two times in the Back link.
Is there anyway of going back to the previous page, no matter how many
refreshes happened in the current one ?
I have been trying to utilize a pre existing snippet of JS that makes a call to some PHP, where the PHP echo's out the answer, namely a dynamic quick search output, that gains its data from an xml file (which works as expected) and thought I might be able to rework the code to work for my altered purpose (which has been a disaster at every attempt) which is as follows:
1. I have a JS file called call4section.js - JS that has a string (str) value assigned (could be number or a combination of numbers and letters) which is passed to a PHP script called call4section.php.
2. The PHP script takes receipt of the string and finds a match within an XML file for the entry under <reference>.
3. The XML file has a format as follows:
<pages>
<note>
<section>value</section>
[code]....
And well, I dont seem to be able to get any further forward with it. Effectively, I can echo out the $reply (if it worked I think), but my stumbling block is sending the starting string, with the JS expecting some reply sent from the PHP.
I am trying to capture the back button and redirect if it is a certain URL, if not just go back like a normal back button.I've never really messed with the history except for something like this: <a href="#" onClick="history.go(-1)">Anyone have an example using this plugin: [URL]r any other plugin that might achieve this
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