I am using an ajax call to generate a new image with some text across it. How can I "replace" the image in the current page with the one I just generated, they will have the same name.
View 4 RepliesI have page with an Ajax request which returns an entire <hml>..</html> page and I would like to use this response data to replace the current page. I wrote the following :
$.ajax({
type: "POST",
url: URL,
data: formData,
[Code]....
I need to do is take the current page's url and replace/add a bit into the URL at the appropriate place.For Example, if this is the Current Page URL:http:[url]...I want to be able to use the bookmarklet to change it to:http:[url]....This is all I've got for it so far. Probably botched that up too. : javascript:(function(){var%20a=document.URL.split([url]....
View 7 Replies View RelatedIm trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear).
However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that this blank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably.
I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
-I found this---but havent figured out how to implement it in my scenario:
Source: [url]
-I found this---but havent figured out how to implement it in my scenario:
Code:
Source: [url]
I'm trying to get the hover over image selected based on the current page. I've used an external jquery.url.js library to access file and href information. The if statement is reached correctly, but I can't get the code within it to work. Each image is stored within an anchor and, as with the hover code (included), I'm trying to change the end of its source file name from '_off'to '_on' so it's active.
$(function () {
$("img.rollover").hover(
function () {
this.src = this.src.replace("_off", "_on");
},
function () {
this.src = this.src.replace("_on", "_off");
});
$page = jQuery.url.attr("file");
$('#menu tr td a').each(function () {
var $href = $(this).attr('href');
if ($href == $page) {
$("img", this).src.replace("_off", "_on");
}});
I am trying to define an "onclick" event to a form button, so that when I click this button, content from another webpage will overwrite this page (not open a new webpage). I've tried the below code (sample) which is not working.
<form action="/script" method="post">
<..other elements../>
<input type="button" name="jump" value="Jump" />
</form>
<script type="text/javascript">
$(':button[name="jump"]').click(function() {
$(document).load('/path/to/another_page.html');
});
</script>
I'm trying to create two bookmarklets:
1. Take the current URL of the page and open a new window with a URL based on the current page. Some examples (I use "->" to mean "this URL turns into that URL"):I plan to use these bookmarklets in sequence, first pressing 1 to log into the CMS, then pressing 2 to edit the current page.
I've created a nav bar for this site - [URL].. I'm using javascript to handle the image rollover which is working just fine. However I want to add to this so that the current page will stay with the second or rollover image. How would you suggest I edit or add to my code so it keeps the second image active if it is the active page? In my script file this is what I'm using for an image:
menu1buttonup = new Image();
menu1buttonup.src = "http://web11.3essentials.com/~cp27358/wp-content/themes/origin/images/menu1.jpg" ;
menu1buttondown = new Image() ;
menu1buttondown.src = "http://web11.3essentials.com/~cp27358/wp-content/themes/origin/images/menu1a.jpg" ;
[Code]...
I've created a nav bar for this site - [URL] - I'm using javascript to handle the image rollover which is working just fine. However I want to add to this so that the current page will stay with the second or rollover image. Do I edit or add to my code so it keeps the second image active if it is the active page?
In my script file this is what I'm using for an image:
menu1buttonup = new Image();
menu1buttonup.src = "[URL]" ;
menu1buttondown = new Image() ;
menu1buttondown.src = "[URL]" ;
Followed by....
function buttondown( buttonname ){
if (document.images) {
document[ buttonname ].src = eval( buttonname + "down.src" );
}} function buttonup ( buttonname ){
if (document.images) {
document[ buttonname ].src = eval( buttonname + "up.src" );
}}
And this is what my list items look like:
<a href="<?php echo home_url(); ?>/?page_id=7" onmouseover="buttondown('menu1button')"
onmouseout="buttonup('menu1button')"><img src="<?php bloginfo('template_url'); ?>/images/menu1.jpg" name="menu1button" /></a>
Im trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear). However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that this blank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably. I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
- I found this---but havent figured out how to implement it in my scenario:
- I found this---but havent figured out how to implement it in my scenario:
Source: [url]
I have done this simple function, it seems to work as intended, to
solve a problem i have had for a while. I couldnt find any sample
around that was working for me.
It should be fast and if possible compatible with todays modern
browser-standards. It should be activated by the onload-event. Code:
My requirement is, I have multiple pages in tab format. If i am on first page in edit mode and change any control's value and without saving information i click on other tab that particular time a popup should appear showing validation message say "you are moving without save and it will loos all changes either click ok to loose the changes and move to other page or click cancel to remain on the current page."I tried using var isDirty = false; var msg = 'This page has unsaved changes.Click OK to abandon the changes and leave the page.Click Cancel to stay on the page so that you can save your changes.';
$(document).ready(function ()
{
$(':input').change(function ()
[code]....
I'm looking to create previous and next image links. The images are brought in via JSON. $('<img />').attr('src', photo.thumbnails["500x500"]).appendTo('.img-full');
Does anyone know how I go about getting the current image and then the ability to click next to find next one?
I am using a Jquery/PHP/MySQL login script which is supposed to display an error or success message when the user enters their username/password and also if the username/pw is successfull go to a secure page. Right now as I have it coded, this isn't working properly. Basically nothing is displayed either way.Also,wasn't sure if I just needed to replace, the ?secure-page part with the file name of the page I want to go to if successful?Here is the code as I have it now.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>[code].....
how to post dat from curent page to another php page using jquery
View 2 Replies View RelatedI write simple slideshow on jQuery but I can't understand how to change current image count. Here is my current code:
HTML Code:
<script type="text/javascript">
$(document).ready(function(){
$('#slideshow img').hide();
$('#slideshow img:first').show();
function slide(){
var $top = $('#slideshow img:visible');
var $next;
if ($top.next().length > 0)
$next = $top.next();
else
$next = $('#slideshow img:first');
$top.hide();
$next.show();
}
var $imgCount = $('#slideshow img');
var $iCount = $imgCount.length;
$('#slideshow img').click(slide);
$('#totalImages').text($iCount);
});
</script>
I'm trying make like this 2/45, where 2 - is current image number.
I'm trying to achieve something (which doesn't seem to difficult to me) but I can't get it to work. I want to embed video's through a swf-videoplayer on my website. The idea is that I have (say 750 * 400 px) images wrapped in links. The links point at the videofile. If the user clicks the link, I want to replace the link+image by the swf video with the same dimensions...
View 2 Replies View RelatedI need to load a different image after, lets say 10 seconds.
So image1.gif will be displayed when the page loads then after say 10 seconds image2.png will replace image1.gif.
I am trying to make a generic function called whenever the window size changes. I want this function to apply to several different images. The idea is that when the window is resized the function will only change the end of the source code by replacing "_small", "_medium", "_large" with the appropriate size depending on the window. The problem is that when I use the code below it makes ALL of the images the same. The variable imageRightIdStr genereates a list of ids of all of the images that I would like this function to affect. ex: #imageRight101,#imageRight201,#imageRight202,#imageRight203,#imageRight301 etc.
Here is the code that I have now. It mostly works except it makes all of my "imageRight_" images the same.
var contentwidth = $('#background').width();
if ((contentwidth) < '1175') {
var logo= $('#pageLogo');
var rightImage = $('.rightImage');
logo.attr('src',logo.attr('src').replace('_large','_small'));
logo.attr('src',logo.attr('src').replace('_medium','_small'));
$(imageRightIdStr).attr('src',$(imageRightIdStr).attr('src').replace('_large','_small'));
$(imageRightIdStr).attr('src',$(imageRightIdStr).attr('src').replace('_medium','_small'));
}else if ((contentwidth) < '1440' && (contentwidth) > '1175') {
var logo= $('#pageLogo');
var rightImage = $('.rightImage');
logo.attr('src',logo.attr('src').replace('_large','_medium'));
logo.attr('src',logo.attr('src').replace('_small','_medium'));
$(imageRightIdStr).attr('src',$(imageRightIdStr).attr('src').replace('_large','_medium'));
$(imageRightIdStr).attr('src',$(imageRightIdStr).attr('src').replace('_small','_medium'));
}
I'm having trouble doing an image replace. When you click on the thumbnail link to replace the large image, it opens in a new window instead of replacing the current image.
View 1 Replies View RelatedHowever, I just want to add a small bit of functionality to a new site to make the waiting site owner happy.As you can see here, I got a big image of glasses on the top right of the home page.I do this with CSS only:Html:
<div id="teaser-right"></div>
CSS:
div#wrapper #content #teaser #teaser-right{
[code]....
Is it possible to replace this logo's 2-image fade code...
... with a JQuery equivalent? If so, could someone point me in the right direction as I'm new to JQuery.
I've got 2 pages: a current events page and a past events page the current events page loads fine as there is only about 10 events the past events page takes about 30 seconds to load and will crash if u click your mouse in the loading time.
The pages are near identical the only difference is the query that selects the events (> versus <)
The page loads immediately without:
But when i put it back in the above happens. I'm using jQuery.roundedcorners.
I am writing a script that will replace the src of an image when the user hovers over it. I am using jquery and regex to accomplish this and have tested it on my local server but the src of the images on the live server is different and uses a non-relative path.
Here is my code
$(document).ready(function() {
$("img.imagefield").mouseover(function() {
var regex = "^(http|https|ftp)://[a-zA-Z0-9-.]+.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/sites/all/files/[a-zA-Z]*";
var src = $(this).attr("src").match(regex) + "_silly";
[Code]...
I was searching for this and found only: var local = window.location.href; Is there any other way to achive this?
View 5 Replies View RelatedIm looking to basically have an image which is a button with a value, and when i click the image, it gets replaced by another image with a different value. when clicked again it would return to the original image and value..Is this possible? and if so, please help cos im terrible at javascript!
View 3 Replies View Related