I'm trying to display a record in a div(message) based on a user selecting the corresponding button.
Basic syntax is:
<button value=1>Review</button>
<button value=2>Review</button>
<button value=3>Review</button>
<div id="message" name="message"></div>
I'm using the code below but for some reason when I click a button nothing happens.
[Code]...
I have a search form that uses AJAX to fetch data and populate a table. Several of the search fields are multiple selects. Problem is, only the first option is getting passed thru to the PHP file called by the AJAX function.
var fs_users = $("#users"), fs_status("#status"), fs_roles("#roles"), ...;
var fs_allFields = $([]).add(fs_users).add(fs_status).add(fs_roles)...;
$("#fsSearch").click(function() {
//alert(fs_roles.val());
[Code]....
For debugging purposes, the target PHP file ("fetch_data.php") dumps the $_POST and $_GET variables to a file. As mentioned, only the first option from the multi-selects is getting passed thru in the $_POST variable ($_GET is empty as expected). The alert (line 4) will correctly display a comma-delimited list of all the selected values (also verified via Firebug while stepping thru the code). Someone in another thread suggested using serialize() (e.g. line 9 becomes "fs_allFields.serialize()", but that caused NOTHING to get passed thru.
Maybe I've been staring at it too long and there's a simple fix is right in front of me, but I just can't see it.
P.S. I'm using the latest versions of jQuery and jQuery-UI.
So far i managed to show/hide (the only) 1 textarea if an option is selected, using javascript. How can i show all textareas in form if an option is selected (lets say <option name="active">) and hide if option selected is name="passive"?
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If an option is selected, can i have jQuery post an extra $_POST variable like "new" or "existing" so I can pick it up on the submit.php page? Or when an option is selected, can I have .js write a hidden tag which contains the variable "existing"?
[URL]
index.php
Code HTML4Strict:
<script type="text/javascript">
function findValue(li) {
if( li == null ) return alert("No match!");
[Code].....
The end goal here is to post a variable on the next page if the user selected an option from the autocomplete list.
I need to do multi DOM manipulation into a page without reload it (something like: when i click on a thum in another part load a photo with a specific text, if i click on this text load another photo).
I use a js like:
First page loading everything goes good.... but when i fall into MY_CODE1, i can't execute MY_CODE2 anymore.....
i need to post data from a form to a page on another domain, without leaving the current page.I am using ASP as a server language.
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how do i cause the form to post to another page? Am I doing it correct? I want this to happen ONLY if validation passes.
I have the following bit of jQuery:
Code:
$("#save_photos_all_continue").click(function() {
event.preventDefault();
var $black_white_all = $("#black_white_all").is(':checked');
var $color_all = $("#color_all").is(':checked');
var $other_all = $("#other_all").is(':checked');
[Code]...
In Google Chrome it works fine but in Mozilla/5.0 it actually goes to the save_edits page instead of just using the post and staying on the original page.
I´m trying to get multiple slide shows on one page (3 beside each other) using JavaScript.
I took the code from http://www.dynamicdrive.com/dynamicindex14/pixelate.htm
for creating the slide show, everything is working fine but I can´t change the code to work with multiple slide shows on one page.
I have found a great bit of javascript that I want to use on my site but I want to use it three times on the same page. If you look at [URL] you see three pictures at the bottom I want to make them change but the first only has four images the second has five and the third has three so I want to use the same code below on them all separatly.
Code:
<script type="text/javascript">
// Flexible Image Slideshow- By JavaScriptKit [URL]
// For this and over 400+ free scripts, visit JavaScript Kit-[URL]
// This notice must stay intact for use
var ultimateshow=new Array()
//ultimateshow[x]=["path to image", "OPTIONAL link for image", "OPTIONAL link target"]
ultimateshow[0]=['images/rotate/tattoos/main-tattoo1.jpg', '', '']
ultimateshow[1]=['images/rotate/tattoos/main-tattoo2.jpg', '', '']
ultimateshow[2]=['images/rotate/tattoos/main-tattoo3.jpg', '', '']
//configure the below 3 variables to set the dimension/background color of the slideshow .....
how to post dat from curent page to another php page using jquery
View 2 Replies View RelatedI am creating a very content rich news/media website that requires an audio player. The audio player should be seen by the user as soon as they enter the website and the playlist should play throughout their time spent at the website and should not be restarted or stopped when navigating the website.
We originally were using a frameset for the audio player, but the fact that none of the pages through out the site could be reached through a link in the URL bar proved to be too much of an issue.
So the new idea was to open the audio player in a javascript pop-up window. But because of the nature of the website, we found that it was very common for users to go "back" in their browser to the homepage after they had navigated away, which would cause the pop-up code to be activated again and would make the pop-up reload, interrupting the audio.
So then we moved the pop-up code to the splash page so that when you enter the main page, its already open, and it can't be interrupted. But THEN we found that the pop-up window was of course opened behind the main website's window, which made it hidden and useless.
So we currently have no solutions! All we need is for this pop-up window to take focus and be the very top window, and once its opened to never be reloaded/refreshed again.
how to send data to another external php page from current php page and also get the html code from that external php page.
View 4 Replies View RelatedSo what I thought was going to be really turns out to not be working for some reason. I'm setting up a shell for my new site. So I'm just trying to get some of my pages linked together for testing the site flow and feel. I want to do this with javascript (jquery) because when I start passing session data that's how I'll be handling this.
So I have this simple line in my js code...
$('#submit').click(function(){
$.post("plans.html");
[code]....
Is there a way to post from a .net page with server form controls using the jQuery .ajax method? The .net page is expecting the server contols so I'm not sure how to handle it so when I serialize() the form it doesn't know what to do with it.
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on the click of the input=Submit, if is selected "Insert New User",
how can I redirect the user to another page (.aspx, .ascx, .html, etc) where he can insert the new values?
I trying to make a simple image gallery, where I have several radio button groups to filter the search results. I have tried this code to create an associative array, but the array comes up as blank.
$
(
'input:radio:checked'
).
each
[Code]......
I'm new to using JQuery and I've been searching everywhere to be able to post XML to a WebMethod on an aspx page in a site. I'm sure it can be done but I just have no idea how.
View 2 Replies View RelatedI am trying to use JQuery to submit a form without reloading the page. Although this works well with thejQuery Form Plugin on a standalone page I need it to work on a page I've loaded with AJAX.[code]...
View 2 Replies View RelatedI'm struggling with a script for an e-commerce site.When the user clicks the add to cart button they are currently taken to a PHP shopping cart page, but the client wants them to stay on the same page after they press the button and get notified that an item has been added to the cart.The add to cart button is a form submit button, because there is also a quantity field for each item. I would have cracked this by now but there are multiple add to cart buttons on each page and when I submit the form only the data from the first form in the page is sent to the cart page.Here's a dummy version the JavaScript:
Code:
$(document).ready(function(){
$('.subbtn').click(function(){
$('<p id="add">Added To Cart</p>').insertAfter(this).fadeOut(3000);[code].....
At the moment I've got it set so that AJAX returns information to the page (just so I know it works), but this won't happen on the actual page.So, as far as I can tell, I need a way of POSTING $(this).parent(); $('[name=quantity]').val(), but I can't seem to find the correct syntax.
Anyone have any code examples or tutorials on how to implement POST's on the pages that each of the jQuery's Ajaxified tabs loads? Mainly looking for examples of the tab content pages post'ing/get'ing params.
here's an example of the stand-alone page that functions normally:[URL]...(select Oct. 8th, 2009 to see example or POST in action)
but when popped into an Ajax jQuery tab, the POST doesnt work[URL]...As you can see, on the second example, when the page POST's, it's no longer running in the tab. How do i get it to just refresh/POST within the tab?
[edit] i reformed my question above [/edit]
I have some trouble with my app. User enters his login&pass, they are being checked on server using ajax, and if they're ok, i wanna open new page, which'll set cookies and session vars, but i have an universal script, and I need request something like universalScript?mode=login (mode is GET) and some POST parameters such as login and pass, besides it must be new page, not ajax, Some ideas?
View 2 Replies View RelatedThis is my first post, and I'm only just learning jqury/JavaScript.
i have a form I'd like to send via POST method to a second php page, i have all the validation etc working fine, I'm struggling with the on Submit handler.. once the form is validated...
can anyone please tell/direct me how i can post this form to a php page that will do the data insertion?[code]...
Using Jquery Cycle Plugin i have multiple containers on the same page. they have a next and prev button. the problem is, when i click the next button it will cause the containers on the pageadvance simultaneously, same goes for the previous button. it works fine when i click just on the images (they will go to the next image) but not with the prev. and next. button. i know i have to add some kind of var. to it. and i tried it but with no luck.
Here is my code.
$('div[id^=slide]').each(function(index) {
$('#slide'+ (index+1)).cycle({
fx: 'fade',
speed: 'fast',
[Code].....
How to get post data from a page loaded in iframe in parent page
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