Does anyone know how to receive an image as "image/png" type in a Javascript function which receives an Ajax response?What I have is:
Code:
function getResponse() {
if (xHRObject.readyState == 4 && xHRObject.status == 200) {
var serverText = xHRObject.responseText;[code]....
which of course returns the characters the image is made of.
capturing just the file name rather than the entire path of the SRC on my input type="image". Basically when I hover over an image, the Default Image should change to the image being hovered on. Here is my code, can't quite get it to work. Sorry I'm very new to JavaScript
<html>
<head>
<script language = "Javascript">
function ChangeDefault(src)
{
//document.frmMain.DefaultImage.src = src <--Doesn't work at all
alert(src) //<---Displays the entire file path, want just file name
[Code]...
Before I waste time trying to achieve this, could someone possibly tell me whether it is in fact possible to upload an image using the jquery ajax function?I have seen examples on google but they are not too clear how they achieve it.
View 5 Replies View RelatedI want text links to swap the image on the website, but then want to allow a zoom function or lightbox function to the image that appears. I'm not best at explaining things so i've done an example below. After clicking the link, the image changes. i want to be able to do the zoom on the image that it's changed to.
View 1 Replies View RelatedI have an ajax call that sends some data to process.php and return back the image name. In process.php I returned the name as follows:
echo "image.png";
The ajax call is:
var $chart = $( '#chart' );
var $test = $( '#test' );
[Code]....
so from test div i get the path printed right: (./images/image.png), but I don't get the image to be desplayed
i am using ajax to retrieve the img url path how am i going to use the img url path i retrieve and display as a image and i using javascript language anyone know? how to do that i try the follow way but don't work what wrong?
Code:
var descIg = "";
descIg += rssent[i].descImg;
var placeImg = document.createElement('img');
placeImg.src = descIg;
I noticed that the image input type does not show up in the elements
array (IE 6.0).
<FORM name=myForm>
<INPUT name=rads id=check1 type=radio value=val1>
<INPUT name=rads id=check2 type=radio value=val2 checked>
<INPUT name=rads id=check3 type=radio value=val3>
<INPUT name=rads id=check4 type=radio value=val4>
<INPUT name=imgIn type=image src=web.gif>
<INPUT type=button name=somethin>
</FORM>
If I have this HTML code, the myForm.elements.length is 5, instead of
the expected 6. You can click on the image in this case, and it acts
like a submit button... proof that the broser recognizes it as part of
the form.
So, if I call myForm.elements[4], I get the button, not the image.
It seems goofy to me, and I cannot find any documentation that explains
why this is.
Of course, I can get access to the object in many other ways... I am
just curious if the is an IE bug.
only first image in the all_images array loads and the rest stays hidden. it works first time i load the page, but any other time it loads only one image. i understand it might have to do with the cache. what could be possible cause for breaking the .each() loop after first iteration? i'm using jquery 1.3.2, png fix and php
[Code]...
When I click on the image form element
<INPUT type=image name=point src="map.png">
point.x and point.y values get submitted to the server
specifying where on the image I have clicked.
Is there any (simple) way to get ahold of that point.x and
point.y BEFORE they are sent to the server (and prevent
that from happening)? Ie. I just want the points where
someone clicks on an image and not interested in a submission
to the server.
i have a problem with the input image type. they act as submit buttons right. but i hav 2 in one page. so its like having 2 submit buttons in a single page. lets name it.. BUTTON_A and BUTTON_B. BUTTON_A has some calls a javascript that needs to submit the page but does not do the main process. BUTTON_B is the real submit button for the form..heres the problem...when i am in any text input field and press enter, it is like i clicked BUTTON_A...what i want to happen is when ever i press enter it clicks BUTTON_B. i believe the problem is becuase BUTTON_A comes first of BUTTON_B. what do i do?
View 2 Replies View RelatedCan anyone tell me how I can recieve a PHP array after running $.ajax()? [code]...
View 5 Replies View RelatedI'm having a problem with Windows Mobile 2003 and AJAX. I'm using Windows Mobile 2003 because it is the earliest version of Windows Mobile I'm willing to build support for.
Basically, in Windows Mobile 2003, AJAX doesn't work if your response is only one character.
So I want to know if I can append something to the response string so I don't receive an error?
I would hate to have to re-program all the thousands of lines of code I have just because Windows Mobile 2003 isn't working.
I've already tried doing:
xmlHttp.responseText += "0";
This doesn't work because IE will throw an error since I cannot do anything with "responseText" since IE does not think AJAX is done (even though status = 200, and readyState = 4) because the responseText is too short. I tried it with two characters instead of one, and it started working again, so I know this is the bug.
When responseText is only one character, the typeof(xmlHttp.responseText) is unknown, but when it's at least two characters, it will show the type as "String."
var req = createXMLHttpRequest();
function createXMLHttpRequest() {
var ua;
if(window.XMLHttpRequest) {
try {
ua = new XMLHttpRequest();
} catch(e) {
ua = false;
}
} else if(window.ActiveXObject) {
try {
ua = new ActiveXObject("Microsoft.XMLHTTP");
} catch(e) {
ua = false;
}
}
return ua;
}
function sendRequest(frm, file) { .....
I have a web service that accepts application/json but returns HTML to place in a DIV. I am not having any luck configuring the .ajax call so that it both POSTs in a format accepted by the web service and does not attempt to validate the HTML response as JSON.
[Code]...
It would seem that I cannot have anything other than 'json' in the dataType, even though from the docs it appears that this only affects the interpretation of the response, changing it's value to 'html' causes the web service to reject the call. I've also tried a converter but perhaps I'm not using it properly. Is it possible to use jquery to post JSON and get back HTML? What configurations am I missing?
When using .ajax, and when before I receive any data back from the server, I would like to call a function that could display some type of 'thinking' icon. In looking a the documentation I see there is a 'success', for when after receiving data back successfully, and an 'error', for obviously when something bad happens and need to error gracefully. I do not see something like a 'beforeSuccess' function that would allow me to specify, for example, to overlay a 'thinking icon' on top of a <div> after request is sent to the server and before I get any data back. I would assume this is a pretty standard necessity in ajax applications, and probably missing something here. How exactly is this done using the .ajax methods?
View 4 Replies View RelatedI want to have a big image and say 5 small thumbnails underneath. When the user clicks a thumbnail, the image loads where the previous big image was. Is there a standard way to do this?
View 3 Replies View Relatedi have image button i need to display image .if the size of the image button is 100*100 and image size is 50*50 .the remaining space of the image button should be empty.the image should not stretch.
View 1 Replies View RelatedIm trying to have a click event that replaces an image on the page with a new image that has been selected randomly from an array. I have solved PART of this already (can get the random image to appear).
However, instead of appearing on the page where the old image was, the new image appears in a blank page.
My research indicates that this blank page location-problem is a result of using document.write in the Function. Therefore, I know I need to find a different way to accomplish this, but am failing miserably.
I have been trying for hours and hours and HOURS to figure out proper syntax for accomplishing this via elements, functions, variables and mootools.
A bit of my research:
-I found this---but havent figured out how to implement it in my scenario:
Source: [url]
-I found this---but havent figured out how to implement it in my scenario:
Code:
Source: [url]
I'm working on a 'live search' for some products in my database. I use a web method in an aspx page to hit the database up for data. The search fires off on each keyup event.
Here's the code that is fired to get the search results:
My problem is that when a user types in the input field really fast, the whole page slows down, it looks like the user isn't typing and there is a lot of lag for the cursor to catch up with the current position. What can I do to prevent this slowdown in my input field and speed up my page responding to the user's typing? I'd really like to have fast results and response time like Google's search.
I have to change text input type to password input type and i am using jquery script. This script work for FF, Chrome and Safari browser but not worked on ie7, ie8.
Script is as:-
How can i update my script, so that it works cross the browser.
I am trying to add a pulldown menu with a button to my website. I have successfully done this with a javascript I found online here to give credit: [URL] I tried to modify the form so it will use an image file instead of the default button. To troubleshoot I took the relevant code and put into a seperate html file. This one is using the default code from the site referenced above. This is the page published online: [URL]
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
[Code]....
Code:
$html .= '<div id="submit"><input type="image" name="subscribe" onmouseover="this.src='images/1_hv.jpg'" onmouseout="this.src='images/1.jpg'" src="images/1.jpg" value="'.$data["button"].'" onClick="return checkform();"></div> ';
why the type="image" code can't work under IE? when i click the image under IE, it can't work. it can't submit the form. but under firefox and chrome.it can work. how to correct it ? when i change the input into
Code:
<input type="submit" name="subscribe" value="'.$data["button"].'" onClick="return checkform();">
when under IE,firefox,chrome. all can work
I use an image button to post a form. Let's say the button is on A.php and form target is B.php. when clicked, B.php comes but with extra arguments in the url. As far as I understand they are the coordinates of the point I clicked on the button image.
<input name="image" type="image" class="search_button_big" title="Search" value=" " src="img/dot.png" />
....B.php?image.x=38&image.y=24ℑ=+
When I remove name property additional arguments in the url simplifies as follows:
<input type="image" class="search_button_big" title="Search" value=" " src="img/dot.png" />
...B.php?x=78&y=31
How can I prevent these x and y's?
Does anyone know of an easy to implement ajax upload script for php
which also has a progress bar. If possible I'd like it to be able to
remove already uploaded files and do minor manipulations.
In the gallery of my site, I have problems with the gallery, because I cannot upload images via Ajax. The site is [URL].
View 2 Replies View RelatedI have a script which allow users to chnage there profile image, and it allmost works perfect. The script is set up so when a user uploads a new picture it overrides the previous one, so if a user have an ID, lets say 15, the image would be called 15.jpg. The problem is that when an new upload is finished it still shows the old image, I think by cache, and thats no good. How do I refresh the image with ajax so when the script has done uploading the image is the new one?
The javascript upload.js:
Code JavaScript:
<!--
function startUpload(){
document.getElementById('f1_userimage').style.visibility = 'hidden';
document.getElementById('f1_upload_process').style.visibility = 'visible';
[Code]....