Make Div Loaded With Different Images Actual Links?
Mar 19, 2011
I have a couple of divs as part of my gallery page, I was wondering how I can make the image that is loaded into the div be a link, so it can be clicked on, but a different link for each image. I want to click the main div on the right when it has been loaded with an image so it opens up the original image source in a new window.
Been looking around for 3 days now, I found exactly the style that I want, have images on my web site, all I need is for someone to show, explain to me how exactly this pagination or whatever it is works, how do i select which actual images from my site or where to be shown in the main window and also the thumbnails below?
as I said, I already know what kind of slide show I want, it's in this link the lower right version of slideshow with the pics of two horses and stuff: [URL] I already have the script on my site but but can't figure out how to place my images: [URL] and I want THUMBNAILS on the bottom like in the first link.... not the text
i have a iframe element with ID iframe-template Then, i used $('#iframe-template').attr('src', url) to load content of url into that iframe! It works fine! But i dunno how to make it grow up to it's actually This is my iframe tag <iframe width='100%' height='100%' id='iframe-template' name='iframe-template' frameborder=0 src='' scrolling='no'></iframe>
Would it be possible to make besttest[1] arrays value an actual variable name and assign it string value "selected"? I have "for" loop that returns the selected state and I need to somehow pass that variable name (which has value "selected") to option tag. And that variable name is the actual value of array.
When I load an HTML file dynamically which contain relative links with jQuery, all the links are broken. which does not involve changing all the links to absolute values?
I am trying to make different images hover over a table of sliced images when you mouse over a particular image. ex. mouse over image 1 = have image 1.1 hover over entire table of images in spot A; mouse over image 2 = have image 2.2 hover over entire table of images in spot B....ect. what i have so far only allows me to mouse over image 1 and have image 1.1 hover over entire table in spot A. Any time i try to move forward with more div's on other images it just jacks everything up.
The pages which have these images are frames.... and even with my best attempts to preload them all still most do not. Some use more than one image and the flicker is obvious.
Below is how I am loading them, and it doesn't matter if I use URL referenced images or locally, (i.e. ./image1.gif)
<script> pic1= new Image; pic1.src="./image1.gif"; pic2= new Image; pic2.src="http://www...."; </script>
Is there a reliable way to pre-load all images in frames, or *should* this work and it's something else?
How do I detect if a couple of images on my page are loaded? I must somehow detect if those images are loaded and if possible, stop the visitor from doing anything until they are loaded.
I embedded a s3slider jquery plugin which has a sequence of more than 80 pictures.That causes a problem when loading the page,since when the slider starts the page completion get stuck.To overcome this I thought I could make it run after $(window).load and somehow it starts running after the page content is fully loaded but ... it has to wait for the whole set of 80 pictures which is not very practical. first it has to fully load the page content and graphics,except for the imgs under the slider, once that's done, instead of waiting for all the 80 pictures, it has to start running after the first 3 pictures of the banner are loaded...but this doesn't work...
When to call a fadeIn function only after all of the elements (images) have been loaded perfectly. I set a function on document ready to fadeIn all divs of which class is "menu".
//animate on page load $(document).ready(function() { $(".menu").fadeIn(2300, function() { $("#welcome").fadeIn(1700);
[Code].....
But, before all of the menu are images, if it is my first time to open the site. The fadeIn effect could not be seen becaue of the loading time needed for images, instead I only see they are loaded "partially" and one by one like usual.
This is the link of the site When to call this fadeIn function only after all of the images have been loaded perfectly?
I'm using a double background image for a site - basically two containers around everything, one with a gif with patches of different colour, and above it a semi-opaque png with a very faint texture. I'm doing it this way as it makes for much faster loading than one jpg with the image and texture combined.
The only problem is that you see the gif load first, then the texture goes over it. Is there any way, perhaps with JS, to hide these background images until they're both fully loaded, then display them together?
My problem is when the page loads, the javascript slideshow starts to play even if the image has not yet finished loading... in effect the first image is not displayed since the image is still loading..
what i hopefully want is to start the slide show when all the images has loaded so that the slideshow will run smooth. code...
the javascript slideshow starts to play even if the image has not yet finished loading... in effect the first image is not displayed since the image is still loading..what i hopefully want is to start the slide show when all the images has loaded so that the slideshow will run smooth..
I have a page that contains images, and those images are displayed in a fancybox window when they are clicked. Some of these images are loaded dynamically after the page loads via AJAX.
All of the images exist inside of link tags with class="challenge_image_gallery". The code works the way it should on the images that are initially loaded on the page. However, when the new images are loaded onto the page using AJAX, the fancybox window loads two instances of the image that was clicked on rather than one as it should.
THis is very nice effect and more easy to use than the CSS method. I'll use this for some hover states.
Problem is that the opacity starts when the page is loaded. So you see the images 'flash' from normal to 'opacity: 25'.
Is there a method so the images have the opacity value immediatly, instead of when the page is loaded? Like a step before 'document.ready'. Or is the only way, the CSS way?
I have a client that wants a new background image every time page is reloaded. I thought I have to script and thought I had it working but when I applied it to all my pages from a template I made in dreamweaver it doesn't work. It only works on the template.
See code below. <head> <script type="text/javascript"> <!-- function MM_goToURL() { //v3.0 var i, args=MM_goToURL.arguments; document.MM_returnValue = false; for (i=0; i<(args.length-1); i+=2) eval(args[i]+".location='"+args[i+1]+"'"); }
The following code adjusts the opacity of an image which were dynamically loaded. It works on all browsers except for IE6.However, jQuery did apply inline styles "FILTER: alpha (opacity=30); ZOOM: 1" on the image. It just doesn't work.
I was wondering if there is something like document.ready; to trigger after all the DOM+Js is loaded. document.ready is triggered when the DOM is ready, but the js might be still loading, i would like to trigger an event only after DOM along with all the JS is loaded.
I am making a simple lightbox without using the silly plugins and I want to know how to make the lightbox resize equally when its being loaded. I can only get it expand from the corner, I want it to stretch down then widen but equally on both sides.
This is the code im using: // Javascript <script language="javascript"> $(function(){ $("a#show-panel").click(function(){ $("#lightbox, #lightbox-panel").animate({"height" : "400px"},2000); $("#lightbox, #lightbox-panel").animate({"width" : "400px"},2000); }); $("a#close-panel").click(function(){ $("#lightbox, #lightbox-panel").fadeOut(300); }); }); </script>
I'm a php developer and have come across a mind boggling issue involving Javascript. I'm uploading images to a server without issue. They are being returned to the page in thumbnails.
The script works great but I can't get the links for the images that I've uploaded.
If I right click and view the image I can see the link on the server. How would I go about getting that link? If I look at the source code the link isn't present. Its a dynamically generated link for the uploaded image.
Using Dreamweaver, I'm trying to implement code on my page so that the images refresh upon loading, and each image links to a different page.I'm also trying to have it so images will rotate on the page and link to other pages within my site.
This script produces 5 random images and works lika a dream. Im trying to figure out how to create links for each of the five rotating images, so the link would also rotate and reflect the new image? Code:
So what I am trying to do is make it so that every time the page is opened or refreshed we get a different image with the corresponding link. Of course I can't make this work.
I have the following code:
<script language="JavaScript"> var id = 3; var ranimage = new Array(); var imagelinks= new Array();
I know I probably have to recode this, but is there a simple answer?
var ImageArr1 = new Array("images/sponsors/deanst.png","images/sponsors/vroom.png","images/sponsors/lfest.png","images/sponsors/beontrack.png"); var ImageHolder1 = document.getElementById('Rotating1'); var ImageArr2 = new Array("images/sponsors/paulmitchell.png","images/sponsors/sinnersaint.png","images/sponsors/pinksofa.png","images/sponsors