Jquery :: Json Google Ws Api?

May 21, 2011

i am trying to get the google json from my local host[URL]...and i getting: Line: 4984 Error: Access is denied. from the jquery what is missing? well this is the code

HTML Code:

<script type="text/javascript" src="Scripts/jquery-1.4.1.js"></script>
<script type="text/javascript" charset="utf-8">
$(document).ready(function () {
alert("s");
var _url = 'https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=fuzzy%20monkey';
var _serverParam = "";

[Code]...

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JQuery :: JSON Not Working With Google API?

May 21, 2010

I'm using the below code to load a json feed from google which looks like this:

// [ { "id": "14323395" ,"t" : "RBS" ,"e" : "LON" ,"l" : "43.68" ,"l_cur" : "GBX43.68" ,"ltt":"8:41AM BST" ,"lt" : "May 21, 8:41AM BST" ,"c" : "-1.14" ,"cp" : "-2.54" ,"ccol" : "chr" } ]

Now this doesn't work because of the // and the square brackets [ ] - if I remove these it works great, but obviously can't change this.

<script type="text/javascript">
$(document).ready(function() {
$.ajax({

[code]....

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JQuery :: How To Get Data From Google Spreadsheet JSON

Nov 2, 2010

I am new to jquery and JavaScript in general and I want to access data in Google Spreadsheet. So at first I published a spreadsheet to be able to retrieve a JSON feed like mentioned here: Simple example of retrieving JSON feeds from Spreadsheets Data APINow I can get a JSON-File - the specific file is this: My Google Spreadsheet JSON

But I was not able to display any data as of now. My code looks like this:
<!DOCTYPE html>
<html><head>
<title>the title</title>
<script src="[URL]" type="text/javascript"></script>
<script type="text/javascript">
jQuery(document).ready(function() {
jQuery.noConflict(); // probably I need this because in the JSON-feed there are $t-objects
jQuery.getJSON("[URL]", function listEntries(json) {
var content = document.createTextNode(json.feed.entry[2].title.$t);
jQuery("p.inhalt").append(content);
});});
</script></head><body>
<p class="inhalt"></p>
</body></html>
So if this looks like noob-code - it is. How the code should look like if a wanted to access the data in the spreadsheet?

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JQuery :: Can't Get JSON Data Out Of Google Picasa?

Dec 7, 2009

I'm not sure if this a Picasa thing or a jQuery thing, but I just can't get the following code to work. It works when I type the URL directly into the browser, but not when I do a getJSON call in jQuery:

[Code]...

It's driving me a little insane, and I've not had any response over on the Picasa board at all.

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JQuery :: Convert A String Version Of A Json Array To An Actual Json Array

Jan 5, 2010

How I can convert a string to a json array.

start code:

The problem is that .css treats snip[1] as a string but I need it to handle it as a json array.

Bad: .css

Good: .css

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JQuery :: Load Html And Loop Through Json While Changing Html With Json Data?

Sep 11, 2010

I have a html file that I want to load, loop through the json data and for each json entry I want to add a new block of the html and insert the json data into the matching div/class of the html. json looks like this:

{"Super" : [{"Name" : "John Doe", "Age" : "30"}, {"Name" : "Jane Doe", "Age" : "40"}]};
html looks like this:
<div class="Name"></div><div class="Age"></div>

So for each json entry of name/age, I want to insert that into the html, and then add another row, until all json data has been fetched. After this I want to insert all of this into #box, which is just a divthat should contain that html. Looping like this obviously does not work, since I just keep replacing the same html through the loop.

var jsonData = {"Super" : [{"Name" : "John Doe", "Age" : "30"}, {"Name" : "Jane Doe", "Age" : "40"}]};
$.each(json.Super, function() {
$('#box .Name').html(this.Name);
$('#box .Age).html(this.Age);
});

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Getting JSON From The API And Then Write The JSON Data In The Form Of Dynamic Table With Pagination?

Oct 20, 2010

I have a JSON structure in API.When I call the API in my code it returns as the same JSON .I have to print this JSON result as table with pagination in Javascript. The table should be dynamic with previous and next buttons and the table should populate the results according to the JSON and each page should have 20 entries and then the remaining entries should go on the next page and I should be able to go back and forth in the table using previous and next respectively.tell me the exact code of how to start with getting JSON from the API and then write the JSON data in the form of dynamic table with pagination.

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Google Maps Adding A Second Google Map To A Page

Apr 7, 2011

I'm not sure where I have translated this incorrectly. I have one google map embedded on my page which works fine. But I wanted to add a second one. I thought the easiest way to do this would be to have a second page which is called later on with all the details on it for the second map. However although I think (this I presume is where I went wrong) I have replicated the instructions correctly the place holder for the second map just remains blank.

This is the code for my called page with the instructions for the second map:

And this is the script of the main page, just in case I would be better off keeping them both in one place.

<head>

I've cut out the script that doesn't relate to this so I hope I haven't missed anything important.

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Google Scraping Vs Google API?

Jun 5, 2010

Can the Google API replace scraping? You can get blocked by Google if you scrape, but can you get the same info from the Google API at no risk?

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JQuery :: Get Value Of Json?

Jun 19, 2010

I have following Json string (returned from server) :

[{"rurl":"Asia.com","status":1,"recordType":0}, {"rurl":"Africa.com","status":1,"recordType":0}]

Iam using following code to get JSON values but Iam getting "UNDEFINED" value. I want to access "rurl" => "Africa.com"

success: function(data) {
var encoded = jQuery.toJSON(data);
alert(jQuery.evalJSON(encoded).rurl);
}

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JQuery :: Remove The New </br> After JSON Req?

Aug 31, 2011

I hve a problem..If i use this code :

<?php
echo '{"test":"test","test1","test1","test2":"'.json_encode(utf8_encode('tést2<br>test2')).'"}';

[code]....

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JQuery :: How To Add JSON To Attr()

Jan 15, 2011

I have json object:

var heightwidth = '';
if (isit) {
heightwidth = { width: 184, height: 135 };

[code]....

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JQuery :: Getting Started With JSON (and PHP)?

Aug 27, 2009

I need to return several values and I'd rather do it all in one ajax call. However there doesn't seem to be anything in data. Perhaps I'm way off here.

[Code]...

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JQuery :: JSON Returned From Php?

Apr 4, 2011

Every parse example I have seen on the internet is the well formed;

jQuery.parseJSON( ' {"sid":"123455","client_id":"1","last_name":"Anderson","first_name":"Alan","institution_id":"1"} ');
What is the easy way to get from this;
{"posts":[{"post":

[Code]...

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Jquery :: How To Decode Json Value Through It

Jan 28, 2009

I am getting following Json output from PHP file code...

how can I decode/get these Json values in Jquery.

I am using following Javascript code to get Json values [in Javascript]code...

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JQuery :: How To Read JSON From An API?

Nov 1, 2011

I'm trying to get statistics from sendgrid by using getJSON(). Their JSON feed reads:

Code:
[{"date":"2009-06-20",
"requests":12342,
"bounces":12,
"clicks":10223,

[Code]...

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JQuery :: 1.5.1+ Broke Old $.get() Json Calls?

Apr 12, 2011

functions like:

function showData(id) {
$.get("/url/getdata", {id : id}, function(data) {
$("#dialogData").html(data);

[code]....

no longer work with the addition of 1.5.Looking at firebug, the correct data is returned, but the function breaks after entering the callback.Everything simply stops.I read about the changes to Ajax call in 1.5, but I have over a thousand such calls through my project -> I cannot even begin to think about hunting them all down and changing them, let alone bug testing it all.

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JQuery :: Animating Append From Json?

Oct 16, 2010

Using json to gather some data. Here's abridged version:

var ids = new Array(1,2,3,4,5,6,7);
for(var i=0;i<ids.length;i++) {
var site = '/ajax/get_feed' + '/<?=isset($dashboard) ? $dashboard : ''?>/' + ids[i];
var divID = ids[i];
getJSON(site, divID);

[Code]...

I remove the ajax loader image, then append data.result, where result is an html string. I want to animate the new content... I've never done something like the following,

$('#twitter img.ajaxloader').fadeOut(); $('#twitter').addClass('lefttext').append(data.result).fadeIn('slow'); I know this doesn't work. Essentially what I'd love to see is for my $('div.row') (the html string returned is wrapped inside a div with a class='row') to animate much like an accordion does when it opens. Just not sure how to get there.

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JQuery :: Can't Parse JSON Results

Jan 4, 2012

I am having difficulty displaying a specific key from a json file. I am trying to parse the following json file using query:

[URL]

I am using this type of function to parse the data:

$.each(json.route,function(i,route){
<!--add a paragraph tag to the results div and enter the speficied key-->
$("#results").append('<p>Result: '+ route +'</p>');

Using this I am able to print all the keys from the route but I am not able to print a specific key.

What I want to do is just get the results for the key "fuelUsed" using this method:

$("#results").append('<p>Result: '+ route.fuelUsed+'</p>');

But I never get back any data that way. Am I not specifying my key correctly?

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JQuery :: Convert JS Object To JSON Via This?

Sep 2, 2010

I am trying to convert a very simple JS object as follows to JSON, cant seem to find the solution [code]...

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JQuery :: Get Current Json Image?

Dec 8, 2010

I'm looking to create previous and next image links. The images are brought in via JSON. $('<img />').attr('src', photo.thumbnails["500x500"]).appendTo('.img-full');

Does anyone know how I go about getting the current image and then the ability to click next to find next one?

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JQuery :: Get Encoded JSON Items?

Apr 30, 2010

I am having quite a bit of trouble getting items out of a json encoded array. I have searched this forum tirelessly and can't find anything except more confusion. I'm simply trying to retrieve data from a mysql db via ajax.

select.php:
echo $json_encode_data;
output is like so:
{

[Code]....

Do you need to use a .json file when using .getJSON? I simply want to print data from my select.php file that has an json encoded array. If there is a more simple way to do this without using json encode

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JQuery :: Get Json File With Ajax?

Jun 1, 2010

How can I get the json that this url generates?[URL]... It returns a json object as a file to download, I've tried getting the data as jsonp, but it needs a callback in the feed, but I can't generate it cause the server which generates the code is external.

[Code]...

Couldnt make it work using the get method. And using other data type just would make the incoming data as null (even including ?callback=? in the url).

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JQuery :: Retrieve A Json Object Value?

Mar 24, 2011

Ihave a Json Object n wanna select one row based on id and name

[Code]...

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JQuery :: Associative Array To JSON?

Jun 21, 2009

I have been trying to figure out how I could go from an associative array to JSON. Is there a function for this?

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JQuery :: Convert Object To JSON

Aug 14, 2009

In addition to fetching JSON you might want to POST it back to the server, but there is no postJSON method. You cannot use the generic ajax method, either. What is missing is the complement of "eval" to turn a JavaScript object in to JSON. The JSON.stringify function from www.json.org (see json2.js in JavaScript section) does the trick, but it would be nice if jQuery incorporated that out of the box, to save some hunting time.

Using the jquery ajax method to set the "type" to "json" and the "content-type" to "application/json" send and recieve JSON, but you must use JSON.stringify to convert your outgoing object to JSON. P.S.. a lot of forgiving parsers have resulted in a lot of articles on JSON being wrong. would I like to mention that here. Property names are JSON strings. JSON strings have double quotes. Therefore, property names have to be surrounded with double quotes. Single quotes are not JSON strings and not legal (JSON is not JavaScript).

[Code]..

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