I am using the jQuery .load() command to place the output of an PHP script (to load the latest tweets from my account via a JSON call) in a particular <div> (.twitter). The scripts work fine in FF, Opera and Chrome, but IE6,7,8 and Safari don't show anything at all.
[Code]...
I'm a bit confused as I'm just learning PHP/Java, and need to display a percentage. I successfully can display a percentage, however, the decimal like any calculate displays .00000012130 whatever sometimes. How can I round the output to the nearest 10s place?
<script language="javascript" type="text/javascript">
var a = "14";
var b = "25";
document.write(parseInt(a) / parseInt(b) * 100);
document.write("%");
</script>
This is the code I use, however, it needs to be modified so that it rounds to the nearest 10 instead of display a decimal.
I have cpa gateway on a site that when the customer completes a function of the gateway.The external js of the gateway sends a command to the website to reload the site.Is there any way I can have some sort of event listener to know if that command is sent or not? The problem I'm having is its causing a loop in my existing JS.So it keeps looping the page. I would like to be able to set a cookie when the command is sent and then just have the cpa gateway not load.
View 1 Replies View Relatedi'm new to jquery and javascript and am self taught (so i am always new to everything!!). my concept is to keep a web page side bar and header and to use menu items ( on click and load) to place pages into my main div. I have done that with images on the first loaded page...then if you click on the images another page gets loaded into the same div this works in ie, chrome and firefox...but not in safari.i don't know if i have a code problem, i have placed my javascriptin the wrong areaor it just is not possible..
View 3 Replies View RelatedI have been trying to get a loaded element to fade in on Safari for about 2 hours now to no avail. Anyone aware of a fix for this?
Here is my code:
I have also tried:
Either one of the above works in every browser but safari.
When I load a page with jQuery load() function API. It does not load the style section on the header using Safari and Chrome.
Attachments
test.php.txt
Size : 538 Bytes
Download : 524
I'm using a function to load a page into a div. When I add the class of the element I want to show (.contentpaneopen) Chrome and Safari show no content. It works OK in IE and FF.When I ommit the class it works on all browsers.
function loadContent(elementSelector, sourceUrl) {
//Works in Chrome en Safari:
$(""+elementSelector+"").load(""+sourceUrl+"");
[code]....
In firefox, this script works just fine. But in safari, it doesn't do anything and I can't figure out why.The intention of this code is to just create a draggable item.
View 1 Replies View RelatedMy webpage won't load at all in Safari, unless I open it as a link from anbother site or if I manually type in the index.html after the url.
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I'm using the following code (simplified version) to call a Json file, parse it and on each iteration, create a div with an ID of "tab". I'm using this with jQuery UI .tab() to create a listing with entries which have three tabs. Anyhow, the principle seems to work except that when I examine what's happening behind the scenes using Firefox console, I see that each href in the html code produced is causing the Json function to re-fire using the href as it's url target.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
[Code].....
In firefox, this script works just fine. But in safari, it doesn't do anything and I can't figure out why.code...
View 7 Replies View RelatedIsn't it possible to place a text at a fixed place on a picture with javascript ?
The text will be AJAX updated...
I want to load an image with JS within the form event "onsubmit" without stipping the submit action of the form.
What I do is the following:
var img = new Image();
img.onload = function(){
myfunction();
};
[Code]....
This logic is a MUST for me, I mean I don't want to use settimeout to postpone the form submit, and I have to call the URL_FOR_PHP_SCRIPT_TO_DO_SOME_LOGIC this way since this code is on a JS file from different domain. This logic works fine on all browsers, and the request to call the image is sent -which is what exactly I need-, however on safari it doesn't call the image request, and start posting the form directly. I tried to add an "onunload" event on the page containing the form when the browsers is safari, but this didn't help too, and the form still submitting data directly without starting sending the request to load the image.
I have a site which displays a selection of advert listings. We log the number of clicks each advert receives via ajax requests.The listings link to both internal pages on our site and external pages, hence the ajax - we cannot log the'clicks' by logging the requests on the destination pages as these are not all on our site for us to log. Also, I don't want to potentially get false positives e.g.from bookmarked pages - hence I am logging the actual clicks, not the requests on the destination.
All is OK in most browsers, but there is a problem with Safari (I am running Safari 4.0 on Windows XP running in Virtualbox OSE) but only where the destination is to open in the same window/tab (some listings go to a new window, some don't). I am logging clicks via an ajax request in the onclick event, which is working fine when the listing is to open in a new window, but it appears that when a new window is not to be opened, the ajax never gets sent.A have constructed the following minimal test case:
index.html
Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" [code].....
Note the line commented '****' in index.html which cancels the action of the link. When this is not commented out, the ajax request is sent correctly. Without it (the desired situation) the ajax request never gets sent. Its as if Safari saves up the ajax requests to do later, but never sends them as the new page cancels all such 'saved up' actions.I am using the Safari web developer tools, but I have also checked this test case by checking the Apache logs. Note that as a test case I don't pretend that it will work in IE, but it should work in standards compliant browsers and has been tested on Firefox 3.6.6 and Opera 10.6. The Apache logs show that logger.txt is being requested, unless it is already in the browser cache.Possible workarounds I've considered, but would prefer to avoid:
On the site in question the only such links that currently open in the same window are internal, so I do have the option of logging safari clicks by logging these requests as opposed to clicks and checking the http referer on the server side. As this is not a very flexible solution as it relies on these specific circumstances, also relies on all other links successfully making a new window, and furthermore relying on http referer could result in false negatives I'd rather find a solution within the javascript.I haven't checked whether an asynchonous request would work, but I don't wish to do this anyway just in case there is ever a server problem that prevents the response coming back (note that for these purposes the response is actually superfluous - we are sending the server a message but don't need anything back). I also want to avoid the delay in sending the user to the destination - there is no point having to wait for a response we don't need.Lastly, and my prefered workaround unless I can find anything better, is to make Safari (only) open all links in a new window anyway.
I use a Time Date Picker Javascript code [URL]. It works fine with a placement problem. When you click one of the last pair input fields on the page, a drop-down list will appear from the input field. In my case, the drop-down list shows on the bottom of a page instead. I can't find the code controls the location of the list.
View 1 Replies View Relatedi try to insert div to another div with the command:
example: $("#stage").html($("#movie").html);
this command work fine, but when i try to press on buttons, in div "#movie",
I will have a list of numbered links and whenever one is clicked, I want to change the content of a <div>. Is there a simple command that does this? I've read a bit of jQuery but could not find this info.
View 6 Replies View Related I have thmbnails of pictures on a page & i would like to open up the full picture (which is already present on the page, but I have used css to display:none on it) in a div (ie overview) when user hovers over the pictures so on the pictures I have done:
Code:
<a onmouseover="javascript:show('{$row['productid']}');" onmouseout="javascript:hide('{$row['productid']}');" href="viewProduct.html?id=" . $row['productid'] . ""> <img height="100px" width="100px"src="images/thmb/". $row['imageLocation']."" /> </a>";
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I am trying to pass in an id because the full picture has that id which is guaranteed to be unique! and I dont know ahead of time the id..
or this cant be done with Jquery/
disclaimer: I have done this using JAVASCRIPT successfully but I am learning Jquery so i thought why not use that..
I have a menu system that toggles the visibility of different divs. Here is an example of how my javascript is now:
$("#one").click(function() { $("#m").hide("fast"); $("#n").hide("fast"); $("#o").hide("fast"); $("p").hide("fast"); $("qx").hide("fast"); $("rx").hide("fast"); $("sx").hide("fast"); $("#one").toggle("fast"); return false; });
Is there any way that I can make it so it hides all divs and then toggles the one I want WITHOUT having to write it out like this. is there a 'hide all' option?
In this code...
Why does the .stop() need to be in there and why is it located before the .animate() command, it has nothing in regards to the .stop() in the .animate() documentation...Im just a few days into jQuery and want to make sure I understand everything.
I am trying to create some divs that hide and show when a link is clicked. There may be multiples on the same page and it each needs to functionindependently.
I've added it to jsfiddle : [URL]
When the user clicks a show more link the first time nothing happens. If you do it again the div expands as planned (great!). If you do it again to close it slides back up but then bounces straight down again (Not Great!). I can't figure out what I've done wrong!. Eventually I'm going to add more functions to show some hidden data as well.
I'm building a body shape calculator which jQuery Cycle turns into a truly beautiful form. However...
The original problem:When a parent element is the slide, any child form labels and inputs cannot be selected if the same click is used to advance the slide. They can be clicked, and the slide is advanced (they were given a 'next' className), but the input is not selected/checked.
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While my calculator form UI feels great using cycle, I feel like I'm totally underusing an excellent plugin when it comes to the 'next' functions - do I need to use a 'before' callback instead? I'm not 100% sure how to employ it.
The very simple code (below) works fine in Safari (and Chrome, Firefox etc.), but it doesn't work in Mobile Safari. Why?(You can find a working example at: http:[url]....)
Code:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>[code]......
I am trying to use the LPR command inside a javascript to print a PDF file directly to the printer. Want just a simple webpage with a button which will print test.pdf when clicked. code...
I know very little when it comes to javascript. If you know of a better way to use the lpr command
I have this code..
javascript:function showMore() {ProfileStream.getInstance().showMore(); setTimeout(showMore, 2000)}; showMore();
i want to loop it 10 times, but do not know how to do it.I have been told that the for var command is what I want, but I cannot get it to work.
[b]How to close the exe files through javascript
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