Get Images Out Of The Database And Display Them In A Grid?

Dec 13, 2010

I have a PHP script that will get images out of the database and display them in a grid. I have two verisons. I save a thumbnail which I display and then a larger image in a different folder. These images are placed in a scroll bar but what I would like to happen is that when I click on a thumbnail it basically displays the bigger image until I click on that image and it goes away. I would love for the middle of the image to be displayed in the middle of the users screen but beggers probably can't be choosers in this case.

An example of a similar desired result is a link here:http://qrayg.com/experiment/hig/Instead of the hover, I'd like to utilize the onclick to display and remove the image. If it's easy to put the center in the center of the screen that that would be absolutely incredible as well.

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I have a table grid of images, i need all the images except the one hovered to fade out to 0

I tried throwing around .filter but no luck

Images are written as <img class='tile' id='${row['_id']}' src='$rsrc/food pictures/${row['_filename']}_in.png'>

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Like so (numbers represent images):
5 4 3
6 1 2
7 8 9
So if the user clicked and dragged to the right the images would then look like:
4 3 12
1 2 11
8 9 10
The new images are taken from the database and the user can drag in any direction.

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This link will show you how I want it to be dislayed like but I do not know how this is done.

Click here

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I have a question for flexigrid jquery grid control users.

I am able to display json data returned from my WCF service in my Flexigrid in my application.

The paging toolbar displays correctly and it's clear that the paging toolbar understands how I've configured it.

However, the grid is not actually implementing the paging filter on the data in the grid. For example, the paging toolbar says "Displaying 1 to 10 of 12 items". However, all 12 items are displayed in the grid.

I guess I'm missing a config setting or callback. Any idea what the problem might be?

Here is my grid config block:

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Sep 22, 2006

I found this javascript to randomize an image on a page...

Code:

<script language="JavaScript" type="text/javascript">
<!--
function random_img(){
var ranimage = new Array();
ranimage[1] = "photo1.jpg";
ranimage[2] = "photo2.jpg";
ranimage[3] = "photo3.jpg";

var ry = Math.floor(Math.random()*ranimage.length)
if (ry==0)
ry=1
document.write('<img src="'+ranimage[ry]+'" border=1>');
}
random_img();
// -->
</script>

I have some images that are dynamically generated and i want these images to randomize every few seconds (at the moment the images change when the user goes to a different page on the site)...can anyone give me any ideas as to whether this is possible??

The PHP code i'm using is below...

<?php

// read image dir
$dir="../../admin/uploads/";
// Open directory, and proceed to read its contents
if (is_dir($dir)) {
if ($dh = opendir($dir)) {
while (($file = readdir($dh)) !== false) {
if (filetype($dir . $file)== "file"){

$counter++;

$selectSQL = "SELECT id, url, imagefile from images";
$result=mysql_query($selectSQL);
#print $result . " - " . mysql_error();

$nameStack=array();
$urlStack=array();

while ($row = mysql_fetch_assoc($result)){
$thisurl= $row['url'];
$thisid= $row['id'];

array_push($nameStack, $row['imagefile']);
array_push($urlStack, $row['url']);

}


}
}
closedir($dh);
}
}


// load each image into array echo rand(5, 15);
// get count of total no. of images
$lastNo=sizeof($urlStack)-1;
$imageToUse=rand(0,$lastNo);
#print "using image $imageToUse of $lastNo";
$imageName=$nameStack[$imageToUse];
$imageUrl=$urlStack[$imageToUse];

#print "got $imageUrl and $imageName
";

//

?>

<a href="<?php echo $imageUrl; ?>"><img src="http://mywebsite.com/admin/uploads/<?php echo $imageName; ?>" alt="click here for our special offers" border=0 /></a>

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Here's what I mean:

How can I extract the current "s.src" parameter and use it on the "img src" tag to display the image accordingly?

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I want to grab images from the database and then display them in a row going downwards. I be using position absolute in css. I want to put them in a row going downwards but having the exact space inbetween each image. Currently I made a row of images going downwards but the space inbetween keeps on increasing when more and more images are needed to be displayed.

[Code]...

Yet the space inbetween images increases the space when there is more and more images displayed.

The first 3 are always have the right space inbetween them. The 4th and so on adds 10px of space more for each image that is displayed but it's gradually. For instance image 4 would be you would take 70 which is image 3 top value and instead of adding 30 the code would add 40 to it. it increases the spaces by 10 for every image past the 3rd image. Yet the firebug will show the top values as if each image has a difference of 30 for the top value.

I was thinking can't I use position X and Y like with jquery or javascript can't I get the current x and y values of image one or 2 and then decrease the X and Y in a way that the spaceing inbetween each image is exactly the same. In our example I want to have like a 30px space inbetween the images and never increase the space as more images are displayed.

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So my question is, how easy it is to do this with javascript and does anyone have any idea how to code it?The main photo sits in a div whose id is "mainphoto" the remainder all sit in a div whose id is "thumbpix".

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I have a MySQL database with a table where I store images (the file name, the mimetype of every file and the binary data in a BLOB plus a unique ID). Now what I'd like to achieve is to load an image from the database using AJAX and the POST method. Viewing a specific image using the GET method is quite simple, I just set the SRC attribute of an <img /> HTML tag to link to the PHP file and set the correct GET variables, there's no AJAX needed for that.I click a button or something, and 'behind the scenes' PHP is retrieving an image from the MySQL database, depending on the unique ID that was provided by AJAX through the POST method. AJAX uses the returned data to fill an element somewhere in the document, and that would be the freshly-loaded image.

Alright here's some code:

//PHP retrieving an image:
$returnImageQuery = "SELECT imageName, mimetype, imageBinaryData FROM imageTable WHERE ID = $_POST['someID']";
$return = mysql_query($returnImageQuery );

[code]....

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this is the code JQuery Code

Code:

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[Code]...

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[Code]...

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<?php
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[Code]...

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$(this).html();
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[Code]...

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