Duplicate Some PHP Code In JS - Invalid Quantifier?
Dec 27, 2009
I'm trying to duplicate some PHP code in JS, but keep running into "invalid quantifier" errors for regular expressions.Here's an example of what I'm working with:
Code JavaScript:
var elementId = 'ipaddress';
var regexsplice_IP_ADDRESS = '(?:[0-9]{1,3}.[0-9]{1,3}+.[0-9]{1,3}+.[0-9]{1,3}+)';
if(!RegExp(regexsplice_IP_ADDRESS).test(elementId.value))){
[code].....
1) do I need to double up on the backslashes within a string using single quotes on characters that are seen as escape characters in regex, but not javascript?
2) do I need to start and end the string with a special character, like I would with preg_match in PHP?
3) To use the RegExp() function to prepare a regular express created from a string...can I use it like in the example above? Or do I have to use a separate delcaration like: var theregex = new RexExp(regexsplice_IP_ADDRESS);
I made this function to duplicate form elements with a little html-code surrounding the input fields. First i clone the html of the first child found (always gets rendered by php). Then, everytime the add-button is pushed, i append a cloned piece of that stored html. It's working fine except for the delete button.
It's seems that whenever a cloned html is removed, the other cloned elements aren't recognized anymore by the delete buttons (although the delete buttons are in them)
I am trying to use Accordion Content script v1.7 from DynamicDrive.com on some pages. I have set up a test page to show the error messages. I have changed the doctype of the page several times, including the exact one they use on the sample/instruction page on DD, but no luck. It is also throwing an error of undefined var ddaccordion, which is defined in ddaccordion.js, which is the JS file that goes with sample page , which is located in the same directory.
I am trying to design menu and also been successful at some extent. Root menu items doesn't create any problem but when I used following code to create drop down submenu items i got the error:Invalid argument
The error causing line is bold
While this javascript code doesn't work in FF3.x.x but in IE.
i have a html page with some javascript functions in a js file linked to it. now, if i create a function in the html page with the same name as one of js functions, how can i call the function that exists on js file (from html)?
My text and what I have been researching on the internet has not been very helpful in determining the code that I need to prevent a user from entering his/her information more than once. Here is my current code
<!DOCTYPE HTML PUBLIC "-//W3C//DTD.HTML 4.01 Transitional//EN" "http://www.w3.org/TR/htm14/loose.dtd"> <html xmlns="http://www.w3.org/1999/xhtml">
[code]....
I have created a new web page to link the duplicate cookie too, titled doubleinfo.html. This is what I am using to let the user know that their information has already been entered.
My text is telling me that I need to look for a nextform() function, but I didn't have to write one so what would I need to do, if anything, to start the document.cookie = "name" codes?
on my page below:[URL] I have a navigation of 1,2,3,4,5which when a user clicks on a different number the image changes, I need to have this navigation for the 4 other large boxes underneath?!here is the code to the page
Here in my case a[0] and a[5] is duplicate because i am using 1 or 0 for active and deactivate purpose a[4] is deactivate value so we can ignore the 10 in this. so in my case 10 is repeated twice on a[0]and a[5] not a[4], so its duplicate value. can any one help me to solve this.
The problem I am having is when the following script is executed within my page and the user submits the form, the variables passed to the GET array are duplicated only for the inputs created by my script. I have other inputs in the form that are created within the HTML of the page that work fine (i.e. they only try to pass their value once) but I cannot get my script to work properly.
Here is my script:
Here is an example of what the url looks like after the form containing this script has been submitted:
The input (segments) created in my page only submits itself once, while anything created by the script (segment_type_1, segment_type_2, etc.) submits itself twice with the second, blank value overriding the first, correct value.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">[code]......
Based on the code above, i wanted to generate an array of input which have the ID "ordDate", so to populate the data into the input, i identify by name attribute.It works fine if i remove the ID for the input, but in my case,the ID is compulsory. Is there any workaround to cater for my needs?
Problem: I have two dropdown list boxes with same data(all data driven). These are used for two separate entries. For every entry you cannot choose the same value twice. For example, I cannot choose for entry 1 the same value in both selection boxes (gqCategory1Entry1 and gqCategory2Entry1)
This part works.
The second entry is the problem: When I choose a value for Entry Two that is the same as in entry one it thinks that "Dubplicate Divisons have been selected").
I have a registration form and I woud like to make a button what after pressed some textboxe's value copied into some others. I can program it in C# but I would like to use jQuery to I dont have to postback it to the server.
What's supposed to happen is when the program is run the user clicks on "Select your Numbers!" their then asked for 5 numbers which they input and then the numbers are checked by a function called �isAlreadySelected� for duplicates and if there is an alert is shown. When 5 numbers are entered correctly then they are shown by a window.alert.
Its done in to 2 functions
When I run the below code I'm prompted for the 5 numbers but it isn't checking for duplicates and my selection is undefined.
I have installed the jQuery cycle plugin onto my website and I am looking for some information on how to duplicate part of the plugin.I am looking to have this type of image slide but I am wanting two of the navigation bars in the same area.
h t t p://malsup.com/jquery/cycle/pager.html
Like the link above, I am wanting to have the numbers appear twice, either side of the image, just to make it more appealing.I have attached an image that shows how I am wanting it to look in more detail.i have tried editing the html to make this possible but up to now have had no luck.
Okay guys, this might be very simple, but i just cant find the answer.
What i want to do is prevent users from submiting entries that already exist in the database using php. code...
All want is to be sure that if the there is an existing row in name with an entry of 'asdf' (example) then it will echo something like name already exists, but if it doesnt i want it to echo okay. What happens is that it ALWAYS echos okay, in other words it always says there is no row named 'name' with the value of 'asdf'
I am calling 2 scripts, that are variations of the same script, and am getting unwanted duplicate output into the other div (place-holder) on an html page. I thought it was a scope issue, but that doesn't seem to make sense. The page is: [URL]
features.js $(document).ready(function() { $.get('xml/features.xml', function(f) { $('#y-place-holder').empty(); $('#y-place-holder').append('<dl class="feature" />'); $('feature', f).each(function() { var $feature = $(this); var fimageurl = $feature.attr('imageurl'); var fseries = $feature.attr("series"); var ftitle = $feature.attr("title"); var fdates1 = $feature.find('dates1').text(); var fdescription = $feature.find('description').text(); var ffeature = ''; ffeature = '<dd>'; .....
With my very limited knowledge of both jQuery and JS i made a small script (with a little help) that duplicates a tablerow when a button is clicked. This works like a charm, however, i would like to add a datepicker to it. This also works well, but just once and not on the copied fields or visa versa. It's probably because the datepicker "thinks" there is just one field.I found several sources to solve the problem, but again, with my newbie knowledge, it's just to hard. I am playing with this for almost two days and can't get it solved.
