I am an html/css/php professional who dabbles a bit in javascript and many other languages. I must say up front however that I absolutely despise javascript. However, it is necessary for the work I do, so I get by. I have been working for roughly 5 hours trying to find a solution to this. What I do doesntwork, even though I believe it should. Here is my problem: I have a 'menu', based inside of a table. There is one particular td, that when clicked, displays a menu of the users online friends. The friends box is in a div.
The td is name 'online' and the friends box is named 'menufriends'. (with id's, of course.) My problem is that I need the friends box to display next to the td. So what when you click the td, it shows up to the right of it instead of below the menu. I have tried all sorts of different methods and cant even get it to change its position.
I have generated a table of given dimensions (say 5x5) using JavaScript. Using Mouse events, I want to add a functionality which would display the position of the cell in that table whenever mouse pointer hovers over a particular cell.Here's what I have done.
i,m trying to make a map who show me as position A and a target adress as point B.I have made it so i can choose adress a and adress b from a dropdown but i want to automaticly load my position as possition A then choose position B from a dropdownlist. How can i do this ?
I'm new to javascript and am not sure why this works in firefox and not chrome. I am trying to create a script that keeps an object fixed horizontally while bing positioned absolute vertically. if I replace the toPP variable in document.getElementById('fire').style.top = toPP; with say '50px' it will move the element down 50 pxs, but how I have it currently it doesn't do anything in chrome
<script type="text/javascript" > window.onscroll = function() { if( window.XMLHttpRequest ) { var x = 0 -document.documentElement.scrollTop; var toP = String(x); var toPP = toP + "px";
#navigation li is the parent element, which is positioned relative.The ul element above that is also position relative. I previously tested a click function and was able to confirm I was getting the correct position back, so now I just need to set the CSS property correctly for all of those links.The reason I want to do this is I have a set of links that appear over a photo of a city skyline. When you hover over those items, I want them to be given a background image that is a blurred and lightened version of the same photo so it needs to line up (sort of like the tabs are made of frosted glass).
I have a HTML file that has a lot of content. In it I have a <div id="d1">somecontent</div> block. Would it be possible for me to know the position of this d1 (absolute or relative) displayed on the page / window if not setting it first ?
if radio button checked display div #something else display nothing if un checkedcurrently I have this and it works but when I click another radio option the div that was activated before stays there. Want a div to show only if certain radio button is checked and if not checked to hide.
I have an onclick that triggers ajax which calls a php script to pull data from MySQL. This information is then displayed in a div. The problem I am having is that sometimes pulling the data from MySQL takes 2-3 seconds, so the div is empty for about 2-3 seconds. How would I go about adding an animated "Loading" gif to display in the div while it is waiting to display the content?
I need a JavaScript (or something else) that will fade out the web site, on load, and display a series of images, then display a "Continue" button to go back to the web site. I have an idea for a cute (and funny) way to get people interested in my site that has a weird name. I searched high and low (Google!, amongst others) for anything that would be close to what I need, to no avail.
I have a <img> tag in my web page that i use as button. when user will click on it, i would like to display a hidden <div> just under.
I mean by just under, that next pixel below the <img> should be the top of <div>. Moreover, the left of <img> should be the left of <div>... like that it will look like aligned.
The challenge is the following one.
my <img> is positioned by CSS file, so it can (but it is not a must) have left and top setup... maybe not.
I did a short test : if i setup in CSS file the left and top of <img>, a simple click on <img> can not retrieve the left and top of itself.
something like that i did : function ShowCalendar(id_master) { var uleft = document.getElementById(id_master.id).left; alert("Left : " + uleft); }
where id_master = id of the <img> as following : <img id='id_img' class='buttonimg' src='calendar2.gif' ></img>
So how can i solved this issue ? Moreover, position of this <div> should be in absolute coordinates, to avoid issue in browser Xsing.
Before you immediately give me an answer, let me describe fully what I'm trying to do, as it's not as simple as the title suggests.
I need to get the absolute position of a DIV (top and left properties) relative to the viewport/screen.
I've tried using .offsetTop and .offsetLeft, but these return the top and left properties relative to the DIV's immediate parent element, not the viewport (unless of course the DIV is top-level and not contained in any other DIVs).
So, is there any way to retrieve the absolute position of a DIV relative to the viewport, even if that DIV is nested in other DIVs?
Is there some possibility to put the horizontal scroll bar of the web browser into the center if the "width" of web page are bigger then the "width" of the web browser screen?
So I don't need to scroll to right if I open the page, but the horizontal scroll bar will be positioned in the center.
That code should do the same think like I when I take the scroll bar and put it in the center position, but this should be happen when I load the page automatically.
I'm using a javascript function to toggle and display only 1 div at a time. In this case, I have 3 divs as toggle buttons and 3 divs to show content (which belong to those 3 buttons). My problem is these 3 divs (divs with class .linkBox) that act as buttons are using the same background-image and I would like to have it move up (y-position: -48px to be exact) when its content is displayed.
Its said that placing the absolute div within a relative div is a best option to correctly achieve the margins within that relative div. However, I'm changing the marginTop and marginLeft via javascript and after some of the changes it shows the absolute divs in incorrect positions in IE.
What i want to do is calculate the vertical-middle right-sided position of text fields in x, y meaning in top and left margins. How can I do that?
I am using one button at the bottom of the page. When i click on that button the page refreshes and goes to the top of the page.But i want when i click on that button the page refreshes and mouse pointer goes to the bottom of the page where the button consists. i have found that it is possible in javascript through set the coordinates for mouse pointer.
suppose that a web page has a mark "M". For example,when a user open the web page If the mark "M" is printed in the position of height 300px from the top of the browser and width 500px from the left of the browser, I like to get the height value 300px and width value 500px. Let's call them X position and Y position.Can I get the X position and Y position of the mark "M" in javascript just after the mark "M" is printed.
Any idea on how to get the coordinates/position of a div element? For example I want to get the coordinates of a particular poll which is placed on my right sidebar.
I tried this, but will not work:
document.getElementById('test').style.left
Must I set the position to relative for the element test?
I have found the code to move my objects around but I can't find a way of remembering the positions the objects were left at when I refresh the screen.
I would like my users to be able to move the layout around and have it save their layout so that the next time they view the website its as they left it.