Change Element Type With JS
Aug 8, 2006Is it possible to change an element type with javacript for example onclick to change a text box to a hidden element or to a textarea?
View 6 RepliesIs it possible to change an element type with javacript for example onclick to change a text box to a hidden element or to a textarea?
View 6 RepliesI'm trying to find a way to change the CSS class for all my many input type elements with an onclick. Is this possible? The scenario I'm trying to fit it into is below (and condensed).
Ideally I'm looking to change the style for background-color onclick, black and white in particular (hoping that the solution would mean adding more colours later).
[Code]....
I have to change text input type to password input type and i am using jquery script. This script work for FF, Chrome and Safari browser but not worked on ie7, ie8.
Script is as:-
How can i update my script, so that it works cross the browser.
I am using the JS and HTML code below to check that required fields are
completed for attributes of a product. The first attribute is a select
menu and the second is a radio set. My JS goes through fine and detects
if the select menu isn't selected with a value, but I keep getting
'undefined' for the radio element type. I've almost pulled out half a
head of hair wondering why. Any experienced eyes see something I don't?
Code:
I have a questio about a selector.How must I type: all p elements that have an em element?
View 1 Replies View RelatedIs it possible to change the input type of a form field. example
<input type="password" name="pw" value="test">
i want to have a "view" button next to that field that when you press and hold it it will chnage that input type to "text" so i can see the password. And when i release the button it will change it back.
I know this sounds like a bad idea and insecure... but its not a big deal.. i have all this stored in an "administrator" panel which an admin must login to get to it. Inside of that i have some admin programs, one of which displays information about the clients. I want to be able to see the clients password when ever i need to reference what it is, but i figured rather then just printing it on the screen all the time this would be a better way.
I have an input text box that I want to change the type from text to password and I wrote code that works in Firefox but not in IE any suggestions? Here is the code(cut down a little for easier reading) code...
View 2 Replies View RelatedI am new to javascript and I tried to change the type of a input using js.My work works well with Firefox and Chrome but not with IE.IE javascript debug mode says:
Quote:
(SCRIPT256: Could not get the type property. This command is not supported. ).
This is the code I used to change the type.
Code:
var email_type=document.getElementById("email");
email_type.type='text';
I have a variable that contains Form Elements. So these elements can be eitther a :text either a :check box See code below:
var currentValue = $(targetedInput).val() ? currentValue = $(targetedInput).val() : currentValue =$(targetedInput).is(':checked')
I was hopping that this line of code would assign a different value to currentValue depending on what kind of object i have. My idea was that If the current Object is a check bot it doesn t have a val attribute..
how to set the 'type' of an html form element using jquery? is there something like?
$("element").type("password");
So I've got a nested object that has this structure:
{"big_s":
{"s1":{"params":{"p1":"stuff","p2":stuff2"","p3":"stuff3"}},
"s2":{"params":{"p1":"stuff","p2":"stuff2","p3":"stuff3"}}
}
}
how would I go about removing one of the inner objects - s1 or s2? I've tried all sorts of ways but can't seem to get anything to remove an item from a jQuery object.
What type of variable is an empty array element? I thought it was undefined, but i noticed that they have different behavior than undefined does:
var r=Array(1);
var s=r.concat([0,"",null,undefined]);
alert (s.toSource()) //==="[, 0, "", null, (void 0)]"
typeof s[0] //==="undefined"
typeof s[4] //==="undefined"
As you can see, 0 and 4 both === undefined. Yet, they don't have the same toSource()...
Is this special type named anything specific? Or more importantly, can it be detected outside of an array as being distinct from undefined? I am thinking this would be the same type as ({}).nonProp ...
I guess the question is actually, "can you tell the difference between uninitialized and undefined"?
ok i don't know quite how to explain this so ill show two websites that implement it:[URL].. the news elements at the top of these pages, so when you highlight the news the picture comes up beside it, what is the name of this element, and are there any tutorials on how its made, or could anyone point me in a few directions so i can get started making one
View 2 Replies View RelatedI have a image gallery that gives very nice popup windows when you click the thumbnail for the larger picture. The problem is that when you hover over the thumbnail(link) it doesn't change the cursor type to a hand which makes it hard to know that it's a link....
View 1 Replies View RelatedI have a grid like so...
<div id="div1">^####^##~#</div>
<div id="div2">~#*####*##</div>
<div id="div3">#^##^~####</div>
<div id="div4">##***#####</div>
<div id="div5">#~~#^^####</div>
...with four different types of characters. I want each type of character to be a different color. I know this could be done by inserting span tags around each character...
<span id="redspan">#</span>
...but I'm stumped on how to do this with JavaScript. I can't create the span tags before the grid.
I am trying to create an input element of type file using the javascript. I am able to create it but the problem i am facing is, i need to apply a CSS class to the control. Can some one let me know how to do the same.
I am pasting the code that i am using to create a control.
function AddUploadFile()
{
var newrow = document.getElementById("files_tbl").insertRow(document.getElementById("files_tbl").rows.length);
[Code].....
I've coded in Java before but I'm still having some trouble. I am trying to draw a ribbon type shape on an <canvas> element and for some reason, when I turned it into a function, it seemed not to work. Here is what I have for drawing the ribbon with a function:
function drawRibbon(height,width,Canvas){
var c=document.getElementById(Canvas);
var cxt=c.getContext("2d");
cxt.fillStyle="#bb0044";
cxt.beginPath();
cxt.moveTo(0,0);
cxt.lineTo(0,height-50);
cxt.lineTo((width-20)/2,height-100);
cxt.lineTo((width-20),height-50);
cxt.lineTo(width-20,0);
cxt.shadowOffsetX = 5;
cxt.shadowOffsetY = 10;
cxt.shadowBlur=10;
cxt.shadowColor = "black";
cxt.fill();
cxt.shadowOffsetX = 0;
cxt.shadowOffsetY = 0;
cxt.shadowBlur=0;
cxt.closePath();
cxt.beginPath();
cxt.strokeStyle = "#ffcc22";
for (i=5;i <= 135; i=i+15){
cxt.moveTo(5,i);
cxt.lineTo(5,i+5);
cxt.stroke();
}}
drawRibbon(200,120,navCanvas);
I feel like it has something either to do with the function definition, or the call. Before this script is executed, i create a canvas in the following way:
<canvas id="navCanvas" height="200" width="120">
Why it is not displaying.
I want to create a input box the says Password inside the box and gets erased when someone clicks inside of it. Then when they type their password it is in asterisk characters.Can anyone tell me what extra scripting I need?
View 1 Replies View RelatedI was just wondering how I could change a html text input tpe from text to password on the on click and when the user clicks off it will change back to text just like facebook does.
View 3 Replies View Related$(this).attr('type', "password");
(this).attr('type') = 'password'
neither of these work, am I doing something wrong?
Full code:
<div id="register-form">
<input type="text" class="reginput" name="username" defaultVal="username / URL" />
<input type="text" class="reginput" name="password" defaultVal="password"/>
<input type="text" class="reginput" name="e-mail" defaultVal="e-mail"/>
<div class="button-form">Create my free account</div>
</div>
$('.reginput').each( function () {
$(this).val($(this).attr('defaultVal'));
$(this).css({color:'#699fe7'});
});
$('.reginput').focus(function(){
if ( $(this).val() == $(this).attr('defaultVal') ){
$(this).val('');
$(this).css({color:'#2d5891'});
$(this).attr('type', "password");
//if ( $(this).attr('name') == 'password') { $(this).attr('type') = 'password' }
}});
$('.reginput').blur(function(){
if ( $(this).val() == '' ){
$(this).val($(this).attr('defaultVal'));
$(this).css({color:'#699fe7'});
}});
I am trying to setup a password input that fist shows: "Password". When the user selects it (or focuses on it), it clears and becomes a password input. If the person, clears the password and leaves focus (blurs), the word password appears again.I did some research on this first. There is this article that requires creation of two inputs (hide one, show the other). I also read this article.Without confusing everyone, I am trying to do this simple and in a smart way:HTML BODY
<input type="text" id="password" name="password" class="password" value="Password" />
jQuery Script
$(document).ready(function() {
[code]....
I'm doing a very simple expand/collapse function using 'slideToggle'. The button that triggers this event simply says 'Expand/collapse'. I want this text to change depending on whether an element is visible or hidden.
[Code]...
I need to add an event for all elements that are not text entry.I have tried this
$(':not(input:text, input:textarea)')
$(':not(:text, :textarea)')
I tried to get it to work for just not type=text
$(':not(:text)')
$(':not(input:text)')
I can't seem to figure it out.
As recently as 1.4.3 $('input:text') would find input elements with no type attribute, but after upgrading to 1.5.1 that is no longer the case.
Is this a bug or an intended refactor to be more standards compliant?
FYI - this is the selector I now have to use: $('input:text,input:not([type])')
how can I check that a given element is a type of "td"?
this works fine: element.is(":checkbox")
but this not element.is(":td")
I realize this script and I do not know where to begin:
1) A simple grid rows / columns.
2) The first column contain an input type = "checkbox"
3) When select the input type, the line should change color than the other rows, and you should open a popup window.
For points 1, 2 you are OK. Point 3 is the difficulty.