On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
In the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() { $("#ARTransferForm").submit(function() { var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code: What I've tried so far is like this: savedSubmit = document.inputs.submit; document.inputs.submit = None; then later: document.inputs.submit = savedSubmit;
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
What I want to do which I can't achieve is that I want the functionality of the Option Type, Number of Answers and Answer buttons within each row to match the functionality on top. The problem is that under the "Answer" column within the new row it does not allow the user to select a button and the textbox under the "Number of Answers" button doesn't do anything but just display a number within the textbox.
Step 1: Open the fiddle and you see an options and answers section on top. Open the grid and select option 8. Buttons A to H would appear.
Step 2: Type in 2 in the Number of Answers Textbox.
Step 3: Select buttons A and D, you will find out that those buttons would turn green to show they are selected. Now as you entered in 2 in the Number of answers textbox (step 2), it won't let you select more than 2 buttons, if you do an alert would apear stating you are beyond limit please deselect a button to choose another button.
Step 4. Click "Add Question", a new row is added in the table.
Step 5: In the new row you just created, lets say that oh no I made a mistake, there should be 4 answers not 2 answers and within the table row you just added you changed the number of answers textbox from 2 to 4. My question is how can I get it so that it allows the user to select the buttons (turn buttons green) and deselect (turn buttons white) under the "Answer" column within in the row and that if the user has selected 4 buttons but tries to select a 5th button, it will come up with same error as in Step 3?
I copied codes on internet and arranged them according to my knowledge of JQuery (which is very shallow).. The code works fine sometimes.... but not all the time. Can anyone help me to find out why the dialog box does not appear everytime I put wrong username and password? Here is the JQuerycode:
[Code]...
Because I am using ui-darkness as the page theme, so at form tag, I don't have defaultbutton="but_submit" tag. If I add it back, I will get error while compiling..
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
On the server side, I'm using a web framework that use submit button "name" attribute to decide which action to perform. On the client side, I have an script that submit forms in Ajax with the "serialize()" functions.
But as the JQuery documentation said, the serialize() function don't send the submit buttons names. I have tried to get the event.target object but this object is the form itself. So, I wonder to know if he is a way to discover obtains the name of the button that has triggered the form submission.
how to create a drop down menu without the need of a submit button? Once user Choose his stuffs, it will auto submit the results without clicking submit?
In the following code, I have 2 questions regarding submit button with image.
1) Does this code <input type="image" name="populate" src="populate.gif"> behave the same as an HTML submit button with image populate.gif? When I click p1 or p2 button, it will post the page to process.asp.
2) When I check the checkbox, I want the image in submit button change from populate.gif to validate.gif. Unfortunately, the code InputForm.p2.src = "validate.gif"; doesn't work. But InputForm.p1.value = "validate button"; is working for a regular HTML submit button. Code:
I created this form and then I call a function to validate what is in the form. That works fine, but I can't figure out how to activate the submit button. Actually, I don't really want the button to do that much right now except to call another web page.
The code is below, maybe I could get some assistance on this. I tried several ideas I found on the Internet, but none worked.
how to get the submit button on a form to work with JavaScript? I want to get the user's name, email address, company name and message sent to my e-mail once the submit button has been clicked.
I need help making this timed quiz so when you hit submit it goes into a mysql database. right now it just tells you if you answered correctly or not Here is the code:
<input type = "text" id = "answer"> <input type = "button" id = "time" onclick="answer()"> <script type = "text/javascript">