In the quiz function the form that is generated all compiles correctly, but the submit button only causes the page to refresh. What am I doing wrong
var c = "1"; //counter
var n = [68]; //array that stores unique random numbers
var t = "better clear";
var lc = [3];
var uc = [3];
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i have a website page that contains only data of which one field gives the number of messages in your inbox, and i need to refresh this as new messages can come in at any time, so the user, while on this page can see there are new messages. how can i call my JS/ajax to do the refresh? i tried header("Refresh:10"); but client was not happy as it refreshes the whole page, he only want the no of messages to refresh as they come in.
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<script type="text/javascript">
function validform(){
var x=document.forms["form3"]["name"].value;
var y=document.forms["form3"]["f_name"].value;
[Code].....
i m trying to call multiple function when submit is pressed.i have tried wrapping the functions as well as onsubmit="return validateForm() && checkdate(mydate)"my 1st function is validating if all the columns in the form are filled or not AND.my 2nd function is validating date text box in my form....i m not able to call multiple functions onsubmit [code]
View 1 Replies View RelatedI am trying to get a form to call a javascript function on submit to send an ajax request. The site sits on one server and the php target file on another. I get a status of 0. From what I read, this is because the php file sits on a different server. I do don't believe I can get around the files sitting on different servers.I can set the php file as the form action, but I do not want to redirect, just send a request to the other server to modify some values in a DB. If I can not send an ajax request between servers, I was thinking an alternative might be to set the php file as the form action, run the updates, and then have the page redirect me back. Is there a better way to get around this problem
View 1 Replies View Relatedhow I can make each radio button call a different page. For example If i click on radio button 1 and click submit it will take me to [url].... and if I click radio button 2 and click submit .
View 7 Replies View RelatedI am trying to call an external ajax function to exec the php script to update a table. It is somehow not working.
<html>
<head>
<script>myAjaxFunctions.js</script>
</head>
<body>
<button type="button" onclick="clearT1();">Clear TableOne</button>
</body>
</html>
/**** This is "myAjaxFunction.js *****/
var asyncRequest;
function getContent(url){
try{
asyncRequest = new XMLHttpRequest();
asyncRequest.onreadystatechange = stateChange;
asyncRequest.open('POST', url, true);
asyncRequest.send(null);
} .....
When I click on a submit button it should take me to get.php but it doesn't whats wrong?
<form enctype='multipart/form-data' action='' method='POST' name='form'>
<div id=$counter><input type='submit' name='webpage' value='Add Webpage' onClick='return changeAction1(this);' /></div>
</form>
<script type="text/javascript">
function changeAction1(form){
form.action = "get.php"
}function changeAction2(form){
form.action = "insert9x.php"
}function changeAction3(form){
form.action = "insert8x.php"
}
</script>
i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)am using php as server scripting ..and i wrote ..in php
PHP Code:
<form action="del_cat.php" name="myform" method="post"> [code]....
my problem is if i click "OK" or "Cancel" both case the form is automatically submitting ..see ...i used
PHP Code:
if (isset($_POST['delete'])) [code].....this code to invoke the function ..
The following (likely far from imperfect code), reports a value of NaN
in the j4 display. I suppose the problem is I am not really passing
the "checked" value of the radio button via .value ... without having
to get this value via html, is there any way I can passed the checked
value via html .. maybe with syntax like n4.checked.value or
something.. Code:
I have some problem while while working on a script..i want to use confirmation() function to confirm submit button and if its true ...then submit form... else keep on same page (thats logic)
Am using php as server scripting..and i wrote..in php
And used a javascript in head
My problem is if i click "OK" or "Cancel" both case the form is automatically submitting ...
See i used:
This code to invoke the function ..
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1. What is the benifit of having the above code with "window.onload" and "for loop" and loop through the forms if I only have ONE form in html?
2. What is this line of code "document.forms[i].onsubmit" saying? Does it mean "Execute function() when submit button within form[i] has been pressed?"
3. function() - Does this empty function mean "run every following function below"??
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
<button onClick="return popup('<span onClick='selectShape(1, 1, 1)'>test<span>');" tabindex=Ɖ' onFocus="setFocusColor(0,3)">....</button>
This will work perfectly, but as soon as I need to pass Strings inside the selectShape function, I get stuck.
So the question is, how can I create the following and have it working
......selectShape(2, 'Tricky', ཤx5°').....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
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I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have this as my Dialog Javascript
$( "#dialog-form<?php echo $diagnumber; ?>" ).dialog({
autoOpen: false,
height: 300,
[code]....
I copied codes on internet and arranged them according to my knowledge of JQuery (which is very shallow).. The code works fine sometimes.... but not all the time. Can anyone help me to find out why the dialog box does not appear everytime I put wrong username and password?
Here is the JQuerycode:
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Because I am using ui-darkness as the page theme, so at form tag, I don't have defaultbutton="but_submit" tag. If I add it back, I will get error while compiling..
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
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when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
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Does the "submit" button always submit form data in non-ajax way?What are the best practices for submitting forms using xhr?
View 1 Replies View RelatedI'm wanting a table cell click event to remove and replace the table it was clicked on, however I'm finding that as it's deleting the original table object the actual running event code is being replaced and the function is bailing.how I can call the delete/refresh function from outside the event's function scope?
View 1 Replies View Related