One more thing, how would I do it so it enables the submit button once the message is Avaliable username.I have this code:
<script type="text/javascript">
//function to create ajax object
function pullAjax(){
[code]....
I set it as display none as a default and then when the box is green for the box to show as a block.Its not showing up tho after the box becomes green
Is there a way I can display the submit button only when or if the count = 200?
View 9 Replies View RelatedI would like my form submit button to show as a link instead of a button, where it will be a link and pass the city value to the action page.
View 3 Replies View Relatedhave added a javascript button to my website that allows me to submit information with out refreshing the page, this works perfectly in Mozilla, however in IE the button doesn't display and in the bottom right hand corner of the browser is the little yellow triangle with the word done with errors.
HTML Code:
<form action="javascript:insert()" method="post">
<div align="center">
<input type="hidden" name="usern" id="usern" value="stn003">
[code]....
I'd like to create a quick and dirty validation method for a form. It's not meant to be very secure.
The way I picture it working is this - there is an input field that asks for a password. If the user types in the password correctly, the "submit" div tag will change from "none" to "block". , which will display the submit button. I just am not familiar with JS enough to know if that's possible.
Here's what I'm starting with:
Code:
I have an odd problem I can't seem to find a solution for. I have two ValidationTextBox elements in a form, username and password. In the onBlur() function of username I call the validator function. Here I make an ajax call to the server to verify that the username is not already registered. If it is then focus is set back to the username field. That all works great. My problem is that when the user clicks on the password field (or tabs) the validator() function for that field is called and displays the tooltip for saying "password can not be empty" and the tooltip for username stating that the username is already taken is not shown.
how to show the username tooltip instead of the password tooltip? I have tried calling an empty displayMessage("") on the password field and this does not work. It is rather annoying because the user does not know why the username field is invalid. Visually it is obvious that the field is invalid but it doesn't state anywhere that the username is already used.
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have this as my Dialog Javascript
$( "#dialog-form<?php echo $diagnumber; ?>" ).dialog({
autoOpen: false,
height: 300,
[code]....
I copied codes on internet and arranged them according to my knowledge of JQuery (which is very shallow).. The code works fine sometimes.... but not all the time. Can anyone help me to find out why the dialog box does not appear everytime I put wrong username and password?
Here is the JQuerycode:
[Code]...
Because I am using ui-darkness as the page theme, so at form tag, I don't have defaultbutton="but_submit" tag. If I add it back, I will get error while compiling..
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
[Code]...
Does the "submit" button always submit form data in non-ajax way?What are the best practices for submitting forms using xhr?
View 1 Replies View RelatedI am trying to hide/show table when hide/show button is pressed
Problem: The code works fine when I remove 'slow' from line 10. But with 'slow' in line 10 content of toggleButton doesnt change from Hide to Show when pressed.
Code:
I have a website containing 26 subdirectories 'a' to 'z'
On the home page I want a text field and submit button
If someone for example types 'j' it will go to the 'j' folder home page
Does anyone know where I might find code like this?
I am a PHP programmer and new to Javascript and jQuery and I have tried about 20 examples/tutorials and cannot seem to get even close to what I want.I have a form (PHP/MySQL) with a list of subjects I got from my database, and then create a set of radio buttons from that list. And based on what radio button they select, I need to pass that variable to a div (at least that's what I want to use) and then show a list of videos that match the radio buttons value. I don't care if its a get or post or other.I tried to use GET or POST so I can use that value for my PHP/MySQL lists.I am open to any suggestions/tutorials, etc.
View 1 Replies View RelatedI have a welcome page, where there is a text field and submit button.The user types in their name and press submit which will open up a window to Page 1 and so on.
Now whenever it opens up pages, it will use the name that was inputted on the welcome page.
eg.
Page 1 = Hello, <inputted name>, how are you today.
Page 2 = So, <inputted name>, what are your plans for today?
Page 3 = <inputted name>, would you like to go to the movies?
I'm trying to do the standard show/hide DIV, but the system I'm trying to use it in is basically this: My site has an application form submit area, and I've got a page where I can view a table with all applicants' details. One of the table fields is just a link to "view full message" (which is a text area field from the form), what I want to do is have this link display in a DIV elsewhere on the page. It needs to change according to which table row is selected.
View 2 Replies View RelatedOn the server side, I'm using a web framework that use submit button "name" attribute to decide which action to perform. On the client side, I have an script that submit forms in Ajax with the "serialize()" functions.
But as the JQuery documentation said, the serialize() function don't send the submit buttons names. I have tried to get the event.target object but this object is the form itself. So, I wonder to know if he is a way to discover obtains the name of the button that has triggered the form submission.
How To show Div After Click (tell friend) link and hide div after onsubmit form ? (Using Jquery or java script)
Example :
TELL FRIENDS CLICK LINK
<div id="formhide"></div> (default is hidden).
After Click Show Loading Message and show form for send data to any email . so if Form is valid Show loading message and message Success ! so hide dive ( to default).
How can I disable a submit button for a form if JS is disabled. In other
words, JS must be enabled to submit the form.
