Can somebody tell me why my mouseover submit button isn't working? I've looked it oever several times and I don't see anything thats wrong. When I go to mouseover the button, it comes up with the error: "Description Object Expected". Here is the script that pertains to the rollover function: Code:
View 3 RepliesI dont know much about javascript but I am trying to get a little mouseover for a submit button to work.
<input name="Submit" type="image" id="submit" src="images/button-send.gif" alt="Send Email" />
<a href="#" onMouseOver="document.Submit.src='images/button-send-over.gif'" onMouseOut="document.Submit.src='images/button-send.gif'"></a>
am I even close?
On my form I have 3 submit buttons which handle different things.I am looking for a way to stop or continue form execution with a confirm box on the third submit button and the third only.I can't use onsubmit because that will trigger on all three buttons.
View 2 Replies View RelatedIn the following .submit function, I am attempting to grab the value of the selected option in the facilityCodes dropdown list when I click the submit button and then during the submit function,select the facilityCode again in the dropdown list when the page reloads and then disable the list so that the user cannot change it.However,the situation is when I reload the page after the submit button is clicked the dropdown defaults to the first option and the list is enabled.I apparently am not understanding how.submit works so that I'm selecting the option I'm defining in my code below and then disabling the list AFTER the page reloads due to an error on the page. My question is how can I accomplish this?Here is my code:
$(function() {
$("#ARTransferForm").submit(function() {
var msgsCount = 0;[code]....
The following will submit the form data to popup by clicking the submit button. I want it will submit the form automatically to the popup, there is no submit button in this page. Basically this page should not show up.
<script type="text/javascript">
function submitmyform(f) {
f.target = 'foo'
window.open('',f.target,'menubar=no,scrollbars=no, width=800,height=800');
f.submit();
return false;
}
</script>
<form name="myform" action="popup.asp" target="_blank" method="post"
onsubmit="return submitmyform(this);">
<input type="hidden" name="item" value="item"/>
<input type="submit" value="submit to popup"/>
</form>
I'm using mailchimps signup box (they don't have a decent forum to ask on) on my website and want to adjust the submit button and change it to a normal link. Here's the button that submit's the form:
[Code]...
I have a page with many forms that I need to change from a post to an ajax call. That part is working, no problem, but now I want to disable the submit button while it's waiting on the server response and then re-enable it when the response comes back.
Here's what I have:
$(function() {
$('form').each(function() {
$(this).submit(function(){
[code]...
I can't figure out what my selector should be to get the submit button of the form that's being submitted. What should I be using instead? Also, if the call errors out, I'd like to just post the form as usual.
I have a form without a submit button. It gets submitted programmatically with document.form.submit().
What I need is to be able to disable this form's submit capability on page load and then reenable it at some later point. Remember there is no 'input' button element.
Code:
What I've tried so far is like this:
savedSubmit = document.inputs.submit;
document.inputs.submit = None;
then later:
document.inputs.submit = savedSubmit;
but this does not work. How can I do this?
I've got a pretty basic form that i need to be able to "submit" by simply loading it in the browser address, not click the submit button. is there a way to do this? Here is the code:
<form name="newform" action="/dir/submition.cfm?z=1&Myid=1" method="post">
<input type="hidden" name="userID" value="27566">
<input type="submit" value="Submit">
</form>
if i load just http://www.mysite.com/dir/submition.cfm?z=1&Myid=1, it doesnt do anything because it doesnt have the userID variable, but im not sure how to include that into the address...
I have this as my Dialog Javascript
$( "#dialog-form<?php echo $diagnumber; ?>" ).dialog({
autoOpen: false,
height: 300,
[code]....
I want to know using Java Sript, how can I get sub buttons when I mouseover a button, for example, in daniweb.com, when I mouseover Web Development button, then it expands and shows PHP, ASP.NET, Cold Fusion, ASP, JSP and so on.. How I can make this type of button like Web Development using Java Script.
View 3 Replies View RelatedI have this button:
<input type="image" src="pause.png" onmouseover="src='pauseon.png'" onmouseout="src='pause.png'" onclick="togglePause()" id="pauseBtn"/>
which changes from the play image to the pause image when clicked, using this function:
[code]....
I copied codes on internet and arranged them according to my knowledge of JQuery (which is very shallow).. The code works fine sometimes.... but not all the time. Can anyone help me to find out why the dialog box does not appear everytime I put wrong username and password?
Here is the JQuerycode:
[Code]...
Because I am using ui-darkness as the page theme, so at form tag, I don't have defaultbutton="but_submit" tag. If I add it back, I will get error while compiling..
I have a form where i use normal buttons with javascript so i can have multiple actions and I don't use a submit button. I can submit the form fine using document.adminform.submit(); but i have an onsubmit="return submitForm"; attached to my <form> tag.
If i had a submit button, it would call the javascript function, but seeing as i don't have a submit button, how can i call that function. here is the bits causing problems
PHP Code:
<form name="adminform" id="adminform" method="post" action="<?php echo $_SERVER['REQUEST_URI']; ?>" onsubmit="return submitForm();">
<p><input type="button" class="back" id="backbutton" title="go back" onclick="performAction('back');" />
<input type="button" class="save" id="savebutton" title="save" onclick="performAction('save');" /></p>
[Code]...
when the save button is clicked, a javascript function is called which does the ocument.adminform.submit(); but i need to do call the submitForm() function at the same time
Below is the code for a Captive Portal Splash Page. I have tried to research how to fix the button at the bottom of my page but I can either add a link (which does not require checking the box to agree to terms) or simply how it came to me without the ability to send customer anywhere.
[Code]...
We have a bit of a baffler as to why the Close X is not visible when using the Thickbox module.
Here's a live example of what I mean. Go to: [url]
Click on the Size Chart link next to the product's options. The popup comes up fine but unless the visitor is psychic they wouldn't know they have to mouseover the top right corner of the popup window to get the X for closing to display. The obvious problem is that the customers panic and close their entire browser after saying a few curse words.
We can't figure out why the X isn't displaying properly (basically not displaying at all).
Any code to create a function and form to make the position of a button change dynamically based on a mouseover event? Whereby a viewer's cursor will chase the button around an IE page for infinity! I would prefer to do this without the need for any plugins if at all possible, and it does not need to be cross-platform, just IE is fine.
View 1 Replies View RelatedI've been looking for a solution to a dropdown menu problem where the button does not stay hovered when the list is navigated/as soon as the cursor leaves the button area. At the moment the effect is setup using css sprites (locally) but I have seperate images also for the 2 states.
[Code]...
Does the "submit" button always submit form data in non-ajax way?What are the best practices for submitting forms using xhr?
View 1 Replies View RelatedI'm used to building objects in Visual Basic and I'm having difficulty simplifying this code into an object so I can just define and run about a dozen of them.
The code creates a button which changes on mouseover and on mouseclick. The button is a link to another page.
Also on mouseover the button slides to the right, giving a more intelligent feel for the user.
What are my options for streamlining this code so I can reduce the number of lines of code-clutter?
The code below is formatted properly.
PHP Code:
I have a website containing 26 subdirectories 'a' to 'z'
On the home page I want a text field and submit button
If someone for example types 'j' it will go to the 'j' folder home page
Does anyone know where I might find code like this?
On the server side, I'm using a web framework that use submit button "name" attribute to decide which action to perform. On the client side, I have an script that submit forms in Ajax with the "serialize()" functions.
But as the JQuery documentation said, the serialize() function don't send the submit buttons names. I have tried to get the event.target object but this object is the form itself. So, I wonder to know if he is a way to discover obtains the name of the button that has triggered the form submission.
How can I disable a submit button for a form if JS is disabled. In other
words, JS must be enabled to submit the form.
how to create a drop down menu without the need of a submit button? Once user Choose his stuffs, it will auto submit the results without clicking submit?
View 4 Replies View RelatedHow do I get the value of a submit button put into a global variable onclick?
<input type="submit" value="2">
How would I get the value of "2" to say a variable named subVal?
I'd like to pass the "levelbtn" value when I click the filter
button, but there are also other submit form buttons.
I defined as "document.testform.submit();" in the javascript, but I
don't think it is right.....