But when there are multiple classes, it only deletes the first element in its query. As a successful test, I appended some CSS to ensure the query selected all classes and added a border to each element. So why does remove() not work? Is it a bug or is my query missing something?
I have a page I am working and I am having some trouble with: I need to show and hide areas based on a radio selection. I initally started using the show / hide feature in Jquery but the problem is the elements need to be removed but then put back if the user selects the radio buttonagain as it has form elements that have validaion on them. The validation is still trying to validate the form elements becuase they are still on the page but just not showing. This is the radio group the user makes the selection from:
I am using jquery with the cookie plugin and I have multiple image buttons that can hide/show multiple elements. My question is how can I add a cookie to this code to remember whether each separate element is opened or closed?
The code, $(document).ready(function() { // choose text for the show/hide link - can contain HTML (e.g. an image) var showText='<div class="expanddown"></div>'; var hideText='<div class="expandup"></div>'; // initialise the visibility check var is_visible = false; // append show/hide links to the element directly preceding the element with a class of "toggle" $('.toggle').prev().append('<a href="#" class="togglelink">'+hideText+'</a>'); // capture clicks on the toggle links $('a.togglelink').click(function() { // switch visibility is_visible = !is_visible; // change the link depending on whether the element is shown or hidden $(this).html( (!is_visible) ? hideText : showText); // toggle the display - uncomment the next line for a basic "accordion" style //$('.toggle').hide();$('a.toggleLink').html(showText); $(this).parent().next('.toggle').slideToggle('fast'); // return false so any link destination is not followed return false; }); }); HTML, <a class="togglelink" href="#"></a> <div class="toggle"> Content </div>
I'm trying to allow users to add the text from a text input into a list, and then have the option of removing this list item. So far I have the code below which allows me to add a styled list item with a link in it which I would like to close the box when clicked but at the moment when I click it nothing is happening. I'm not sure if I'm approaching it correctly or if there is an error in my code.
jQuery(function(){ $('#addTask').click(function() { var Task = $("#jobTasks").val(); if (Task == '') {
I appended elements inside this div. But I want it where if a check box is checked then that element which is an a tag html element that will be removed.
The problem... when lets say append 3 <a> tag elements. when I remove all 3. Then append like 4.. I see like gaps. like I want it where if I delete the element it will float upwards. what that means that if I got 3 elements and I delete all 3 and then append 1 new one... then that new one should be shown at the top of the div. Not displayed a little bit lower then where the 3rd element we removed was located at.
It seems like that html code that is appended still stays there for some reason.
I am trying to insert and remove form element dynamically. What I was doing was some sort of recipe program where a user can prefer to add for elements as he/she is done inputting a recipe. He/She can also remove the ingredient if he/she opts to. Here is the link: [URL]
I already solved the problem but I am not sure if what I did is an efficient one. The thing I did was clone the first child of the form. But I realized that if I would put text inside the first child of the for, the duplicate field will also contain the same text as the first child which I don't want to happen. This is why, I set the display of the first child of the form as none. I am not sure if this would cause some problem when I would submit the whole form so that the inputs will be saved in the database since the first child is empty. I was thinking that as the form will be submitted, I would just remove the first child.
I have a few input button classes all with the same class. When a user clicks on the input button, then I disable the input button so the user does not click on it again. I want to make it so when the user goes back, all of the buttons of the same class are active again(including the one that the user just clicked on).
When the user select an option in a dropdownlist, new dropdownlist elements are added dynamically using jquery. When a user clicks on a new option i the first dropdown, I want all the dynamically added events to be removed so that I can render new ones. But it seems the dynamically added events haven't been added to the DOM, so they cannot be removed. Is it possible to remove them? In that case, how? I've read a lot about .Live(), but my problem is not regarding an event - I just need to reach an element(?).
I've run into a problem on a particular project, and it seems to be browser specific. [code]...
Now, this works all fine and dandy in Firefox and Safari, but in the IE's, it will switch properly, but if you switch while in the middle of a movie playing and then switch back to it, the video is paused at the spot where the switch happened and will not play again. That does not happen in Firefox or Safari. Your thoughts? Is this just a cache thing with IE that can't be worked around?
So I have a table with rows and basically I cloned it and then appended it underneath another table. The user can click on the plus button to clone the table (which on the UI looks just like a row of fields) over and over. Next to the plus button I have a minus button that I want to use to remove the cloned table. Here's my code for the add table button:
Basically what I need to do is write functionality for the remove button that when clicked removes the bottom most table. Is there functionality in jquery where you can say "find last occurrence of 'addrow' and remove it onclick"? [code]...
I'm a newbie to jQuery and I'm facing a "big" problem for my actual knowledge.. code...
If I run the code and click on "Delete" what I can obtain is only a partial remove of fields (the "Label4" and "Label5" still remains on the screen, all the others are removed)... but what I really need is a complete remove all of the "two" rows... I did many search on the forum but I wasn't able to find an answer .
In the following script all works fine except the "Remove all items".It adds and removes individual elements fine, but when I call the dropElems() function it removes up to the last 2. If I click it again, it removes only one.Finally, pressing one more time does remove all.I'm calling the same function to remove one element multiple times to remove all the elements, but it seems to stop short of the actual desired action.[code]
I have an entry form where a length needs to me entered. It can either be entered in meters (one input field) or feet and inches (two input fields).
I'd like to have the user select which units he wants to specify (with a selection tool) and then the form would automatically either display one text box or two.
Exactly how would one go about removing all except one of the above LI elements? Also each page refresh the left over LI element must be a randomly left over element. The last part is the one I am getting stuck on... how to make sure the left over LI element is random each time.
I have a page with three identical listbox containing items in the same order. When an element is selected from any of the three lists, the script should search for the occurrence of the same element in other two lists and remove them on the fly from all the three lists.
The following code adds an element to a page when a new address is inputted. Is there a way to remove all added elements with a Clear All button? I have a "Clear All" button with id="ClearAddresses" but I don't know how to remove all created elements - the code here only removes one at a time, since the element is created when the "Search" button is clicked.
var Dom = { get: function(el){ if (typeof el === 'string') return document.getElementById(el); else return el; }, add: function(el, dest){ var el = this.get(el); var dest = this.get(dest); dest.appendChild(el); }, ..... setTimeout("add_visited_address();", 50); }
when i click a "CREATE" button a row should be created which contains 5 columns. In first column check box, second column textbox, third column textarea, fourth column radio button, fifth column a button with "DELETE" as value, which on click should delete the created row.
the number of times i click "create" button that many rows has to be created.their names also should be generated dynamically.
I've selected multiple tables and tried to use each for applying cornering to each table. Inside the callback function, I try to find the first/last table cells to apply cornering for each corner. However, when there are multiple tables it looks at _all_ the tr elements for the first/last rows. See example code:
// Add cornering to tables $('table.corner-me').addClass('ui-corner-all').each(function(){ var $table = $(this); $table.find('tr:first :first-child').addClass('ui-corner-tl');
Can someone explain to me the best way to loop through the geocode and marker (google maps) part of this code for all of the elements with the "address" class using jQuery (or javascript if need be). I tried wrapping the contents of the codeAddress function in $(".address").each(function () {... and replacing the getElementById with a jquery selector, but I still seem to be lost.
I just started using jquery a few days ago and am already addicted.Now I am trying to figure out one thing which I can't seem to get answered by Google:I am building a dynamic website where at one place there will be an unclear number of div-elements. So there can be none, just one or several.The plan is to show them by a click on a button via slideDown(). So I wrapped them with another div.wrapper via wrapAll(). This works nicely for any number.Now the thing is: if my .wrapper has no specified height, the slideDown jumps - which doesn't look very nice.So I gave it a height:$('.wrapper').css({'height': $('div').outerHeight()});Presto, the animation works smoothly. But this works only if there's just one div.
