I am trying to remove attribute from multiple by single change but unable to do so. I am trying to do something like that
function(){
$('#city').change(function(){
if($('option:selected', this).val() === 'None'){
$('#school').attr('disabled' , true);
[Code].....
I have two input box contains name and dob. I have made dob read only and I am inputing date through a javascript calender. Now I have configerd my form if two input have any value then submit button will be enable else not. [code]But my problem is due to i am using javascriptto input dob the submit button is not enabling. I have tried also by.change But still i stucked at the same place.
View 1 Replies View RelatedIs there a jQuery way for me to retrieve the placeholder attribute of a form input element? I've tried the obvious:
alert
(
$
(
[Code]....
but it returns undefined in both firefox and chrome for some reason! All other attributes are displayed fine with the above code... is this a bug in jQuery? using the latest version. Is there a workaround?
How can I remove all <div foo="whatver"...> div elements using the attribute foo for my selector? Basically any div with a foo attribute I want gone.
View 2 Replies View RelatedFor the HTML I have
<span id="one">Vestibulum </span> <span id="two">tortor</span> <span id="three">quam,</span>
for the JS I have
$("button").toggle(
function () {
$("span").removeClass("big");
[Code].....
this cycles through and does what i need, however i have like 100 span tags ... is there a way to do this without having to identify every span ID ?
I have a few input button classes all with the same class. When a user clicks on the input button, then I disable the input button so the user does not click on it again. I want to make it so when the user goes back, all of the buttons of the same class are active again(including the one that the user just clicked on).
View 3 Replies View RelatedI have a form with some select option like
<select name="chart" id="chart">
<option>Google Chart</option>
<option>Flash Chart</option>
</select>
[Code]...
Now I am having problem the remove attributes are written on base of .change if I load the cookie at first then typeo option's disable attribute not getting removed. how can I use remove disable attributes and load cookies?
I need xml data to be used in javascript.
When I embed the whole xml in html page then I am able to access xml. But when when I use src tag I am unable to get xml file. code...
Can anyone please tell me why I am not able to get xml file by using src attribute in XML data island.
I have developed one project and in that i have taken two css now i want to add jquery effects in that, But my display is not properely adjusted and extra enlargement is done so how i can add jquery in my php project without affecting another effect? And one more thing where i can get the jquery effect codes?
View 1 Replies View RelatedCan someone tell me how to remove an attribute from an element that is dynamically assigned using Javascript? (such as a CSS class)
View 2 Replies View RelatedI'm having problems removing the event listeners, they dont seem to be removed
(I am currently only checking for non-ie browsers) code...
Way I can get at a single class when many are defined? [code]...
The script above doesn't work because the class has multiple definitions i.e.
class="tags current"
Is there a way to easily find a single class out of many?
I have one aplication that generate the html code of the pages and i can't change the attributes, but i can add some code.I would like to have a javascript or something like this that will remove or change the attribute height and width in the images.The images have a size defined and i nedd to increase the size of the images.I have searched and tried some scripts but with no success. I think i must have one javascript that run in the end of the load of the page.
View 6 Replies View RelatedI've been unsuccessfully trying to get the datepicker to work on multiple instances on the same form.
Head:
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
[code]....
I need to get the clicked on field plus another field in the current row of a table....
$(function() {
$(".trclick").live("click", function() {
$("#flightno").val($(this).text()); //.children("a").text());
[code]....
The class of a column in the table is assigned the class - trclick. I need to get the value of $fnum when the $rev field is clicked. How can I get the value of $fnum when $rev is clicked?
My site's working perfectly in the other browsers, and when I delete line 28 (see below) it works in IE but not exactly how I want. Is there a way to retain two jquery references on a single page in IE?
This is the head section of my code:
I have an image that I want to animate several properties, starting at the same time but ending at different times.
I want opacity to go from 0 to 1 in 2 seconds, and dimensions to grow in 10 seconds. Both animations should start at the same time.
I'm calling animate twice, but the second animation waits for the first one to complete.
Is there a way to get around this without having to code my own animate function?
$(document).ready(function(){
Here is the application for this javascript.
When the.slide-button-one(top 'Profile', 'Clients' or 'Contact' links) is clicked,#main-content-portfolio (white-background div) slides down and the display is set to none. This reveals#main-content-info (grey-background div).
Currently however, the display value of #main-content-portfolio is set to none BEFORE the slide. How can I switch this order of events?
scrolling multiple DIVs using a single controller. This is what I need done. I have 4 DIVs, ie. A, B, C & D. View the attached sample screenshot or click here to view it on the internet. I need both horizontal and vertical scrollbars that will move selected DIVs when scrolled.
Horizontal = DIVs A, C and D
Vertical = DIVs B and C
I am getting to know jquery a little, and I am trying hide and show a div when a link is clicked.I have a page setup that has a flash video in a div on the main page. Then when a link is clicked, a lightbox window opens and plays another video. I am trying to get the video on the main page to hide while the lightbox video is playing. Then when a user closes the lightbox window, the div with the main video on the page is shown and starts playing again.So far I can get this to work with one link. But I cannot get the main video div to hide when a second link is clicked.
View 1 Replies View RelatedI am working on single form divided into multiple pages using <div id="">. I am using next and previous buttons <input type="button"> to navigate between these pages but I am unable to validate each page before moving to next page using next button.
I am displaying next page form by using "element.style.display = 'none' & element.style.display = 'block' " method.
How to with validation on the current page before moving to next page.
I am adding my code below:
It doesn't appear to be possible to validate multiple forms on a pages that only has a single <form> tag, using the JQuery Validation Plugin offered by Jörn Zaefferer. The reason I need to do this is because my pages are created with ASP.NET whose architecture generally calls for a single page-wide <form> tag. In my designs, I'd like to submit my data using a custom ajax call to a web-method, and link it to a click event on a button.
Below is an example:
<!
DOCTYPE
html
PUBLIC
"-//W3C//DTDXHTML1.0Transitional//EN" "[URL]" >
<
html
xmlns
=
"[URL]"
> .....
I'm not sure that I fully understand the documentation for the Validation plugin, but it doesn't seem like this is possible, as the plugin seems to need a <form> for each form.
I've many dynamic form on my current project. One if them have a two radio button, acting a little bit like tabs. If you select the first radio, the end of the form change to display the "branche #1", and if you select the second radio button, the end of the form change to display the "branche #2".
Let recap with dummy code:
And now I will have to make 3 validations:
1) The first one for the common field.
2) The second one, if buyer is selected.
3) The third one, if seller is selected.
So the code should look like:
But is seem that only my common fields get validated. How should I handle that situation ?
Under PHP control, I am loading an <img> tag with one thing or another. I'm trying to work my way towards not changing the actual tag beyond what is already there (don't mess with the HTML).
The HTML is:
Code:
I am switching the image src path to something totally different. A such, I need to have the browser remove the alt and title attributes. I do this by loading the following in the {SRC} placeholder:
Code:
Using FF2.0.0.20, View Generated Output, I see that these attributes are indeed gone. Yet, the browser still shows (definitely) the alt attribute and (probably) the other attributes as well. I have also confirmed this happens with FF4.0.1-Portable.
Code like the below creates almost always more than one and sometimes as many as ELEVEN dialog boxes. This frustrating behavior doesn't seem to be affected at all by whether you choose "OK" or "Cancel".Is this a known issue and if so, is there a workaround?
$(".delete").live('click',function(){
if(confirm('delete stuff?'){
$.post('delete.php',{toDelete:$(this).attr('id')},function(){
[code]....
I have a grid that uses RowAltRow as the classes for the rows...is there a way to have the hover applied to both instead of having to define it twice (or more)?
[Code]...