I originally thought I should always include js which shouldn't be parsed until the html had been written using the following:
$(document).ready(function () {
//My code
});
I later read that I shouldn't do this (JQuery Cookbook, or something similar) but instead should just include my JS at the very end of the page but before the body close tag.
This page: [url] is linked to 1.js which has this code:
When the page is first loaded, it triggers the alert. It doesn't seem like it would because it is in the livequery function. Why does it do that?
I'm using the Google AJAX APIs, but some reason google.load works when run through normal javascript, but if I call the method from my jquery ready function it doesn't work. Code and output is below
page.html
<script type="text/javascript">
loadGoogleStuff();
function loaded() {
console.debug("in loaded function");
}
[Code]...
window.loadFirebugConsole is not a function If I comment out line 3 in code.js, the console debug runs okay, so the ready function is running okay. Even though there's a reference to Firebug, the same error occurs in Safari too. Nothing on the page loads.
I have 2 javascript files: 1 containing generic functions for my site used sitewide and another for a particular web page containing just the javascript for that page. The page is also calling the jQuery javascript file.
What I want to do is have a javascript function in my main javascript file which uses features of jQuery such as show, hide etc. and then I want to call this javascript function from the other page specific javascript file.
[Code]...
This does not work and so was wondering if anyone can point me in the right direction as to how to achieve this or something similar.
I understand that ready() will run when DOM is ready:
When will this run?:
just one question.I want to remove the div within ready function. I'm using $("noJS").remove(); script, but it only hides the div (when I check the site's code, that div is still there).
View 3 Replies View RelatedI've built a complex web application that loads content into the main page using .load of php pages. Some of those pages are using datepicker and timepicker. I have these working ok to a point, but there is some troubling behaviour. e.g. sometimes when clicking a date field, the calendar doesn't appear. The timepicker seems to work ok most of the time. Clicking around like a loon on various pages sometimes makes the field work with dates, but other times not.
Sometimes I see the calendar display stays on the page even when new content is loaded. Summary is that the datepicker works perfectly, but then it stops working, then starts again.. Now I have a mix of calls to google and local source code .js and ui and tools which is perhaps complicating things. I'm not sure if this is a problem with coding, or the doc ready function being used in 'child' pages.
I am needing to use both functions, as shown below, which are within the <head> section of my code. However, I find that if I do both, neither works. If I do only one, it works.Apparently, I don't know how to properly use $(document).ready(function(). What should I do?
<script type="text/javascript" charset="utf-8">
$(document).ready(function()
{$("button").click(function(){ $("p.hide").hide(); });
[code]....
I can't remember where I read it, but I thought that doing$( function(){
//code here
});
Would make the code execute on page load?However, it seems that the above function only fires if I also include
$(document).ready(function(){
//code here
});
[code]....
I have a function within the
$(document).ready(function() {
function myFunction(){
}
));
But I want to call it from Flash? What name should I use? jQuery.myFunction does not seem to work..
I am getting $document.ready(function() not defined in the firebug console. I have seen that in most cases this is caused when the jQuery core is missing or the path is invalid. I do not believe this is the problem in my case becuase firebug shows the code as being loaded successfully and it is readable.
I have the following scripts in my head;
<script type="text/javascript" src="jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="jquery.validate.js"></script>
<script type="text/javascript">
jQuery.validator.addMethod(
"selectNone",
function(value, element) {
if (element.value == "none") {
return false;
}}, .....
I imported *.js file:
<Script src="Scripts/jquery-1.7.1.min.js" type="text/javascript"></script>
and wrote jqurey function :
$(document).ready(
function() {
checkStatus();
[code]....
I want to modify a local variable of the ready function set like so:
$(function () {
var modifyme = 0;
...
});
I cant change the code setting the ready function, as I am writing only a greasemonkey userscript. I already tried using the .data("events") method, but it never listed the "ready" event. Any function so I can modify the variable!
This question may be simple, but I don't know how to do it. (I'm getting hava script error) I have 04 master pages and around 100s of ASPX pages. So when I want to work in some conent page where should I use my $(document).ready(function(). I already have used this in Master pages. [code]...
View 3 Replies View RelatedI've got a number of divs with the prefix menu and the suffix where is say 1-10. My code is below. It assigns the click function fine to each, but assigns them all the function based on the last value of the for loop. (It calls the current value, while I want the value from when the code was originally executed to set up the click function). Scratching my head on how to accomplish this.$(function(){
[Code]...
Can we NOT place JQuery ready function in head section ? is it possible ? We put it into html body, and then use some function to scan ..
View 1 Replies View RelatedIs there any way to use delegate function without any event or in document ready event? [code]
View 8 Replies View RelatedI have inherited some code and have sort of been going through a crash course with JS (typically I'm working in C/C++/Java/asm). The person before me used jQuery, which seems to be basically a convenience thing and for the most part I understand the applications they've used it in. However, one thing scares me. The primary JS file is prefaced with:
Code:
And I have no idea what that does. From what I can guess, it probably waits to define the rest of the code until the document has been entirely loaded, but when I wrap it around MY code it just breaks everything.
My change function allows users to switch from country to country and get different text and features. It works when changing country selections. But at initial page load, it does not fire jQuery change to set the text for the default / initial country. When I change away and then back to the default/initial country, change fires and shows the proper information and features. I have tried document.ready with a change function both inside the switch selections and outside the change function. Neither work - they don't fire the hide, show and other jQuery in the switch cases at doc ready. Its not clear to me what function will fire the jQuery change function at doc ready. Here's the code. The country selection below is just 2 countries to keep it simple, but actually, there are many.
$
(
document
)
[Code].....
In my application i am using two jquery scripts .One is for accordian and another one is for drillMenu . Both js files are having "jQuery(document).ready(function($)".
If i use both the js file in my application only one functionality is working. For suppose if menu drill is working then it is not supporting another one.
I can't seem to get the syntax correct to get this to work. I'm sure it is something simple.I want to call multiple functions inside my document.ready function.The first function gets called but not the second.
$(document).ready(
function GetSuspectCollection() {
$.ajax({[code].....
I use the following code to add a "click" behaviour to an element:
$(document).ready(function(){
$("#element_id").click (function(){
...... do something ....
[Code]....
Part of the node I clone is the element from the first piece of code I quoted. The addRowJob function also changed the ID of every element in the node I cloned. This way all IDs remain unique. Lets say the element in question has the ID "#element_id". Now I clone the node (which includes the element) and the cloned element gets its ID changed to "#element_id_new".
Of course I now want this newly append element ("#element_id_new") to have a click event attached to, but even if extend my $(document).ready(function() to:
$(document).ready(function(){
$("#element_id").click (function(){
...... do something ....
});
[Code].....
I simply doesn't work for the appended element.
My guess is that the $(document).ready(function(){ only fires when the document is finished loading. At this stage there is no element with the ID "#element_id_new" and therefore the click event can't be attached to the element. Makes senses...
But how do I get this click event attached to the newly appended element with the ID "#element_id_new"?
Any way to wait until it is fully loaded
<script type="text/javascript">
$(document).ready(function(){
$("#featured > ul").tabs({fx:{opacity: "toggle"}}).tabs("rotate", 4000, true);
});
</script>
I have noticed on a few occasions where I navigate to a page and the document.ready() function gets called and executes. I then push a button on that page which calls a javascript function that does a jquery submit to the same page I am currently on. This time, document.ready() does not get triggered. How do I make this happen the second time, have the stuff I want on page ready be executed? I am using Chrome if that helps.
View 3 Replies View RelatedHow can I get the width of an image when the page is ready...? I tried the code below, but it always return the value '0'...!
[Code]....
I have a few document ready functions on my page. I don't want the functions to get executed if the page is loaded because the user clicks on the browser forward/back button. Is there a way to prevent the document ready functions from getting executed if the user clicks on the forward/back button?
View 2 Replies View Related