JQuery :: Use The -original- Value Of A Variable In Document Ready Function?
Mar 20, 2010
I've got a number of divs with the prefix menu and the suffix where is say 1-10. My code is below. It assigns the click function fine to each, but assigns them all the function based on the last value of the for loop. (It calls the current value, while I want the value from when the code was originally executed to set up the click function). Scratching my head on how to accomplish this.$(function(){
I am needing to use both functions, as shown below, which are within the <head> section of my code. However, I find that if I do both, neither works. If I do only one, it works.Apparently, I don't know how to properly use $(document).ready(function(). What should I do?
I am getting $document.ready(function() not defined in the firebug console. I have seen that in most cases this is caused when the jQuery core is missing or the path is invalid. I do not believe this is the problem in my case becuase firebug shows the code as being loaded successfully and it is readable.
I have the following scripts in my head; <script type="text/javascript" src="jquery-1.4.2.min.js"></script> <script type="text/javascript" src="jquery.validate.js"></script> <script type="text/javascript"> jQuery.validator.addMethod( "selectNone", function(value, element) { if (element.value == "none") { return false; }}, .....
This question may be simple, but I don't know how to do it. (I'm getting hava script error) I have 04 master pages and around 100s of ASPX pages. So when I want to work in some conent page where should I use my $(document).ready(function(). I already have used this in Master pages. [code]...
I have inherited some code and have sort of been going through a crash course with JS (typically I'm working in C/C++/Java/asm). The person before me used jQuery, which seems to be basically a convenience thing and for the most part I understand the applications they've used it in. However, one thing scares me. The primary JS file is prefaced with:
Code:
And I have no idea what that does. From what I can guess, it probably waits to define the rest of the code until the document has been entirely loaded, but when I wrap it around MY code it just breaks everything.
I'm having some problem with return value for a function. I'm trying to access google blogger's API to display blog entries on my site. I'm doing this through JQuery and requesting a JSON response. Everything seems to work ok, but I want to access the link for the blog entry. This is a subset of the "entry" object.
I want to get the link where the "link.rel == "self". To do this I have to loop through the link object (5 times). The loop and conditional statement works correctly, but I can't get the variable inside this loop back to my original function.
I have this code: $.each(data.feed.entry, function(i, entry){ $.each(entry.link, function(j, link){ if(link.rel == "self"){ var postlink = link.href; alert("link : " + postlink); return postlink; }}); alert(postlink); });
My change function allows users to switch from country to country and get different text and features. It works when changing country selections. But at initial page load, it does not fire jQuery change to set the text for the default / initial country. When I change away and then back to the default/initial country, change fires and shows the proper information and features. I have tried document.ready with a change function both inside the switch selections and outside the change function. Neither work - they don't fire the hide, show and other jQuery in the switch cases at doc ready. Its not clear to me what function will fire the jQuery change function at doc ready. Here's the code. The country selection below is just 2 countries to keep it simple, but actually, there are many.
In my application i am using two jquery scripts .One is for accordian and another one is for drillMenu . Both js files are having "jQuery(document).ready(function($)".
If i use both the js file in my application only one functionality is working. For suppose if menu drill is working then it is not supporting another one.
I use the following code to add a "click" behaviour to an element:
$(document).ready(function(){ $("#element_id").click (function(){ ...... do something ....
[Code]....
Part of the node I clone is the element from the first piece of code I quoted. The addRowJob function also changed the ID of every element in the node I cloned. This way all IDs remain unique. Lets say the element in question has the ID "#element_id". Now I clone the node (which includes the element) and the cloned element gets its ID changed to "#element_id_new".
Of course I now want this newly append element ("#element_id_new") to have a click event attached to, but even if extend my $(document).ready(function() to:
$(document).ready(function(){ $("#element_id").click (function(){ ...... do something .... });
[Code].....
I simply doesn't work for the appended element.
My guess is that the $(document).ready(function(){ only fires when the document is finished loading. At this stage there is no element with the ID "#element_id_new" and therefore the click event can't be attached to the element. Makes senses...
But how do I get this click event attached to the newly appended element with the ID "#element_id_new"?
I have a few document ready functions on my page. I don't want the functions to get executed if the page is loaded because the user clicks on the browser forward/back button. Is there a way to prevent the document ready functions from getting executed if the user clicks on the forward/back button?
I want to modify a local variable of the ready function set like so: $(function () { var modifyme = 0; ... }); I cant change the code setting the ready function, as I am writing only a greasemonkey userscript. I already tried using the .data("events") method, but it never listed the "ready" event. Any function so I can modify the variable!
I'm new to jquery. I did some pages in jquery.I'm confuse about the use of $(document).ready. Whether I put my code inside or out of $(document).ready, it works fine. In plain english, how can we describe the use of $(document).ready?
I am trying to use the Multi Drop Down Menu plugin available at CodeNothing.com. However the problem is occuring even without calling the functions in the plugin. (It occurs when I call the functions in the plugin as well but that doesn't matter)I am experiencing some very strange behaviour. I havesome standard nested unordered lists where the top list is given the id multi-ddm. Now when I run the code below I get 1 alert (which is correct as I only have 1 child li element) saying hello.
no error appears and the alert appears once, which is correct.So is it the $(document).ready that is causing the problem or the '> li'. I cannot work it out and have been at it chopping and changing for ages.
I know that to run jQuery when the document is ready, you just use $(function() { ...jquery code... });
but that isn't allways what I want, sometimes I want to one or more jQuery codes when for a example a div (with a class or id) has been created, or when an image has loaded.
i have two pages A & B A shows the intended functionality of the fading images/text on the left, the video image that pops up a jquery tools expose overlay, and the tabs on the bottom left page B is identical in all ways that i think matter. in other words, the javascript and html elements are all the same. the only other difference is that page B is created via a wordpress theme.
There are pages containing input field where in user enters value. Now I have a requirement to block UI untill the document is ready and every input field is rendered. I have found that I can use blockUI plugin for this : [URL] I have also found few good examples in : [URL]
how do I call $.blockUI() on pre-ready stage and call $.unblockUI(); on .ready(). I would want my UI to be locked untill the doc is ready. I can put call to $.unblockUI(); in .ready() but where do I put $.blockUI().
