I've been banging my head against this extremely frustrating bug but I finally managed to get an isolated test case. Call .animate() on two different elements one after the other and give the second one a "complete" callback. In the callback function call .stop() on the first element, the one with no callback.
The callback function should only fire once (when the second element's animation completes) but instead it fires twice. It only occurs when the animations are started in that order and stop() is called inside the callback.[URL]...
how to stop the document.write opening a new window when called in a function, what I want to do is really simple but is defeating at every turn.I have a line of text that is a link on an html page,when clicked i want the the function called to print a name, imediatly after the calling link (on the same page).
So I have a menu animation that I built in flash/actionscript 2.0 and when you click on menu the header pulls down to reveal the menu, then you can click on menu again to push the header back up and hide the menu. I have a <div> below the header that I am trying to "push" down and "pull up" with the menu animation so what I did was in the actionscript button I used
That's the code for "pulling" the menu down, it's pretty much the same for "pushing" it up but calling for "moveUp()" instead of moveDown().So in my html I am using...
<script> function moveUp() { $("#moveme").animate({
[Code].....
the div is labeled as <div id="moveme" style="margin-top: -250px; width: 920px; height: 1000px; overflow: visible;"> if I use a regular javascript function that just moves the div it works, but looks horrible, as soon as I try to animate it it does nothing at all. I have tried using different sytax's likemarginTop: "-325px" and even "margin-top": "+=-325px" but nothing is working, it just will not move.
jquery and a button delete, for remove rows of database.The problem is that I do not know how must input checkbox by clickable with click delete button sent to php code?my jquery code:
It seems stop method is not working for me...I don't know what I am doing wrong, but when I mouseout when the mouseover animation is still running, the mouseout animation does not occur..
Click on any of them, and they open up just fine, however, after this point they dont close, and you also can't open any other one, it just... stays stuck there.
I had this working just fine, and in the process of working with wordpress and templating, obviously I changed something to mess it up.
The problem is that it stop working of Firefox after about two hours. I used it on the main page and leave it working and afterabouttwo hours the picture stop moving and there is only one pictureshown.
I'm brand new to jQuery, so I apologize if this is a 101 question, but I'm trying to sort out a production issue. I do QA for an ecommerce website. When one of our developers made some changes to our application recently, a couple of the plugins we use stopped working on those pages. Looking at the code, it seems we load jQuery 1.4 and several plugins, including autocomplete and popdown. In the changes, for some reason, the developer loads jQuery 1.4.2 (after 1.4 has been called) but doesn't call the plugins again. I'm assuming that this is the reason the plugins stop working. Can anyone confirm this theory?
(The reasons why we don't call 1.4.2 earlier in the document are, sadly, mostly bureaucratic. If I can get this confirmation, hopefully I can push through that.)
We have a problem in our currently built website, in chrome+firefox the website works great but in IE 7+8+9 the javascript stops working after few seconds or after several commands a user do in the website.
I've been working on a freelance design site, and I have been using jshowoff and fancybox on my portfolio page. The portfolio has multiple sections that are set to be scrolled through using jshowoff by using the slide links. This use of jshowoff is working perfectly fine, but fancybox isn't. fancybox is supposed to be set to launch a modal when any of the portfolio thumbnail images are clicked. As it is right now, fancybox links will not work within the jshowoff slide div, but they do work outside of the jshowoff slide div.
I have done about 5 hours of searching online for possible fixed to my issue, and I haven't found anything. I am attempting to fix the conflict the between jshowoff and fancybox. I am very new to using jQuery plugins, so hopefully, you can all bear with me.If anyone may know how I can fix my fancybox links, so that fancybox will work within my jshowoff slide, I'd greatly appreciate it. I have provided the html below:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml">
how to stop the browsers back button from working after a user has logged out. I tried the windows.history.forward(1); function but it either is not working for me, or I am not putting it int the right place.The logout button is on the menu.php page. The button calls the logout.php file which redirects the user to the index.php page after logout.
When the JS file is not working at the time of Ajax files is called. on first time the onmouseover JS is working but , if you call the ajax JS is not working.
I had a beautiful script written by @rnd me that looks like this:
Code: <body> <input id='inp' /> <select id='sug' /> <script type='text/javascript'> function el(tid) {return document.getElementById(tid);} function addScript(u){ var head=document.getElementsByTagName('head')[0], [Code]....
This script made it possible to show Google suggestion while typing in an input field. The Google suggestions are retrieved over here: [URL] The problem is that all of the sudden it stopped working! For apparently no reason because Google is still 'providing' the suggestions online. So I have two questions: Why is it stopped working? Did Google restrict the suggestions to third parties?
The code is working 100%, but the only problem is with the function calling statement. It is working on the first img (picture) i want it to be called on the second picture.
<!DOCTYPE html PUBLIC "-w3cDTD xhtml 1.0 strict EN" <html xmlns=http:www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns = http:www.w3.org/1999/xhtml">
I m trying to make a person stay on same page on cancel, but the confirm takes the user to the next page like they press ok. how can i stop it? code...
I have a function that sends some data to a PHP file for processing, and call a page refresh after that, but it's not working. This is what I have so far:
function Reload() {location.reload() ;} function del(v,m,f){ $.post("system/reject.php", {id: v}) ; javascript:parent.mainFrame.document.location.reload(); }
The function Reload is something else I tried while trying to get it to work but everything I have done so far doesn't work. :(
I want to run a function only if it has been called from lets say another function, is there an event handler for that? I dont want to call the function on document.ready since it will load without being called?
for example, the below function is run when page loads, how do I just run it only when I call it directly, say from another function..
I have a table in which I have 3 columns. On the firs row, last column contain a button "save". On clicking Save, the button saved is changed to a delete button and it has to insert a new row above the row.
It checks all <li> elements and save value of title and block input fields in array of objects ang generate JSON - code and input it into #code element.But when I delete one of the <li> by clicking the link, it becomes invisible for me, but function ParseMenu save it into array whatever/ What can I delete this <li> element from everywhere?